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What is the chl-square test-statistic for this data?Report all answers accurate to three decimal places...

Question

What is the chl-square test-statistic for this data?Report all answers accurate to three decimal places

What is the chl-square test-statistic for this data? Report all answers accurate to three decimal places



Answers

Match the decimal with its percent form. a. $5 \%$ b. $50 \%$ c. $80 \%$ d. $33 \frac{1}{3} \%$ e. $30 \%$ f. $500 \%$. $$0 . \overline{3}$$

In this question we are going to round several numbers to the nearest thousands first one. Yeah. Mhm. Yeah. Instead of using the fraction bar I'm going to write it out the thousands place Is the 3rd number past the decimal. So I look at the eight since it's bigger than five I round this eight up point 0.8 89. Next one. Yeah. Yes. Mhm. Thousands place. Look at the four. It's less than five. So we keep the numeral in front as it is next one. Yeah. Okay. Yeah. Thousands place less than five. Keep the six as it is last one. Yeah. Yes. Thousands place Following number is a five. We're going to round the four up. Okay. Yeah. Yeah. Okay.

Suppose we have a four digit number. It will look something like this with a comma between the first and second digits. So let's label the values of these. The one on the far right is always going to be one, and then the one to the left of that will always be 10 adding a zero than 100 adding another zero and adding another 0 1000 So the third term from the left is going to be 10 in this case.

Did you find the meaning of this sequence? Nina, You noted by the expert or what did you do? Is we end up all the time together, Andi. Then this tree, this 90 Children with the vibe. A little over a number of times. Him we have 12345 and six. So in November 6 here. So we should have the minus six plus zero Blast three plus four plus three plus 92. Then we do have a six. We get Geico Jenna 16.

Consider the given real number. Here. We need to approximate the serial number two three decimal places. And the first solution is by using rounding method so to 6.9951 And here we see that the third decimal is five, an extra 30 smell, It is one. And since one is less than five, the third decimal place reminds the same. That is after grounding up, it will be approximately 6.995 Now in the subdivision we need to use truncation so it is 6.9951 And here the third decimal places five. And now, in order to truncate, we eliminate all visits to the right of five. That is will eliminate one. So after john education, this will be approximately equal to 6.995


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