5

[25 Points] The cell CdICdCl2(6.62 m)ICl2(1.000 atm)IPt has a cell voltage equal to 2.0 V at 25 %C. The 7.0 mollkg solution of CdClz is saturated and is at equilibr...

Question

[25 Points] The cell CdICdCl2(6.62 m)ICl2(1.000 atm)IPt has a cell voltage equal to 2.0 V at 25 %C. The 7.0 mollkg solution of CdClz is saturated and is at equilibrium wth CdClz 5/2H20 and water vapor at 17.0 torr: The activity coefficient of CdClz at this molality is equal to 0.03. The vapor pressure of pure water at this temperature is 24.0 torr. Find Ee for the cell and AGO for the reaction. Cd(s) Clzg) 5/2 HzOv) CdClz 5/2 HzO(s)

[25 Points] The cell CdICdCl2(6.62 m)ICl2(1.000 atm)IPt has a cell voltage equal to 2.0 V at 25 %C. The 7.0 mollkg solution of CdClz is saturated and is at equilibrium wth CdClz 5/2H20 and water vapor at 17.0 torr: The activity coefficient of CdClz at this molality is equal to 0.03. The vapor pressure of pure water at this temperature is 24.0 torr. Find Ee for the cell and AGO for the reaction. Cd(s) Clzg) 5/2 HzOv) CdClz 5/2 HzO(s)



Answers

The vapor pressure of water at $20.0^{\circ} \mathrm{C}$ is 17.5 torr. $\mathrm{At}$ that temperature, what would be the vapor pressure of solution made by dissolving $23.0 \mathrm{~g}$ of $\mathrm{NaCl}$ in $0.100 \mathrm{~kg}$ of water? (Assume complete dissociation of the solute and an ideal solution.)

So for this question, we need to remember that pressure. Uh, they put pressure above a solution to a mixture, I guess of two different liquids. So liquid and liquid be the total pressure vapour pressure that is is going to be equal to the mole fraction of a times the pressure of a this work pure liquid, plus the mole fraction of B times. The pressure be if it were here looking. And so we'll have to work to get the mole fractions here, but and were given the pressures. So where should stay? In this case, that is the methanol and B is ethanol. And so the pressure of pure methanol is 92. Tour the pressure of here. Ethanol is 45 tour. It's now it's where to find the mole fractions. We have 25 grams with methanol. We have 75 grams of ethanol. We want to divide by the molecular weights for each of these to get the number of moles. So over here we're going to multiply by one for every single bowl we have. Ah, 32.4 grams. That's the Michler. Wait. So you see the grams units here will cancel out with Divided. By the way, we're gonna find that we have 0.78 02 moles of methanol here. We're gonna divide by the molecular weight of ethanol, which is 46.7 grams and every more. And so these grams will cancel out, and we're going to find that we have 1.627 moles. And so now the total amount of balls in this solution is going to be the 0.78 plus 1.63 I'm rounding here a little bit and so going to find the way about 2.4 moles total it. And so, if we want to find the mole, fractions were going to take this number divided by 2.4, this number two by 2.4. And so the mole fraction for methanol is gonna be equal to that 0.78 malls over 2.4 months. And we're going to get, uh, 0.3 to 5 as our mole fraction and our mole fraction for ethanol is gonna be equal to, uh, 1.6 malls over our 2.4 moles and said, I don't give us about 0.66 And so now we have our mole fractions for each of you. Is this Is this a soy geometry question? Basic. Now, a plug those in. So for since methanol is want the 92 tour, we're gonna plug in the 0.3 to 5 here, then the other 1.66 for ethanol in, so we can, you know, put us into a conclave. We'll get our final pressure of 60 tour, and that makes sense is between 92 45.

