Question
.wileyplus.com/euugerynuymanium S Lock, Statistics: Unlocking the Power of Data, 2e Help System Announcements ctice Assignment Gradebook...
.wileyplus.com/euugerynuymanium S Lock, Statistics: Unlocking the Power of Data, 2e Help System Announcements ctice Assignment Gradebook ORION nment PRINTER VER Chapter 2, Section 3, Exercise 107 Percent Obese by State Computer output giving descriptive statistics for ti percent of the population that is obese for each of the 50 US states, from the USStates dataset, is given in the table shown below. Since included, this is a population, not a sample. Descriptive Statistics: Obese Variable N N* Mean SE Mean StDev Minimum e Median e Maximum Obese 50 0 28.766 0.476 3.369 21.300 26,375 29.400 31.150 35.100 Percent of the population that is obese by state Click here for the dataset associated with this question. (a) What are the mean and the standard deviation? exact number, no tolerance LINK TO TEXT Privacy Policy. I 2000-2019.John Wiley & Sons, Inc. All Rights Reserved. A Division of lohn Wiley & Sons, Inc. Here to search 10096A 0:)
Answers
Answer:
a).
µ = 28.766
we know that \sigma =\sqrt{ \frac{\sum x^2- (\sum x)^2 /n)}{n}}
But given is the sample standard deviation s.
Therefore,
σ =
=sqrt( 49*3.369^2/50)
=3.33514
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