## Question

###### How to find a sloping edge of a rectangular based pyramid? The rectangular based has length 4.8m and width 3m and the height of the pyramid is 4m .

## Answers

#4.9m# ## Explanation:

Determine the center point of the rectangular base:

#1/2# of#3m=1.5m#

#1/2# of#4.8m=2.4m# The crossing point of the two lines= centre point of the rectangle.

This centre point is also the bottom of the perpendicular height of 4m given.

Draw a line from the corner of the rectangle to the centre of the rectangle.

So: In the horizontal right triangle= adjacent side=1.5m and opposite.side=2.4m

With Pythagoras:

#hypotenuse^2=1.5^2+2.4^2# hypotenuse

#=sqrt(1.5^2+2.4^2)# hypotenuse

#:.=sqrt(8.01# hypotenuse

#:.=2.83m# also adjacent side of vertical right angle triangle with

Opposite side given#=4m# So: In the vertical right triangle the hypotenuse = slope of pyramid

#:.Slope^2=2.83^2+4^2#

#:.Slope^2=24.0089^2#

#:.slope=sqrt(24.0089)#

#:.4.9m# slope of the pyramid