Question
An unknown gaseous hydrocarbon consists of 85.63% carbon by mass. A 0.100-g sample of the gas...
An unknown gaseous hydrocarbon consists of 85.63% carbon by mass. A 0.100-g sample of the gas occupies a volume of 0.0533 L at STP. What is the identity of the gas? A. C4H8 B. C3H6 C. C2H4 D. C5H10 E. CH2
Answers
% of carbon = 85.63%
% of Hydrogen = 100 - 85.63 = 14.37%
Calculate atomic ratio by dividing % composition by atomic mass.
Mass ratio of carbon = 85.63/12 = 7.13
Mass ratio of hydrogen = 14.37/1 = 14.37
Now calculate simplest ratio by dividing atomic ratio by smallest atomic ratio
Simplest ratio of carbon = 7.13/7.13 = 1
Simplest ratio of hydrogen = 14.37/7.13 = 2.015 = 2
Empirical formula of compound = CH2
According to avogadro's law 1 mole occupy volume 22.414 L
then 0.0533 L = 0.0533/22.414 = 0.002377978 mole
0.002377978 mole = 0.100 gm then 1 mole = 1
0.100 / 0.002377978 =42.05 gm
molar mass of gas = 42.05 gm
Empirical formula mass = (12
1) + (1
2) = 14
n = molecular formula mass / Empirical formula mass = 42.05/14 = 3
Molecular formula = n
Empirical formula = 3
Empirical formula
Molecular formula of compound = C3H6
Answer - B. C3H6
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