## Question

###### According to a poll of adults about 42% work during their summer vacation. Suppose that this...

**According to a poll of adults about 42% work during their summer vacation. Suppose that this claim about the population proportion is true. Now if we take a sample of 49 adults, and find the sample proportion [^( p)] of adults who work during summer vacation.**

***Please show how you calculated the answers!**

What is the expected value of sample proportion [^(*p*)]? **0.42**

Computer's answer now shown above. You are correct.Your receipt no. is 159-1096 | Previous Tries |

What is the standard deviation of sample proportion [^(*p*)]? **0.0705**

Computer's answer now shown above. You are correct.Your receipt no. is 159-2974 | Previous Tries |

The shape of the sampling distribution of sample proportion [^(*p*)] will be roughly like a

Incorrect student's t distribution

Correct: **normal distribution**

Incorrect uniform distribution

Incorrect Poisson distribution

Incorrect binomial distribution

Computer's answer now shown above. You are correct.Your receipt no. is 159-8316 | Previous Tries |

*P*(0.31 ? [^(*p*)] ? 0.55) = **0.908**

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**Is the sample large enough to compute the above probability?**

Yes, because *n* ? 30

Yes, because *np* ? 10 and *n*(1?*p*) ? 10.

Yes, because the number of successes and failures are both larger than 10.

No, the sample size is not sufficiently large. We actually had to assume normally distributed population.

Yes, because *np* ? 10.

Incorrect. | Tries 2/3 | Previous Tries |

**Find c such that P([^(p)] ? c) = 0.6**

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