I) In the lab there are some sample materials, as mentioned in table below. Hasan wants to identify material in the physics lab,and he chose one material of Area cm...

Determine the specific heat of a material if
a 35 g sample of the material absorbs 48 $\mathrm{J}$ as
it is heated from 298 $\mathrm{K}$ to 313 $\mathrm{K}$ .

Okay here we are given a body that has a mass of .15 kg and its temperature is increased. So DELTA T Equals 5°C.. Um and delta T. And Celsius and kelvin is the same. So I'm going to write this as Calvin And were given 385 jewels of energy too. Um cause this increase in temperature. So 385 jewels. Mhm. And we would like to know the bodies. Um So this mass is specific heat capacity. So we can do that by looking at our formula Q equals M. C. Delta T. And solve for that specific heat capacity C. So see equals cube over em Delta T Q. was 385 jewels. The mass m is .15 kg And Delta T. is five Kelvin. When we put that into a calculator, We end up with about 513 jules per kilogram Calvin.

In this problem suppose you have all the materials listed in table 18.1 of the book with a volume of one Centim cube for each sample at at a room temperature of 22 degree Sir shoes. So the problem as which of the following materials As the highest and lowest temperature when keep of one goal is added to each. There you are. And what is the value of this temple? Sure. So to solve this problem we will use the equation for the here since it relates the mass the specific hit and changing them very sure. Since on table 18.1 the specific case of which materials are instead. So Q. Is equal to M. C. About that where M. Is the mass the mother you see the specific hit and got A. T. It's the changing them. Very true. Isolating well that is the left side CN stand military sweating. Then the equation becomes like this. I see you can see we can infer that the temperature. Mhm. The final temple ritual. Since we know that DELTA T. Is equal to different final and initial temperature. So the patient begins like this. So we can infer from this equation that the final temperature yes inversely proportional through the specific it. Now scenes I'm on the list lead has the lois specific heat therefore. Okay, lead has the highest fine I think very true. And scenes water that's the highest specific it Table 18.1. Therefore, since it was brought inversely proportional temperature. Water has the lowest. Now let's determine the numerical values of this. So using our equation there you have this and not that the mask are not given. But the density we know the density of these materials and the volume is given. So we can use the formula for density with this which is desert is supposed to mass over volume. Then massive goes to volume, multiplied by the density. Then our equation becomes like this. Then for lead we have one jaws. Mhm Over dis quantity the density of leg which is 11.34 g per centimeter cube given volume which is one centimeter cube. And the specific heat of lead Which is 0.129 joe per gram Calvin. Yeah. Yeah. Then this quantity plus the initial temperature which is 22. Okay. The researchers and we can find that the final temperature is of lead. Yes 22 boy 684. And for the water we have see immigration one joe's already visit of water which is one grand person. two m cube. The given volume multiplied by the specific heat up water which is 4.19 jobs program Calvin plus 22° Our Shoes. And we can find that This is equals two 22.2 Trina researchers. Yeah. Okay there. Okay.

So all the medals have Mueller hit capacity off 24.8 Jews on this. I was there when the water hit capacity of silver that is edgy as in the same as this 24 point and specific capacity is going to 30 toe problem, which we have can't visit it. So this was very close to the permanent value off 0.23 says job down.

In this situation, we have given a cubical box whose volume is 216 semi job. And inside this it is heated by electrically by 100 watt hitter. And we have given the temperature difference between inside and outside surface and it is told that it is in the study state. Now we have to find the thermal conductivity of this material. So first of all, I am growing the diagram for the institution that this is a cubical box. And we have told that in this there is the electrical hitter. So let this is our electrical later inside this box. And we have given the volume of this Box that is v equals 2- 1 6 semi q. This is typical work box. So this can be written as QB because 2216 is the age of this cubical box. So from here we get the value of it that is six semi. So surface area can be written as that is six times of a square. So this is six into 60 square. So they feel comes out to be 216 into 10 to the power minus four m square. So this is the surface area of this cubical box. Now we see that it is flowing from this two outside this is the which is growing from all these surfaces. So And we have given the temperature difference of inside and outside that is the entity is 5°.. Yes. Yes. And we have to find the thermal conductivity that is so we can see that. Mhm. Floor it can be written as to buy tea is equals two. Okay into temperature difference delta T upon L. Now put all the data in this situation. So this is given to us. That is 100 war. So this is 100 is because two. Okay, we have to find area is 216 and 210 to the power -4 and this is five. And technology is given to us that is zero Once a me. So this is your .1 into 10 to the power -2 m. So from here we get this if Jay Z equals two zero point after. So when we get case, because two, 259 watt per meter degrees has here. So this is the answer for our given to shin. Thank you.