Question
дz дz 1. In the equation, x sin y - y cos z + xyz =...
дz дz 1. In the equation, x sin y - y cos z + xyz = 0, z is a function of x and y. Find and ду" дх D- 1) and o- (-11 1)
Answers
O x Shy - y 603 2 +xyz = 0, for aZ = 2 2x d dx е xe bortially differentiate with respect to x (ce song) - (4 Cosz) + (292) = 0 Siny. I (2) - Y Z (cosa) + y 8 (212)=0 Siny. (1) - YC-Sinz) x 22 + y{ x 2 2 2 + 2.0 (x)} = dx + ZP xe Siny + y sinz.az + xy дах ze xe +yz=0 ze {y sinz+xy} + (JZ + Siny) =0 (9z+ Siny) ze da (hxt zursh) Ans.he 23 xsing - y losz + xyz=0 find az Particelly differentiate with respect to y, ay ( z silny) 2 (yol Z) + (XYZ)=0 dy (Sing) – (C052 2 (Y) + y los d P he x 2 sh}x+ ze +z.d he Cos 2)) he gy ge 18;} xlosy- (Cosz – ysinz.az + xy ze he + az 19Xzx he xlosy - Cosz + y sinz. dZ he zu txy ze +xz so he ay {y Sm2 + xy} +(x2+xCosy – Cos 2) = 0 -(XZ +X Cosy - Cosz) ZP he (4 SMZ + xy) Ang
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