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Given table the relation between and Ior the Ohm' $ Iaw experiment. Plof a graph using the gien values: Calculate the slope and find the value of the unknown ...

Question

Given table the relation between and Ior the Ohm' $ Iaw experiment. Plof a graph using the gien values: Calculate the slope and find the value of the unknown resistance. Wrlie . conclusion about the graph and the resultI( mal0.OoOO5 0 OOO1 0.00015 0.0002 0.00025 0.0003 0.00035 0.0004

Given table the relation between and Ior the Ohm' $ Iaw experiment. Plof a graph using the gien values: Calculate the slope and find the value of the unknown resistance. Wrlie . conclusion about the graph and the result I( mal 0.OoOO5 0 OOO1 0.00015 0.0002 0.00025 0.0003 0.00035 0.0004



Answers

The values of current $I$ flowing in a given resistor for the corresponding values of potential difference $V$ across the resistor are given below $\begin{array}{l}I \text { (amperes) } & 0.5 & 1.0 & 2.0 & 3.0 & 4.0 \\ V \text { (volts) } & 1.6 & 3.4 & 6.7 & 10.2 & 13.2\end{array}$ Plot a graph between $V$ and $I$ and calculate the resistance of that resistor.

Okay, So this is the potential versus current graph. As you inside of the gravity is a straight line that meets the night grown obeys the Lone Star in this case. Okay. And the resistance in the resistor is just simply you go through the slope phonograph, which is you ve a be over. I, as you can tell the slope here is it to three point a. So there for the resistance, you see 4 to 3 point a omega. And these are the answers for this question.

The figure shows graph our potential. It's a function off current here. The graph is ah syllabi suggested lying with constant. So the corruptions did well dish and good and done linearly proportional to each other. So the graph fulfills the conditions are homes and, uh so we can apply Tomsula. So this object he had the slope of Gaurav is he goto judging? But don't you difference upon catching current which is equal toe really sense. So here sell abuse resistance of the object? No, In the third part, we want to calculate Slow up the graph. It's a little off autograph that is able to judging for breaking difference upon judging gun judging potential different that is Let me do minus. We want a pawn. I do minus. I won from the graph in the constricted triangle we have we to is 0.6 their world minus everyone ese 0.30 world upon I do is 4.0 1,000,000 Pierre minus I want is 2.0 1,000,000 Pierre. So the hell so equal do 0.30 world upon true 0.0 1,000,000. Pierre, which is it gonna do? They're a part of trees in the world upon to multiply 10 to the power minus three and beer. So we have slow equal to 1 50 well home.

In this problem were given this equation which relates the diameter of the copper wire to the resistance. Oh, the copper wire And what we want to do first is complete the table. This is part A and a great way to complete the table for this money values is to go ahead and use your calculator. You have a graphing calculator that has a table feature Goto y equals Take the function in. You don't necessarily have to grap it, but what we're going to do is type the function in so that we can then use a table to find the values. So there's a function. I think I forgot my subtraction sign there. Let's get that in. Okay. And I'm going to go to table set, which is second window. I'm going to make sure it says independent ass. That way I can type in my own X values. Then I'm going to go into the table, which is second graf and I'm going to type in the X values from the table. There was five 10 20. We had all the multiples of 10 on up until we get to 100 and you can see the calculator is finding those y values for us, and then we can just transfer them into our table. Okay, so here, you see that I've written all those why values in my table. And now I'm going to plot those points to sketch a graph of this model. So what we want to Dio is go ahead and you can see that I made my scale on the X axis, going from zero up to 100 my scale on the Y axis going a little higher than 400 because of the values we saw from the table. And so we comply at 54 30 10 107. That's a big drop. 2026. Another big drop. And then you can see these numbers just get so small, it's going to be very difficult to tell the difference between them just kind of roughly estimate that, and then we can go ahead and draw that curtain. Okay, so that takes care of heartbeat. Oh, there's another part of part B which is use them graft to estimate the resistance when X equals 85.5. Well, that's gonna be a little bit tricky to Dio, 85.5 is right about here. And, well, it's gonna be hard to tell what that y value is. Maybe we can kind of fudge it a little bit and look at these X values. And why values? Let's estimate it's at about 1.1. Okay, Now, for part C, we're going to algebraic Lee confirm that the resistance is approximately 1.1 when the diameter is 85.5 mills. So we're gonna take 85.5 mills and substituted in for X in our equation. So we have y equals 7 10,070 divided by 85.5 squared minus 0.37 And we do end up with approximately 1.1. I should make that an approximately symbol. Two more accuracy. I have 1.103 etcetera. Okay, So that estimate, even though the graph was very rough, was not do that now for party. What can we conclude about this relationship? You can see that as X gets larger, so does the diameter increases the resistance significantly drops. All right,

Okay, So this is the graph for the, uh, potential verses, currents, And, as you can tell and the graph for the potential, where's his currents? It's not a straight line they missed. Uh, all right, That's not obey the owns law, OK, and then this is the resistant worships Corrine graph, and these are the answers for these questions.


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