So we have, Ah, 25 grams methanol in 75 grams of ethanol in a mixture weighing 100 grams, and we want to know what the vapor pressure of that mixture is, and that will be some of the vapor pressures for the two substances. So what we need to dio is find out the vapor pressure of each substance, and that will end the mixture that will depend on on the mole fraction. So we're gonna need to know the moles of each substance. So I've added up the molar masses. That's 0.0 point 78 months and 1.73. So this is the methanol. This is the ethanol. The, uh, vapor pressure of the methanol will be. It's mo for action over the some. Well, of course, it's moles from the some of the most times, the vapour pressure it would exert if it was pure and that is, that is, that is given in tour or millimeters, which is the same thing into that mole fraction has 0.3 or four, so the methanol would be exerting 28 tour or millimeters, and then the vapor pressure of the ethanol in the mixture is gonna be. It's moles over the total times its favorite pressure. And that is 0.696 696 said what I meant. But I didn't write what I meant. 31.3. And so the vapor pressure of the solution would be 59 point three tour.

Your problem. 100. We're calculating. Be mass of any CEO, given the following information in case. So we're given the most of H 20 and were given the vapour pressure. So, um, we're going to find out the massive any cl by solving for the most first. So we have We're going to use the mole fraction of water. Okay, so the mole fraction of water is he goes to the moles of water plus or sorry over the total number of moles, which is just the most of water and the most of our salyut, which is so do you all right. And they CEO. So one thing we need to remember is that anything else is a strong electrolyte disassociate into, um, a soda, my on and a quarried ion. So we need to multiply this most by two. So, so far, what we have is the most of h 20 Okay, So before we could. So, for the most of any CEO, we need the, um, mole fraction of water. So we're going to figure out the mole fraction of water using the vapor pressures that are given. Okay, So the pressure of the solution. The pressure of the solution is equals to the mole. Fraction of water times the pressure of water at this temperature. Okay, so we're given all the vapor pressures. You just need to rearrange this equation. So mole fraction of H duo is he goes to the pressure of the solution over a D vapor pressure of water. So plug those numbers and we have 25.7 tour divided by 31.8 four. And that gives us a mole fraction of zero point 80 I don't know that we have the more fraction I shall let me go ahead and just move. That may put it over here is your old point It it don't know that we have the mole fraction for water. We could rearrange this aggression and look for the most of any CEO. Okay, so let's go ahead and do that. We have the mole fraction of H Door, which is joe 0.808 The moles of H 20 is given its 0.115 over 0.115 most plus two times the most of any CEO. Okay, so at this point, we have every number we need blood in. And we just need to, um, rearranged that question. So most of an A and a C o Z equals two 0.115 more divided by zero point it through a minus 0.115 moles. All of that over two. Okay, so all I did here is just rearrange this equation that we have, So that's just, um, algebraic process. So after we blood bat into the calculator, we get the most of any C l the B 0.136 months. Okay, so now that we have the most of any CL, all we need is to multiply this by the molar mass of any C l and we get the Gramps. So zero point you write that. 0.136 most times the molar mass of any CEO is 58 58 point for far, three grams sperm away. Okay, so the malls cancel, and that leaves us with grams. Where final answer is 0.795 Gramps

Let's sell for the vapor pressure of the solution. We have 165 grams of glucose C six h 12 06 Let's convert this to moles is in the molar mass. This one year olds 0.9 17 moules of the glucose and, uh, the mouse of water, we're told, is equal to 685 grabs. So let's calculate the moles of water, which would be 6 85 grams smaller, massive waters, 18 grams per mole. So 65 right about 18. 38.1 Moles of water. No, we can calculate the mole fraction of the glucose, which would be equal to 0.917 over 0.917 and 38.1. This would be equal to more fraction of 0.235 And now we can use roads law here to, um, go more fraction of the soil. Utes is equal to the sure over the Sure, and we're told that the vapour pressure is, uh, of water is 23.8 quote, substitute or values. In here we have more fraction of 0.235 and, um, P is are unknown, so this would be 23.8 millimeters I agree, minus a over 23.8 millimeters of mercury solving for P A. We find that that is equal to 23.2 millimeters of mercury, so the pressure off the solution is 23.2 millimeters of mercury.


