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RhadonRelation 2Domaln RangeDomain RangedooripensunpaperFunctlon Not functionFunction @at TunctionRelation 3RelationWakl) (7141).(6. ~1). (0,,6)} Functior Not &...

Question

RhadonRelation 2Domaln RangeDomain RangedooripensunpaperFunctlon Not functionFunction @at TunctionRelation 3RelationWakl) (7141).(6. ~1). (0,,6)} Functior Not & #hnceion((a 119).( -9).(8). (k-9)}Functicn

Rhadon Relation 2 Domaln Range Domain Range doori pen sun paper Functlon Not function Function @at Tunction Relation 3 Relation Wakl) (7141).(6. ~1). (0,,6)} Functior Not & #hnceion ((a 119).( -9).(8). (k-9)} Functicn



Answers

Find the domain and range of the relation. State whether or not the relation is a function. $$\{(-4,4),(-2,2),(0,0),(-2,-2)\}$$

With the following relation is a function or not function and if it is a function we need to find the domain and range. So here if we look at our X values, our X values don't repeat. So this is a function. So our domain are all the X values, So 149, 16 25, and etc, which we could also right as X. Such that X X is a perfect square. Our range are Y values, that is better. So range would be 246, 8, 10, 12 or we can say to extend it and etc. We could also say the wise such that why is a positive even number?

Okay, So the domain of this relation is this the set of all of our X coordinates? Yes. That's gonna be negative too. Zero 1 to 2. And because there were no repeats, this is going to be a function. We don't even have to look at our range to know that. And then arrange is gonna be just equal to the value of two. Since every element, the domain points to that value in the range. And like I said before, this is a function. And that's because there's no repeats in our domain, Thank you very much.

Welcome back. This problem you're giving relation. This is gonna take a welder. Rates we have one creates the to what makes the line two relates to blown. All right, let me have three relates to to Whoa. Four relates to to and five relates to to. So let's right out the elements of our green and range. All right, So what appears as art inputs? Here we have 012 34 and five. All right, what is our range? Well, what are our possible opens? You see, that one is a possible output. It appears multiple times, but it is one. Yes, unique output. Right? It's award is ready. It there ones no see. That, too isn't a possible output. And it also appears a couple of times, but we're just right ones. All right. I wish you were not on black, so it's not quite as what is wonky. All right, So is it a function? Well, you see that each of our inputs maps to exactly one output doesn't matter that half of them up to the same output in the other half. Mobster. Different output. The fact that is every single time we put in that zero. We'll always get out. Go already won. Every time we put in that three will always get out of two. Likewise, for the other, um, other elements of argument. So, yes, this is a function who's is a function.

All right for this problem were given. Oops, E her peers is your one 11 21 32 work to and five to. So what is your Who's that supposed to be a d right there with me? What is your domain? Well, what distinct inputs can we put? Have it for our relation? Here is that we have a 0123 for end E five. What is your range? In other words, what are the outputs that we can have? Well, we have he won one is repeated a couple of times. We also have a to so our rant range includes the elements went into Doesn't matter that where they're repeated a couple of times or just can put them in their ones Now is this relation? They function? Is it a function? Well, if we look at each of the art inputs each one, um Leeds. It's to exactly one l put right. We put in the zero always get our one. We put in the to always get out of one for putting. If I always get out of two on the same for the other, um elements a burger mean? All right, so yes, this is a function. Yes. Exclamation find underlined. It is a function


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