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The cockroach Periplaneta americana Can detect a static electric field of magnitude 7.50 KNIC using their ong - antennie If I ecess static churge o cockroach is moc...

Question

The cockroach Periplaneta americana Can detect a static electric field of magnitude 7.50 KNIC using their ong - antennie If I ecess static churge o cockroach is mocleled pent charges Iocated : the end of each antenna: what mgnifude of charge would euch anlenna pOSse"s$ onler for each antennae experience fon e of magnitude 4.50 AN fromt the eilernal electric field? Calculate utits (f nanecoulnbs (nC)

The cockroach Periplaneta americana Can detect a static electric field of magnitude 7.50 KNIC using their ong - antennie If I ecess static churge o cockroach is mocleled pent charges Iocated : the end of each antenna: what mgnifude of charge would euch anlenna pOSse"s$ onler for each antennae experience fon e of magnitude 4.50 AN fromt the eilernal electric field? Calculate utits (f nanecoulnbs (nC)



Answers

Biology The cockroach Periplaneta americana can detect a static electric field of $8.0 \mathrm{kN} / \mathrm{C}$ using its long antennae. If we model the excess static charge on a cockroach as a point charge located at the end of each antenna, what magnitude of charge would each antenna possess in order for each antennae to experience a force of $3.0 \mu \mathrm{N}$ from the external electric field? Example 16-5

So we have two charges. 26 micro column on minus 47. Micro column on the force. Between them, it's 5.7. You don't you want to find the distance between there? Remember, four speed. We do charges. Yes. Hey Q on Q toe by our square. But human and cute, Remember, are the magnitude of the force on absolutely magnitudes of the charge and f is the magnitude of the force. We don't care about the direction in this formula. So using this formula, you can see that if you send the r squared or to the other side and after the other side kick, you won, you do by F and that is it. I'm sorry. This is our square. So you take a square root on both sides and you see that we can find the distance using this formula. And that isn't will simply stop shooting her values. So that squared off. You know about the value of K. It's 8.99 times 10 bar, nine Newton meters square for Coolum scare. Coolum Square on our charges are 26 on 47 micro columns. So that's 10 fire minus six for each. So tell me about £10 minus six squared Coolum squared, divided by our distance. Forced here simply 5.7 Newton's. The newness gets cancelled. Begin cancer early school square on D squared off meter square is simply meters and this gives us the distance, which is 1.39 meters. Simple is that?

Little strong of the vector diagram. Ah, that here is the cumin. And then here is on the Q two right, and the distance between Q one and Q two is one meter right? And here is another point. Ah, week white coordinate zero point five meter. Right. So let us find out electric fields at this point, you to kill one in Q two. Well, do to cure one. So electric field is in this direction. Let's say this is e one. And from Are you too, right? Electric field is in this direction and disease detour. Right now, Let's, uh, result. Be wanting. He dio in two compliments. Well, this is E one, uh, sign or 45 degrees. Remember that this angle is equal to 45 degrees since this equals 45 right then by using geometry, Peter is also 45 okay? And the x component of E to his e to sign 45. Right? So you see, to assign 25 okay and further. Um, excuse me. Not the single rather to single. It's equal to teeter. Right? Um, this one. This angle is equal to feed our saying that is also equal to Peter, right? Okay. Right. And the vertical component is, uh, Lake e y is equal to do E one co sign of 45 less e to in to co sign of 45 and e x on e x is equal to, um, even sign of 45. Right? He accessible to Yvonne. Sign of 45 minus e to sign of 45 25 degrees. Now latest find out e one any to I so e one is equal. Do Okay, times cure Divided are square Will K's 8.99 motive migrate into the Volver nine and cure is 20. Multiply by 10 to the dollar minus line divided but are well it's do 0.7 and there for anyone is equal Teoh 366.93 Now let us find a P two p two is equal to que times killing Divided are square P s 8.99 multiplied returned to the bar nine and here it is 20 multiplied attended Holland minus nine and our 0.7 old square. So this are is from the figure it's equal dizzy Form seven and e two is equal to 183.46 Now we can easily find out he accident E y. So he acts is equal to 366.93 most of my by sign of 45 minus 1 83.46 Multiply by a sign of 25 degrees, and therefore E X is equal to 129.73 and E. Y. So you, why is equal do pre 66 0.93 multiplied by no sign of 45 less 1 83 Mind. 46 Times Co. Sign of 45 On day four R E y is equal to 3 89.1 it. Now we can find out the total electric field well, The result and electric food is given by he X were list e my square. So by substituting the X and the Y 1 29.73 holds were less about 3 89.18 hold square. So being for E is equal do 410.2 three Newton curriculum, and we can also find out angle using pita is equal to Jane in worse to Why? Divided my ex. So why is 389.18? You know, Danny Worse, who divided by 1 29.73 So if he doesn't is equal to, um, cream in the positive axe direction, creating the positive X direction, right?

And this problem the concept covered is the concept of electrostatic force due to the electric field. So the force exerted by the field is the Cuban into the magnitude of the electric, feed into the magnitude of the church. And from the situation we can write the equation for the magnitude of the electric field. This the force exerted upon the magnitude of the church. And from the problem, the force exerted equals zero 05 No tints, and the magnitude of the charge equals 1.5 into tenderness -8 cooler. Now we can substitute the values to find the magnitude of the electric field, so the magnitude of the electric fuel equals 0.05 newton upon 1.5 into endless -8 cooler are the magnitude of selected failures, 3.33 into Then the six newtons for

Hi and this given problem, There are the two charged particles you won and you do kept at a gap are between them both the charged particles are identical, having a charge plus 400 nano Fulham. And the gap between them is given us 20.0 centimetre. Let it be at a let it be at B. Then the midpoint between them that is C. It will be having a distance 10 centimeter from both the charged particles. No, we have to find net electric field at this midpoint there this midpoint that is C. We know electrical always goes away from the positive charge as both of these charges are positive in nature. Electrical due to a that will be going away towards be an electric bill due to be that will be going away from B towards a. Now using expression for electric field hey into Q by our square as the charge. The key that distance all are same and the stands, sorry the direction is opposed so we can say as E A and E B are having same magnitude but opposite direction. So they will cancel each other hands. Net electric field at this midpoint will come out to be zero. Which is the answer for this given problem here. Thank you


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