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Name and draw the major product(s) of electrophilic chlorination of the following compounds:(a) $m$ -Nitrophenol(b) $o$ -Xylene (dimethylbenzene)(c) $p$ -Nitrobenzo...

Question

Name and draw the major product(s) of electrophilic chlorination of the following compounds:(a) $m$ -Nitrophenol(b) $o$ -Xylene (dimethylbenzene)(c) $p$ -Nitrobenzoic acid(d) $p$ -Bromobenzenesulfonic acid

Name and draw the major product(s) of electrophilic chlorination of the following compounds: (a) $m$ -Nitrophenol (b) $o$ -Xylene (dimethylbenzene) (c) $p$ -Nitrobenzoic acid (d) $p$ -Bromobenzenesulfonic acid



Answers

Draw structures of and supply names for the organic
compounds produced by reacting ethene with each of
the following substances.
\begin{equation}
\begin{array}{ll}{\text { a. water }} & {\text { c. hydrogen chloride }} \\ {\text { b. hydrogen }} & {\text { d. fluorine }}\end{array}
\end{equation}

For discussion. We have to represent the formation off a compound using the condensed structure Starting adoption. Hey, we have been Zwicker said that a C six bitch. Fine seat. Who, bitch? When's weak ass it along with ethanol C two h 50 h. That gifts ch three c h 20 c double mourned oxygen. I've been doing so this called ist it kind Ben's await moving towards second option. We have economic asset on dhe metal. I mean, so Veronica said, Well, even ch three c double bond go who? Which, along with CH three. And it's too it to make acid along red metal. I mean, which gives us ch three and hi George in C C H three along with double bonded oxygen. This compound is called and I'm right. So auctions see the reactions will be asked to casted on final oof Who let us start ascetic acid and Finn All this reaction give us the formation off finial acid ate. It is represented as the H three who which, along with the female

For this one. We have to draw the condensed structure off the compound phone. So starting with Option A, we have beauty tannic acid along with methanol. So beauty, Annika said, will be ch three ch two. See? It's two C o. H, whereas the methanol will be ch three. Who etch it, Give us the final compound, which is CH three. Oh, see double born o See It's to see it's too See a street. This compound is a bit tight, bit down. Wait or should be, were provided with the reactions. Ben's Week asset on dhe to prop inal So Ben's Wicca said, will be re presented. Us C 00 h. Benzene on to prop in all will be ch three c h sietch tweet along with which this reaction needs to formation off ch. Three c c h. Three. Hide Georgian excision. Double want excision on DDE Benzene. The product is called us to battle the tire benzoate auction. See the reactant are proponent asset on dime a tile proponent. Cassidy's c'est three c. It's too C O H. What diamond trade. A mean ruby sietch treat too. An itch. This leads to formation off ch three night Georgia. See, it's ST Carbon Oxygen. See, it's too See? It's three. The product form. This called us n n Die metal being a mite so yeah.

For auction E the RU The molecule is made up off and Toxie group attached with beauty in Jane the ups The name is one talk See beauty provided the common name is beauty in tight in tow for option B In this molecule on it, Toxie Group is attached to Propane Jing The R u B SC name is one it Toxie Propane The common name for this molecule is entire profile Ito auction See over here Um a toxic group is attached to propane chain Therefore are you B SC name is want mid Toxie dropping And the ups he name is one are you B sc name is metal profile Ito

Okay, so you were just introduced to, um, substitution effects and, um, directing groups. Right. So you're given three sets of compounds, and all of them have varying degrees of activation Deactivation. Um, so you in each scheme, you basically just have to, um, figure out which you're going to react, um, or rank them in order of rate of reaction. Right. So deactivated rings are going to be, um, first foster. So number one will be the most deactivated, and then I'll will go off to four, which will be the most activated. So basically, you're ignoring the benzene ring. You're just looking at the substantial INTs. Um, pretty much right. So in the first scheme we have, we have nitrobenzene. We have final. We have tall, you mean, and we have regular benzene. So, um, if you look at all of the groups, right, So in this case, we have one deactivating group that's the Nitro group, and we have to activating groups. That's the hydroxide group and the Method group. And then benzine has an age shits. That's nothing. Right? Um so the deactivated group is going to be number one. This is the slowest. And then essentially you have. Um you have to activating groups and you have benzene. So the any type of activating group is going to give you a faster, faster rate to Elektra Felt Iraq substitution that benzene Well, so by default, benzene is gonna be too. And then when you're stuck with all of your activated rings, which ring is more active So you go to page 5 81 and you look at the the classification of substitution effects, figure and use. Look at where hydroxy hole is in comparison to alcohol. And hydroxy is much more activating that the alcohol group, so tall you mean is gonna be Josh slower than fennel. So finals going to the fastest here. So you do the same thing in, um and be right. So in this case, you have to deactivating groups. You have the Korean and you have this this Essel group, this carb oxalic acid. It's not really in a cell. Groups are a so implies there's an alcohol mandarins. This is a car box. Elder acid, Um and then you have on activating group in the final here. So, um, which so, in terms of your deactivating groups is the is the c o h. More deactivate than your Korean on. The answer is yes. Right, So the halogen aren't are just slightly deactivating, um, in comparison to all of your other Carbonell containing, um or some kind of carbon or sulfur Nitrogen, double bonds, toe oxygen containing group. Um, So, um, your slowest is gonna be more deactivated, Which means your benzo gas that's gonna be the most deactivated, followed by your Korean. So you rank those two first. Oh, sorry. I'm going. I just changed my number Scheme on you. Um, so one is the most deactivated. So too, is going to be here. Um, so I just wanna make my key. So one is slowest, and then four is the fastest I shared in at the start. I'm sorry. Um, so then you left with one activating group and benzene, right? So the activated group is going to be faster than then. Benzie and so finals going to the fastest again here. So finally you're left with benzene, bro, Benzene, Ben's, Alba hide and Antolin. Um, so identify your groups, right? So you have deactivating, deactivating, and then Antolin is one of the most strongly activating groups. It's on the same order as the hydroxy group in terms of most strongly activating the ring. Um, so again, you have a halogen in terms of deactivating groups. What? You're gonna be the slowest. You have a halogen versus ah Carbonell containing group. So going with the same logic, we just didn't part B. You're slow West is gonna have been solved. A hide followed by bro me in. And then you have your activating is going to be the fastest, followed by regular trailing regular benzene. Um so always look, look at the group's right. The most deactivated ring is going to be the slowest, and the most activated drink is going to be the fastest towards the next edition Reaction to the ring. So, really, you're just, um, cup commit that that chart to memory for your exams. That's that's really all you have to consider in these in these reactions here in these


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