Question
Can someone explain how to solve this in detail? A population of water snakes is found...

Answers
Solution for question A:-
Island - Frequncy of banded snakes = 0.16 ie; genotype frequency of banded snakes (q2) = 0.16.
(given-banding is caused by recessive allele)
Therefore q = Squareroot of 0.16
q = 0.4
Mainland - Frequncy of banded snakes = 0.25 ie; genotype frequency of banded snakes (q2) = 0.25.
(given-banding is caused by recessive allele)
Therefore q = Squareroot of 0.25
q = 0.5
Thus frequency for alleles for bands on island and on mainland before migration is 0.4 and 0.5 respectively.
Solution for question B:-
Given Migration rate as 20% ie; 0.2
Now,
Change in recessive allele frequency (qchange)= migration rate * [recessive allele frequency of the migrants (Mainland) - recessive allele frequency of the host (island)]
Therefore qchange = 0.2 * (0.5 - 0.4)
qchange = 0.02.
Now,
Post migration frequency (recessive allele) at island qnew = pre migration frequency (recessive allele) at island + qchange
Therefore, qnew =0.4 + 0.02 = 0.42.
Post migration recessive allele frequency (banding allele) = 0.42