How much power is produced if a voltage of #12 V# is applied to a circuit with a resistance of #24 Omega#?

#P = 6 W#

Explanation:

There are 3 variations of the power formula:

#P = V*I, " "P = I^2*R, " and " P = V^2/R#

If you know any one of them, the others are available thru the use of Ohm"s Law and a bit of algebra.

For this problem, use #P = V^2/R#

#P = (12 V)^2/(24 Omega) = 6 V^2/Omega = 6 W#

I hope this helps,
Steve

#6# watts

Explanation:

Power in this case is given by the equation:

#P=V^2/R#

where:

• #P# is the power in watts

• #V# is the voltage in volts

• #R# is the resistance in ohms

So, we get:

#P=(12 \ "V")^2/(24 \ Omega)#

#=(144 \ "V"^2)/(24 \ Omega)#

#=6 \ "W"#