Question
Whats the magnitude of the resultant of the two forces F=400 N y 71° F 490...
Whats the magnitude of the resultant of the two forces
F=400 N
y 71° F 490 N
Answers
To calculate position of resultant use
Tan (theta) = Fy/Fx
Please rate positively
Dale FSinti 71 Ecos.74 LE F=4oon 490 S unnation of all Vertical Forces fy= F Cos71 + ugo Ey = 400 Cos71 +490 Ey = 620.22N Summation of all Horizonatal Fores Exc= F Sin 71 Exc= 4100 Sintl Exx= 378.20 N Pesulatant R = (Foch fyl?Fy R Fox R = 378.2012 +162 2012 +620.22 R=726.435 N
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