## Question

###### Parameterize the line from (4, 1) to (6, ~2) so that the line is at (4, 1) at t 0,and at (6, 2) att = 1.,0 â‚¬ (t) =-4 + 2t y (t) = -1 - 3t0 = (t) = 4+ 2t y(t) = -1 -3t0 = (t) =4 -2t y (t) = 1 + 3t0 * (t) = 4 +2t y (t) =1 - 3t

Parameterize the line from (4, 1) to (6, ~2) so that the line is at (4, 1) at t 0,and at (6, 2) att = 1., 0 â‚¬ (t) =-4 + 2t y (t) = -1 - 3t 0 = (t) = 4+ 2t y(t) = -1 -3t 0 = (t) =4 -2t y (t) = 1 + 3t 0 * (t) = 4 +2t y (t) =1 - 3t

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