Question
Your friend is constructing an balancing display for an art project. She has one rock on...
Your friend is constructing an balancing display for an art project. She has one rock on the left (ms = 2.55 kg) and three on the right (total mass mp = 8.93 kg). The distance from the fulcrum to the center of the pile of rocks is rp = 0.390 m. ... swer the two questions below, using three significan digits. single pile Part A: What is the value of the torque (Tp) produced by the pile of rocks? Number Tp = 0 Nm clockwise (Enter a positive value.) Part B: How far away (rs) should the single rock be located in order for the display to be in equilibrium? Number
Answers
mass of simple rock ims) = 2.55 ug mass of rite of rock (mp) = 8.934g distance from fulcurm to center of the pile of nocks (np) = 0.39om resingle neile a) Tonquect) = Flla fonce) x R{ distance of fulcoum from body) -) t = mg x R (.p = mpg) > 2= (8.93×10 X 0.39 ) = 34.807Hm So, the torique produced by pile of nock is 134.827 km Fon equilibrium, I single mass ) x (distance from fulcrum) = ( pile of mass ) (distance from the fulcrum) - mpx Apice - m xa single 5) 2.55 X risingle = (8.93) X(0.39) - resingle = 3.4827 = 1.365m the distance of the single rock is (1.365m] 2.55
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