Similar Solved Questions

4 answers
NS claplei 10 HomeworkScore:15 0/ 23 (10 complete)HW Score: 40.5896, 9.33 of 2318.2. 17Queslion Helpmobub ih denshy luncilon andam Wanahl Wilucol Ihe random variable between the expected value Umcan Anueha MedunInletval (B, 16] Fulrd Ihe Median of Ine (aridom variabl and Md Ihe probabihly IhatThe median valueTRoiindMo decimalcicesIeded !
nS claplei 10 Homework Score: 15 0/ 23 (10 complete) HW Score: 40.5896, 9.33 of 23 18.2. 17 Queslion Help mobub ih denshy luncilon andam Wanahl Wilucol Ihe random variable between the expected value Umcan Anueha Medun Inletval (B, 16] Fulrd Ihe Median of Ine (aridom variabl and Md Ihe probabihly Iha...
5 answers
(1) Learn to use MATLAB function "chiZpdf and chizcdf"(2) Generate Chi-Square distribution pdf and cdf for of v = from 1to 6.(3) Plot all pdf curves in one plot_(4) Plot all cdf curves in another plot:(5) Observe changes of the curves as V increases from 1 to 6.
(1) Learn to use MATLAB function "chiZpdf and chizcdf" (2) Generate Chi-Square distribution pdf and cdf for of v = from 1to 6. (3) Plot all pdf curves in one plot_ (4) Plot all cdf curves in another plot: (5) Observe changes of the curves as V increases from 1 to 6....
5 answers
0far-nee deatanHenn 38-bten Brnt 12738 € Ir $Aal
0far-nee deatan Henn 38-bten Brnt 12738 € Ir $ Aal...
5 answers
2 (y of light travels fromanorei medium making45 0FcaTTIAthe figure bela tSecuna MEdmneFind -ne angle pi ratractionitune sccond madlumOdidknoncroFindiretractionil the sccond made(ciFlndFhe30nmefractio ^i the seconz mediumanol
2 (y of light travels from anorei medium making 45 0 FcaTTIA the figure bela t Secuna MEdmne Find -ne angle pi ratraction itune sccond madlum Odidkn oncr oFindi retraction il the sccond made (ciFlndFhe30nm efractio ^ i the seconz medium anol...
5 answers
For the first two problemswish to approximate the integral Ls(r)ds: Cousider the numerical integration formla H(f) Wf(-o) "1 f(a)wleteShow thut 6(f) ix &Xact for all polynomials of dcgrev' Olle Iozs wich the Sallle (Wo values of uw Aual Show" that H(f) is eXict polynominl that has only odd degree for all For ptticular vale of h(f) Lect fot polyuomials of degte less (and therefore polvnomials of degree thrce less). Fiud that value of
For the first two problems wish to approximate the integral Ls(r)ds: Cousider the numerical integration formla H(f) Wf(-o) "1 f(a) wlete Show thut 6(f) ix &Xact for all polynomials of dcgrev' Olle Iozs wich the Sallle (Wo values of uw Aual Show" that H(f) is eXict polynominl that ...
5 answers
0114 ? fian' sec" (x)dx =3 (x) + 3 tan (x)+c(x)+csec J (x)(+c
0114 ? fian' sec" (x)dx = 3 (x) + 3 tan (x)+c (x)+c sec J (x) (+c...
5 answers
At time t=0s a particle is at position ro 2.3mi 1.8mj_ The particle is travelling at a speed of Iol 4.5 m along a direction that makes an angle of 0 67 degrees counterclockwise from the positive X-axis in the xy plane The particle experiences a constant acceleration of & = 1.3 mi 2.8 2]. What is the X-component of the particles velocity at time t =2.25? Answer in meters per second.Answer:
At time t=0s a particle is at position ro 2.3mi 1.8mj_ The particle is travelling at a speed of Iol 4.5 m along a direction that makes an angle of 0 67 degrees counterclockwise from the positive X-axis in the xy plane The particle experiences a constant acceleration of & = 1.3 mi 2.8 2]. What is...
5 answers
Letflx,y) = Vsx + 3y.Computefry (2,~2) O- 34O- 33O- 10-}O-101
Let flx,y) = Vsx + 3y. Computefry (2,~2) O- 34 O- 33 O- 1 0-} O-1 01...
