5

7 Whak d 2 "Smflsqvz...

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7 Whak d 2 "Smflsqvz

7 Whak d 2 "Smflsqvz



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Simplify. $$ -7-2 $$

Hi. We're looking at the last blast Transform off E to the 70 times sine squared t evaluated at some point s. Now, if we could recall how multiplying something by an exponential works, it's corresponds to a shift in the lap. Last transform. So this is the same as the last last transforms of sine squared t apply it at s minus seven. First, think about how to calculate the last last transformer signs. 20. Well, if we let ff t be equal to sine squared t then F priority is going to be equal to two fine tea coasts tea which we can also right as the sign off to t this'll means that the lack last transformer F crime could be easily calculated because we know the last last transformer that triggered a metric function. It's gonna be too over s square plus four. But now he also remember that the black last ransom of a derivative is related to the lab class. Transform of the original function in particular, is equal to s time for lack last transform F minus the initial value of F zero. Fortunately, in this case, sine squared of 00 to this just disappears completely. Therefore, we obtained the lap. Last transfer of F is gonna be called to Over s aspect was full. And now this means that the last class transfer the original function we were tryingto find a lower class transformer is s minus seven times X minus seven squared plus four.

Here. I'm gonna square both numbers on 4/49 times their simple, which is 14 over three. So I can divide both these by seven and get two and seven gonna multiply across, which gets me eight over 21.

We need to simplify the following, so diagonally seven goes into 21 so we're left with one and a 32 goes into force. We're left with one and two. When we multiply across, we're left with 2/3 and that's our final answer.

Today we're going to be simplifying the expression 2/7 minus three of 14. And to start we will make both fractions of the same denominator. So you need to multiply the first one by 2/2. Two times two is four and two times seven is 14. This one stays the same 3/14. The four minus three is one and the 14 stays the same. This cannot be reduced any further. It's our answer is going to be 1/14.


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