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Five forces are listed below:5 kN5 mN5 MN5 nNStarting with the smallest first; arrange them in increasing order of magnitudea. 5 mN5 nNkNSMNb. 5 nN5 mN5 kNSMN5 nNkN...

Question

Five forces are listed below:5 kN5 mN5 MN5 nNStarting with the smallest first; arrange them in increasing order of magnitudea. 5 mN5 nNkNSMNb. 5 nN5 mN5 kNSMN5 nNkNMNSmN5kNmNMNSnN

Five forces are listed below: 5 kN 5 mN 5 MN 5 nN Starting with the smallest first; arrange them in increasing order of magnitude a. 5 mN 5 nN kN SMN b. 5 nN 5 mN 5 kN SMN 5 nN kN MN SmN 5kN mN MN SnN



Answers

Five forces act on an object: (1) $60.0 \mathrm{N}$ at $90.0^{\circ}$ (2) $40.0 \mathrm{N}$ at $0.0^{\circ},(3) 80.0 \mathrm{N}$ at $270.0^{\circ},(4) 40.0 \mathrm{N}$ at $180.0^{\circ},$ and (5) $50.0 \mathrm{N}$ at $60.0^{\circ} .$ What are the magnitude and direction of a sixth force that would produce equilibrium?

This exercise. We have four force vectors that have the same magnitude s and we have to find what is the maximum magnitude of the Net force? Ah, that results of adding the four vectors. And what is the smallest possible magnitude? Remember that the maximum possible magnitude will happen when all four vectors are lined up. When they all have the same direction, the same sense, the same orientation, then the magnitude off the some of the factors is just gonna be the some of the magnitude of the vector of of the vectors. So suppose that we have f one plus F two plus a three plus F four and suppose they are all lined up in one direction. So suppose we have you're a graph and we have f one in this direction than F two is in this interaction. Then at three in this interaction, then f four in the same direction. In this case, the total magnitude will simply be the some of the managers of the individual forces, which is four times the magnitude f. So this is the maximum magnitude of of the net force, so maximum ah f net is able to for F. You know that's try to find the minimum. So suppose Ah, that's all four vectors from out of all the four vectors, F one and F two are lined up, and F three and F four are pointing in the opposite direction as F one and F two. So in the case we would have F one and F two pointing in this interaction while f two I'm sorry of three and F four were pointing in the opposite direction in this case, F three ah, and therefore cancel the contributions from F one and F two and the Sun and for endless at two was a three plus have four is equal to zero. So the net force, the minimum net force, is equal to zero, and this concludes the exercise.

This problem, we have given five objects. Object has 243 K in the X axis and two K towards the Y axis to the magnitude of net. Force will be equal to the road two square, three square. So this will be equal to and the Road four plus nine, which is 13 k. This is under hood 13 K Net force. Now you talk about object B on object B. The net force also is equal to two squared plus three square. That means under Rule 13 J now net force on civil of equal to three K minus took. That means one K. Newton. This is the net force on objects. See, this is the networks on objects V. This is the networks on object. Now, if we talk about the object to D Net Force is a call to two K Last three K. This is equal to five K. This is the Net force on object to D. Now, if we talk about that object is about this angle is theater. So we can say this is a call to suppose the theta is equal to 30 degree so we can say this is a call to net force will be equal to two key here and this is equal to three sign 30. That means three by two in this direction. And here in this direction three costs 30. So the net force will be called to and the road mhm. So the networks will be equal to 2.6 minus two. That means 20.6 square plus 1.5 square. So this is a call to 1.5 square. Let's wind 60 square. This is equal to 1.6 K. Now the smallest forces object. Uh, on objects, see f force on objects, see, and then foods on object. We know that under 13 is a call to around 3.6 k after object on C four zone object, see and then force on object mhm. And then force on our objective A and B and then force on our second game. This is the the ranking of the forces on five objects. Thank you.

Problem. Five in this problem. Three forces are acting on a mass block as soon in this diagram. And we have to determine the magnitude of force F. So that the mass M is act arrest means resultant force acting on the mass. zero. So for resultant force on anybody to be zero. Net force in horizontal as well as invited that as well as in vertical direction must be zero. So, first of all, we will resolve this five newton force which is acting at an angle of 53 degree in its horizontal and vertical component. So let us say These two are representing its horizontal and vertical component. Therefore, original component of this five Newton force will be five, Cost 53° And vertical component will be five. Sign 53. Dealing. Now from trigonometry we know the value of sign 53° and it is four by five and Cost 53° Is three divided by five. No, let us take that is are the forces in vertical direction balanced or not? So in vertical direction in a particularly upward direction, five signed 30° signed, 53° acting Therefore. 5 5 sign 53° will be equals 25 multiplied by sign, 50 three's four divided by five. So this five gets canceled. So this is for newton. Therefore, in vertically upward direction for newton forces acting so particularly downward force of same magnitude will balance the forcing vertical direction. Therefore, net forcing vertical direction is Balanced. Now we have to balance the forces in horizontal direction, so to balance the forces in horizontal direction, f must be equals 25 costs 53 tickly. Now we know the value of cost 53 degree. It is three by five, so five gets canceled. So this is three newton. Therefore, value of force F should be three Newton. So, from the given options option is the character option? Yes.

Before I even read the problem, I generally just go ahead and draw the diagram. Maybe that's not the best form, but ah, that's what I'm doing. Anyway, Um, I don't really like where the eight killing Newtons is drawn. So I'm gonna move this up and I'm going to draw it down word like this and then the force. And I don't like how that forces drawn either. I'd rather have it in the other place. And, you know, you could just move forces around if you want Teoh. Okay, so now we've got another force year, which is I hate it when I do that. Another force, which is f like this 30 degrees and we call this F. Okay, So the reason why I moved it this way is because I want all the beginning points to be at the same point a little easier for me. Teoh. Visualize. All right, what are the magnitudes of Force F to the resultant is a small as possible. Okay. I want the result in to be a small as possible. Well, this is think about this. First, it could completely cancel out the six killer killing Newtons. But then it would be putting Mawr Force in the direction of the eight killing news. It can't cancel out the eight killing Nunes unless the unless we're allowed to put it in the opposite direction. I don't think we're allowed to dio um so but this is looks It looks like it might be a little difficult. So nevertheless, I'm going to write all out of these forces in the UAE directions. The force resulting in the Y direction is Well, it's gonna be af times the sign of 30 plus eight killer news. The resultant in the X direction is going to be six minus f co sign 30. Okay, now the result, it is going to be the square root of f R. Why squared plus f r ax squared F signed 30 plus eight squared plus F note six minus f co sign 30 squared. So I'm gonna graph this and just look for where it is the minimum ID like to show you this, But unfortunately, my computer lags so much when I try to show this won't share the calculator. Why equals the square root? Uh, efs uh, it's just I don't know what F is so I'm going to write X sign. 30 looks. Eight squared plus six minus X. No sign. 30 where All right, the minimum is at the point zero common. 10. It appears interesting. Drawing looks almost like a parabola. Uh, that's not the minimum, though. The minimum that was the Y intercept. The minimum is actually that f equals one point 20 killer news, and the resultant is going to be the Y value 9.93 killing ends. Let's see is this question. The answer is not in the back of the book. So when it's not in the back of the book, I think about whether it makes sense, especially drawing, considering this drawing here.


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