Question
A steel cable to be used in a suspension bridge (loaded in tension) must support a...
A steel cable to be used in a suspension bridge (loaded in tension) must support a weight equivalent to 1500 kg. If the elastic limit of the steel to use is σy= 1380 MPa, y and the UTS = 1550 MPa, calculate:
a) Minimum diameter of the cable to avoid failure.
b) How this diameter must be modified if a security factor of 2.5 is used.
Answers
I - - 1380 н Pa, ots - sto MP4 load to be supported = 1.800 kg = 1500 x 9.81 N = 14715N al Minm dia to avoid failure At failure point the stress would be Manimum (ie) ultimate tensile strength. i ruts = Load - Area 1550 MPa = 14715 7(d)? . d² 12.087 Td = 3.4.76 mm b) for security factor 2.5 - we take a safety precaution over the failure stress value.Cr.e) Uis. CUTS . safely ISSO - 14715 esser - 14765. Scanned with CamScanne d = 5.497 mm 7
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