Question
Freight trains can produce only relatively small acceleration and decelerations. (a) What is the final velocity...
Freight trains can produce only relatively small acceleration and decelerations. (a) What is the final velocity (in m/s) of a freight train that accelerates at a rate of 0.0700 m/s2 for 8.00 min, starting with an initial velocity of 5.00 m/s? m/s (b) If the train can slow down at a rate of 0.650 m/s², how long (In s) will it take to come to a stop from this velocity? (c) How far (in m) will it travel in each case? m (distance traveled during acceleration) m (distance traveled during deceleration)
Answers
а) V- 4+а= 5 + 0.01% (8x60) = 38.6 m/s V= utat 0 : 38.4 + (- 6.(so) е - 38. 6 - 59: 389 [email protected] 0-60 C) S = ut that? - sx a so +, хоол хvg. lост на s: a +, а 38.6 х (sq. 38s) + (- 6.(s) х (S-38s - 11ч6 (2 м Ang
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