Question
Calculate the amount of copper (II) sulfate needed to prepare 100. mL of 0.0100 M solution
Calculate the amount of copper (II) sulfate needed to prepare 100. mL of 0.0100 M solution
Answers
The equation for Molarity must be rearranged to solve for the moles of solute (CuSO4). The moles of solute can then be converted into grams.
Moles of CuSO4 = Molarity (moles/L)
Volume of solution (L)
Moles of CuSO4 = 0.01 (moles/L)
Moles of CuSO4 = 0.001 moles
Now, convert the moles of solute into grams by using the molar mass of CuSO4.
Cu = 63.549 g/mol
S = 32.065 g/mol
O = 15.999 g/mol
CuSO4= ( 63.549 + 32.065 + 63.996 ) g/mol = 159.61 g/mol
Grams of CuSO4 = 0.001 mole
Grams of CuSO4 = 0.1596 g
Hence , The amount of Copper (II) Sulfate needed to prepare 100ml of 0.01 M solution is 159.6 mg
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