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Construct 90% Confidence Interval

Question

Construct 90% Confidence Interval

Of 43 bank customers depositing a check, 18 received some cash back. Construct a 90% confidence interval for the proportion of all depositors who ask or cash back.Assume all statistical requirements are met.

Please SHOW ALL your work. Thx.

Answers

p^=18/43=.42
q^=1-.42=.58
n=43

90% confidence interval mean z cutoff scores of +1.65/-1.65
p^-z*sqrt(p^q^/n)<p<p^+z*sqrt(p^q^/n)
.42-1.65*sqrt(.42*.58/43)<p<.42+1.65*s…
.42-1.65*sqrt(.0056651)<p<.42+1.65*sqr…
.42-1.65*sqrt(.0752668)<p<.42+1.65*sqr…
.42-.1241902<p<42+.1241902
.295<p<.544

Math- statistics-90 percent confidence interval?
Of 43 bank customers depositing a check, 18 received some cash back. (a) Construct a 90 percent confidence interval for the proportion of all depositorswho ask for cash back. (b) Check the normality assumption.


p^=18/43=.42
q^=1-.42=.58
n=43

90% confidence interval mean z cutoff scores of +1.65/-1.65
p^-z*sqrt(p^q^/n)<p<p^+z*sqrt(p^q^/n)
.42-1.65*sqrt(.42*.58/43)<p<.42+1.65*s…
.42-1.65*sqrt(.0056651)<p<.42+1.65*sqr…
.42-1.65*sqrt(.0752668)<p<.42+1.65*sqr…
.42-.1241902<p<42+.1241902
.295<p<.544

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