Complete the following table. Explain in your own words how the charges on ionic compounds are...

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1St part 02- s2- N3- Nat Na F Na20 Na2s Na N Na Br AL3+ ARF Al203 Al2 S3 ALBB AQN CuFa Cuo Cus Cuz N2 CuBr2 2. Balaneed ot eRarges on ionie compounds There is two. methods kor balanced of eharge on ionie Compounds:- O The math way • make the total eharges equal 2ero eharge of Na is +) eharge olrfin- So, Balenee charge 1 x (+1) +1(-1)=0 eg; Na F The eriss eross method Take he eRarge of eaeh and make that number of and simplify ik needed A03t -> 2nd part charge on he anion (seeond element) eharge on Hhe Cation (firnt. element) Balanee eharges Compound +1 Known beeause-2, known because 2) + 1(-2) = 0 Nag s it is sulbide ion s2- in IA group +1 determined in -2, becawse 02- 2* +1 (-2)=0 last eolumn in oxide ion -3, determine as +2 Ynown because in IA group eharge ok Pzx 342)+2(x) - 0 Ca P2 followo -1 becuse ehloride Let efarge of Hgisx +2, determined as Folown Hgc2 iom. I() +2(-1) :o on becanse-1, el- is eRloride kcl 1(+1) + 1C-1) -0 TA group ion -2, beeawse s2- +4, determinedas LeUowa PbS2 Let thange o& Pb=X 1.x +21-2)=0 in sulfide ion w(+4)+2.(-2) = o

Determination ok eharge on each atom heneral proeedure for tinding of ehas ge on each aom- O find no. ob protons (t) 6 Find no. ols electron () [repernent negative no. and eleetrons to Sind eharrge. Add protons e.g:- Ca have 12 Psotons and 1o eleetron, The eharge eharge. no. ak Protont no of electron 12 +(-10) So, ca' fhave 4 2 2.