Question
2. 0.5 moles of an ideal gas is initially at T, = 300 K in a...
2. 0.5 moles of an ideal gas is initially at T, = 300 K in a volume Va=0.8 L. This gas has a y value of 9/7. It is taken around the cycle as shown: (1) expanded isothermally to volume Vo = 1.6 L, from a to b. (2) expanded adiabatically to T. = 275 K, from b to c. 0.8L (3) compressed at constant pressure to T, = 235.74 K, from c to d. (4) compressed adiabatically back to the start, from d to a. For each process, calculate the following quantities: (i) the heat absorbed or rejected during each process, (ii) the work done during each process, (iii) the change in internal energy of the system during each process. 1.6L V a. a-b b. b c c. C-d d. da e. What net work is done? f. What is the efficiency of this engine?
Answers
We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this imagee net work done -103.984 -43.75R+ 19.69RT 112.9558 What -15.50SR احیا) effiäency= Heat given (abserbed] - 15:5650S 11 19.69 R + 112.455R1 ! 15.505 132.145 19 0.117 Any 17 E E
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