5

D0 46) |x - 5| + 12 < -7...

Question

D0 46) |x - 5| + 12 < -7

D0 46) |x - 5| + 12 < -7



Answers

Solve each absolute value inequality. $$12<\left|-2 x+\frac{6}{7}\right|+\frac{3}{7}$$

It would solve the given observed while you inequality there given inequality is 12. Liston minus two, Explicit by seven plus three basemen it doesn't provide is an equal day's a blackboard site office an equal to buy three Basic when they get 12 minus three Bay seven. Yes, then more or less minus to express. Six. Basement less three by seven minus three basically are simplifying this big it 81 by seven less than more less off mines to express. Six Bay seven. This can't be real address minus two. It's less six Bay seven data, then 81 by seven. You know that if morning is residency, then it's solutions that just Ulis than minus C or your residency. So applying the same concept here we shall write. This s minus two Ex bliss six base of it. Less than minus 81 by seven. Off minus two. Ex less. Six by seven. Greater than 81 by seven. First, little solve this inequality. Now this minus two ex less six by seven less than minus 81 by seven. So but I'm both sides off this inequality by six by seven we get minus two weeks less since by seven minus six way. Seven less than minus 81. Day seven minus six. Bay seven. Simplifying this We get minus two ex less than minus 87 by seven. No, I won't. I joked. This inequality with minus two, we get minus to explain minus two. And here it will be minus 87 by seven by minus two. Since we're dividing where the minus sign the final thing equality changes. It's on simplifying this bigot x greater than 87 by 40. Next visual sold this inequality thatis minus two. It's less since by seven greater than 81 by seven. Subject both sides was in equality by a six way seven Get minus two mics unless it's very seven minus six by seven later than 81 day seven minus six. Bay seven on simplifying this bigot minus two x greater than 75 by seven. Divide both sides off this inequality by minus two we get It's less than minus 75 by 14. Hence, the solution is set of all real numbers X that are less than mine. 75 way 14 or redder than 87 by 40. It's a building tradition. This is in present. Illness X is the real number since ident ext listening minus 75 Way, Woody. Oh, next rater than 87 by 40 Intern tradition. We shall present this US minus Infinity comma minus 75 by 14. Union 87 24 Game. Come on, infinitive.

To solve this inequality. We was split it into two parts, so one of them would be if Expo seven was positive, so that would be experts. Seven. There's less than 12 and the other part is a extra seven is needed, so that was negative. Explodes. Seven. Has really lesson 12. Now we can just all right on separately. So the left side that's easy with your subtract seven on both sides and we get X is less than what this one. We have a negative on the front, so we need to divide both sides by negative one. And when we do that because we're dividing by negative number, we need to flip the anabolic. So now we subtract seven on both sides, and we get X is greater than make it a 19. So our solution is that's where the naked of 19 and less than five, which we can write as that is greater than negative. 19. Bless them

So to solve this, I need to get the absolute value by itself. That means I'm going to subtract five from both sides, which will give me seven absolute X plus two greater than negative one. Then divide by seven. That's going to give me absolute X plus two greater than negative +17 Okay, so normally we would say that negative is a problem, but in this case, it it's going to make our lives very easy. Absolute values talk about a distance. Distance is always positive. A positive is always greater than a negative, which means no matter what I put in here for X, I will get a true statement. So X is an element of the rial numbers you could put anything in, and it'll work.

Yeah. In this question we've been asked to solve an absolute value inequality, we should isolate the absolute value first, which means we want to add seven to both sides. That results in a new inequality That is less than five. Now we can write to individual linear inequalities one where the expression inside the absolute value is less than five and one where the expression inside the absolute value is greater than negative five because the original inequality was less than we used the conjunction. And and we have to solve for ex subtract one. Sure, Divide by -4 which reverses the inequality. Subtract one, divide by negative, for which reverses the inequality And a negative divided by a negative is positive. 6/4 can be reduced to 3/2. Yeah. And on a number line We are looking for values of X that are greater than negative one and less than 3/2. So that would indicate everything in between but not including set builder notation. All values of X such that X is between but not including -1 and positive three halves. Who An interval notation indicates all values between -1 and positive 3/2.


