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Use boolean algebra to reduce; qm+q!p+q!m+!q!m+!mp

Question

Use boolean algebra to reduce; qm+q!p+q!m+!q!m+!mp

Use boolean algebra to reduce; qm+q!p+q!m+!q!m+!mp

Answers

qm+q!p+q!m+!q!m+!mp =qm+q!m+q!p+q!m+!q!m+!mp = qm+q!m+q!p+(q+!q)!m+!mp = qm+q!m+q!p+(1)!m+!mp = qm+q!m+q!p+!m+!mp = qm+q!m+q!p+!m(1+p) = qm+q!m+q!p+!m(1) = qm+q!m+q!p+!m = q(m+!m)+q!p+!m = q(1)+q!p+!m = q+q!p+!m = q(1+!p)+!m = q(1)+!m = q+!m


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