Question
This crate has a weight of 200 pounds. The kinetic coefficient between it and the floor...
This crate has a weight of 200 pounds. The kinetic coefficient between it and the floor is 0.45. If a constant force P of 120 pounds is applied as shown, how far will the crate move in 5 seconds, if it is initially at rest? (Give your answer in units of feet) Р
Answers
The crate moves in 5 seconds in 1.875 feet.
Giveno M W = 200 lb P= 120 lb. A) Cena Fm عي 9 M=0.45. t = 5 see isitial velocity ,u=0. (aritially rest) Solution Applying the equations of dynamis. EF=ma 0. IP-Fm = ma Ev=o. NR=W 200 lb limiting friction fm = MNR 0.45 x 200 fm = 90 lb.substitute * is 0. ma 120 - 90 30 lb = 200 lb xa 0.15 f4 /3 =a. using the equation, 8 = ut + Çat? = 0 + 1 x 0,155 8 = 1.875 Ft.
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