Similar Solved Questions

5 answers
Revious Noueo charge To say Electrostatic of the Iin an can neither be created interact that. Forces '1 a whole-number multiple of the nor electric charge is neighboring electric charges Ih conserved electron. is to say that electric 1 (Zpts)8 '45000 # Overland Park Leavenon
revious Noueo charge To say Electrostatic of the Iin an can neither be created interact that. Forces '1 a whole-number multiple of the nor electric charge is neighboring electric charges Ih conserved electron. is to say that electric 1 (Zpts) 8 '45000 # Overland Park Leavenon...
5 answers
5 g potassium WI Wa grams Itbe the provided box. H content 1 are of a 8 standard Check my 'opeles ! wolk 159 'Bu There are about
5 g potassium WI Wa grams Itbe the provided box. H content 1 are of a 8 standard Check my 'opeles ! wolk 159 'Bu There are about...
5 answers
Point) Find tne volume of the solid enckced by (he paraboklds < = 4 (*and = = 50 4(2 +3)
point) Find tne volume of the solid enckced by (he paraboklds < = 4 (* and = = 50 4(2 +3)...
5 answers
HHICHA;FrltaFrovida Ihe reagenfs and or conditions necessary perform the following chemical transformationsJXDoHC01
HHICHA; Frlta Frovida Ihe reagenfs and or conditions necessary perform the following chemical transformations J X DoH C01...
5 answers
Solve using augmented matrix method: If the system has infinite number of solutions, state the general solution. If the system has no solution, explain why: X1 + 3x2 = 13x1 2xz = 14
Solve using augmented matrix method: If the system has infinite number of solutions, state the general solution. If the system has no solution, explain why: X1 + 3x2 = 1 3x1 2xz = 14...
5 answers
What is the IUPAC name of the alkene below?Answers:a: cis-2-methylhex-3-eneb. cis-5-methylhex-3-ene trans-5-methylhex-3-ene d. trans-2-methylhex-3-ene
What is the IUPAC name of the alkene below? Answers: a: cis-2-methylhex-3-ene b. cis-5-methylhex-3-ene trans-5-methylhex-3-ene d. trans-2-methylhex-3-ene...
5 answers
Write each expression using exponents.$$(3 t)(3 t)(-3 t)$$
Write each expression using exponents. $$(3 t)(3 t)(-3 t)$$...
1 answers
If $f(x)=2-6(x-1)+\frac{3}{2 !}(x-1)^{2}-\frac{5}{3 !}(x-1)^{3}+ \frac{1}{4 !}(x-1)^{4},$ what are $f^{\prime \prime}(1)$ and $f^{\prime \prime \prime}(1) ?$
If $f(x)=2-6(x-1)+\frac{3}{2 !}(x-1)^{2}-\frac{5}{3 !}(x-1)^{3}+ \frac{1}{4 !}(x-1)^{4},$ what are $f^{\prime \prime}(1)$ and $f^{\prime \prime \prime}(1) ?$...
5 answers
Question 5Let v1, 02, U3 and w1, W2, W3 be vectors in V. Suppose (v1, 02, U3) spans the whole space V, and (w1; w2, w3) is linearly independent:Is the following statement true?(v1, 02, U3) is linearly independent:Your True False selection(Only for true false question)true
Question 5 Let v1, 02, U3 and w1, W2, W3 be vectors in V. Suppose (v1, 02, U3) spans the whole space V, and (w1; w2, w3) is linearly independent: Is the following statement true? (v1, 02, U3) is linearly independent: Your True False selection(Only for true false question) true...
5 answers
10 What is the product of the following reaction?NaOCH;CH; 2. Hzot
10 What is the product of the following reaction? NaOCH;CH; 2. Hzot...
5 answers
If25 students in one class had an average of 93% and 20 sludents from another class had an average of* 98%, approximately what is the average percent of all 45 students?
If25 students in one class had an average of 93% and 20 sludents from another class had an average of* 98%, approximately what is the average percent of all 45 students?...
5 answers
CREDIT) Score: 27.41/50 "27/50 answered Progress saved Done VoQuestion 43C1pt 01 299Without using a calculator; compute the sine and coslne 0f 315 by using the reference angle(Type sqrt(2) for V2 and sqrt(3) for V3.)What is the reference angle?degreesIn what quadrant is this angle?(answer 1, 2,3, Or 4)sin(3158cos(315" )Submit Question
CREDIT) Score: 27.41/50 "27/50 answered Progress saved Done Vo Question 43 C1pt 01 299 Without using a calculator; compute the sine and coslne 0f 315 by using the reference angle (Type sqrt(2) for V2 and sqrt(3) for V3.) What is the reference angle? degrees In what quadrant is this angle? (answ...
5 answers
Point) Solve the system-12dx dt30 13with the initial valuex(0)13x(t)
point) Solve the system -12 dx dt 30 13 with the initial value x(0) 13 x(t)...
5 answers
Potassium chlorate decomposes Into potassium chloride and axygen How manY grams oxygen can produced from 12 Tolc cnlorate? (enter number onty;no: unlc round corert # slg figs)DotassiumQuestion15The average humanrequircs 70 K 10* gof clucose (Cakno per day: How Many groms photosynthesis reartion COz 640 CcHt O (enter number onty; not unit; round correct # siR fizs)nuquiredproolce 120 & of alucosefollowing
Potassium chlorate decomposes Into potassium chloride and axygen How manY grams oxygen can produced from 12 Tolc cnlorate? (enter number onty;no: unlc round corert # slg figs) Dotassium Question15 The average humanrequircs 70 K 10* gof clucose (Cakno per day: How Many groms photosynthesis reartion ...

-- 0.063792--