Question
A 0.50-μF and a 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a...
A 0.50-μF and a 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a 14-V battery.
1. Calculate the potential difference across each capacitor.
Express your answers using two significant figures separated by a comma.
2. Calculate the charge on each capasitor.
Express your answers using two significant figures separated by a comma.
3. Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.
Express your answers using two significant figures separated by a comma.
4. Calculate the charge on each capasitor assuming the two capacitors are in parallel.
Express your answers using two significant figures separated by a comma.
Answers
1. Let Q- charge on each capacitor(charge is same since they are in series) . So from Q=CV
Q=C1 x V1 ; Q= C2 x V2
0.5 V1= 1.4 V2; V1= 2.8 V2----(A);
Also, V=V1+ V2; 14=V1+ V2-----(B)
Solving (A) and (B)
V1=10.3V , V2=3.7V ; 10.3, 3.7
2.Q=C1V1;
Q= 5.2 x 10-6 C (for both)
3. Since both of them are parallel, voltage across =14 V (for both of them); 14V,14V
4. From Q=CV
Q1= C1x V1=7.0 x 10-6 C
Q2= C2 x V2= 1.96 x 10-5 C= 2 x 10-5 C
7.0 x 10-6 C, 2 x 10-5 C
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