1 answers
Find the area and centroid of the region that is bounded by the curves $y=x^{2}$ and $y=2^{x}$ for $2 \leqq x \leqq 4$.
Find the area and centroid of the region that is bounded by the curves $y=x^{2}$ and $y=2^{x}$ for $2 \leqq x \leqq 4$....
5 answers
4 (abi; 3)The general solution of J' +4y + 13y =0. isC1 ev3 , cos(x) + C2 evs , sin(x)C1 e2x cos(Vx) + C2 e2r sin( V3x)C1 e3r Cos 3(2x) + C2 ex sin(2x)C1 e-2 cos (3x) C2 e ~2r sin (3x)C1 e2x cos(3x) C2 e2x sin (3x)C1 eJr cos(x) C2 e3x sin (x
4 (abi; 3) The general solution of J' +4y + 13y =0. is C1 ev3 , cos(x) + C2 evs , sin(x) C1 e2x cos(Vx) + C2 e2r sin( V3x) C1 e3r Cos 3(2x) + C2 ex sin(2x) C1 e-2 cos (3x) C2 e ~2r sin (3x) C1 e2x cos(3x) C2 e2x sin (3x) C1 eJr cos(x) C2 e3x sin (x...
5 answers
Graph each linear function. Give the domain and range. Identify any constant functions.$$f(x)=-2 x$$
Graph each linear function. Give the domain and range. Identify any constant functions. $$f(x)=-2 x$$...
1 answers
Determine the angle $\theta$ that will eliminate the $x y$ term and write the corresponding equation without the $x y$ term. $9 x^{2}-3 \sqrt{3} x y+6 y^{2}+4 y-3=0$
determine the angle $\theta$ that will eliminate the $x y$ term and write the corresponding equation without the $x y$ term. $9 x^{2}-3 \sqrt{3} x y+6 y^{2}+4 y-3=0$...
5 answers
9) A typical soda can is essentially a cylinder and holds approximately 21.195 in' of liquid. What should be thle radius and height h of the soda can be to minimize the material needed t0 make such can? Two formulas cone handy here: Surface area of a cylinder is SA 6.28r2 6.28rh, and volume V-3.[Ar2h
9) A typical soda can is essentially a cylinder and holds approximately 21.195 in' of liquid. What should be thle radius and height h of the soda can be to minimize the material needed t0 make such can? Two formulas cone handy here: Surface area of a cylinder is SA 6.28r2 6.28rh, and volume V-3...
4 answers
Part /, Find basis for the kernel of A, matrix for the Iinear transformation; T.Part Il. Find basis for the range of A Show this part in your supporting work:(1,1 "6)[2 -3 0j40,0,0102, 3 11
Part /, Find basis for the kernel of A, matrix for the Iinear transformation; T. Part Il. Find basis for the range of A Show this part in your supporting work: (1,1 "6) [2 -3 0j 40,0,01 02, 3 11...
5 answers
Find the given limit.lim (3x + 10) Xht 6lim (3x + 10) Xt 6 (Simplify your answer )
Find the given limit. lim (3x + 10) Xht 6 lim (3x + 10) Xt 6 (Simplify your answer )...
5 answers
Use the image below for exam scoreson the math exam to find the percentage of scores with at least 73.Bar Chart of Class LimitsL34-6263/2T1-A243-92Class Lmis35935760.659
Use the image below for exam scoreson the math exam to find the percentage of scores with at least 73. Bar Chart of Class Limits L 34-62 63/2 T1-A2 43-92 Class Lmis 359 3576 0.659...
5 answers
950 878990 959 917 875 834 798 765 735 708 684 661 641 623 606 590 575 561 505 463 430 402 378 361 330 305 286 269 256754 707 666 632 602 576 553 532 514 497 482 468 456 444 396 361 335 312 294 279 254 236 220 207 196NOTE: To test Ho p = 0 against H;; 0 # 0, eject Hoif the absolute value of r is reaterthan the criticl value in the table:
950 878 990 959 917 875 834 798 765 735 708 684 661 641 623 606 590 575 561 505 463 430 402 378 361 330 305 286 269 256 754 707 666 632 602 576 553 532 514 497 482 468 456 444 396 361 335 312 294 279 254 236 220 207 196 NOTE: To test Ho p = 0 against H;; 0 # 0, eject Hoif the absolute value of r is ...

-- 0.019113--