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How do you find the zeros, real and imaginary, of  y=x^2/3+1/7x-5/9  using the quadratic formula?

Question

How do you find the zeros, real and imaginary, of  y=x^2/3+1/7x-5/9  using the quadratic formula?
How do you find the zeros, real and imaginary, of  y=x^2/3+1/7x-5/9  using the quadratic formula?

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