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Homework No.8Complete the following reactions and write the name of the resulting comp ounds:~BlaTHBr (Drueance 91_poroxtdo}4-mothyi-7 pentene720 €4130,TKuno_...

Question

Homework No.8Complete the following reactions and write the name of the resulting comp ounds:~BlaTHBr (Drueance 91_poroxtdo}4-mothyi-7 pentene720 €4130,TKuno_ (20Mnm onPeroxido)~He{~NiA 720-€CIClnAu~so_Br~HBI~ih 720€~Aso.28

Homework No.8 Complete the following reactions and write the name of the resulting comp ounds: ~Bla THBr (Drueance 91_poroxtdo} 4-mothyi-7 pentene 720 € 4130, TKuno_ (20 Mnm on Peroxido) ~He{ ~NiA 720-€ CIClnAu ~so_ Br ~HBI ~ih 720€ ~Aso. 28



Answers

Complete the following equations for these reactions.

Hello fortunate identify the name of reactions well below. So in the first reaction to more of it already combined and gives it elegant and solemn. So this reaction is called adverse reaction in which we take any driving the words of the extra in that the reaction we have call miraculous is which reaction is that three Article mechanism in with your two best disease. And we will get al Qaeda elke. So it is a called me electrolysis in the city action we have our to see you like. That is also called Gilman region and it is a this reaction is goldust Cody how synthesis for a house in texas reaction and that the reaction we have acetone is reacting with that drink mercury at cl that can alert you to group into hydrocarbon. And this reaction is called as Clemmensen reduction kelly Manson production. So correct office and will give me okay.

Problem to anyone. We were asked to write the product, given the following reactions Case apart. A. We got a car, books Ilic acid and I know mean Okay, So for these types of problems, it's very important to be ableto find the function group or the part of the molecule that would be responsible for reacting. Okay, In this case, having this benzene ring right here is not really gonna affect what we're doing, at least for this specific reaction. Right? So we're concerned about having that car back cilic acid and gonna mean Okay, So whenever we have those and we reacted with heat, what's gonna happen is re or taking this, um oh h group out and we're going to replace it with an H two. Okay. And that one of those hydrogen is also gonna, um, get out and mixed with O H to make water. Okay, so Oh, try to explain that a little bit more as we go draw our product. Okay, so we're starting with just having that benzene ring. Okay, so we have this benzene ring, and it has being metal group. It has a metal group, and then we have our car book Selic Acid. Okay, Got she. And as I've mentioned that oh, age group is going to leave this molecule, and we're going to replace it with this image. Um three. Okay, so, um, instead of any three, we're gonna have any each do, because again, one of those hydrogen is going to leave an aged three and mixed with ohh to make water. Okay, but this should be there should be our final product right here. Okay. Next we got part B. And again, our goal here is to find the function group or the part of the molecule that's going to react. Okay, So, looking at the first molecule here in part B, I see a car book, selic acid, and looking at the second structure. All they see are carbons and hard agents and just one alcohol. So that alcohol No, I'm better have something to do with this reaction kick. And we're reacting that with an acid and a catalyst or an acid catalyst. So we just have about h plus from the acid written. Okay. So whenever we react a carb oxalic acid with on alcohol, we're making an Esther. Okay, so say this is our one. And it has that carb oxalic acid And say, this is our two, that alcohol again. It's just going to leave this group, and we're going to have this art too connected to that car books Ilic Acid. Okay, so then he raised what we have so far. And as you notice there are, there are 20 h, um, groups in here and one of those oxygen's And both those hydrogen czar gonna leave and make water. Okay, so let's start with just dropping this first molecule. Oh, my God. Ch three she age. And then we got that chlorine up there C h to and we got our car broke. Cilic acid. Okay, so again, I'm gonna leave that hydrogen out so we could connect this second molecule ass on Esther. Okay, So we are We are drawing this molecule backwards because the the, um, alcohol is right here. So we have ch right, and we have this metal group touch to it, and then we have ch two ch three. Okay, so there you have it. That should be our product for reaction. Be

Hello. Question is identify the products in the reaction. So first reaction. Yeah. Okay. C. S. Three he introduced CST plus at Cl and represents of peroxide but we know that but outside effect is not applicable in the presents of at sierra. It is actually given only in the presents of HBR So the l minus will get credit on that carbon which has a stable carbon. So this pipe one will break in this direction and a positive charge will come here. This positive charges on each table because of here is 300 five alpha hydrogen and at this carbon there is only four L 5 to 200 to four night. So we will get yeah. CS tree here will come see it. CS enthusiastic thank in the second option. Second part we have conjugated die in this one and this one so what will happen I stopped this pipeline will break and car book then we'll get formed let's start to work again this one and this car back then is in contribution with that double one. So development will come here. Development and positive charge. Welcome here and now we are minus will attack on this car book attack and we will get this C. S. Street and you haven't come here. Okay, thank you.

This problem is asking us to show the products of these two reactions. So in part a, our nuclear file, the best nuclear bell that we have in this reaction is the amine and the best left. Your file is the anhydride. So our electoral, our nuclear file, will come in and attack our Electra file. And whenever we attacked a carbon carbon, you push pylons up onto the O. And that gives us an intermediate that looks like this will have our siege. Three. This will be up here, um, and then the rest of this compound, and then we'll have our n attach, which is now positive with the rest of that compound over there. So our end is positive because we've added a bomb to it. Um and but But it doesn't need to be right. It's gonna memory finished your problem. We don't want the end to be positive. We want it to be neutral, so we're gonna instead take that positive charge and give it to our leaving. Groups are leaving. Group is gonna be this whole side of the anhydride, and that is going to come in and take one of the H is off of this and give those electrons back to it so that we have a permeated leaving group. It's per nated. Now, um, with the rest of that compound on there, and then we have our neutral in with the rest of its compound, and now we can finish off the reaction mechanisms. And now this, uh, these electrons can come back down and reform that double bond and we can kick off our leaving groups. So the final product for this one as this fool compound with now and h um, connected to that Carbonneau carbon that now has reformed that's double bond. And it has that ch three still on it. And the other half that we made Waas now a car boxlike passage of the other side of it and hard drive. So there is part a and in part B, we have a very similar reaction. So, um, this time we just haven't secondary mean but the same anhydride. So again, this is going to come in and attack here. Push these up, Will do that Proton transfer that we talked about appear where the end will give the proton away to the O. I think it off, bear, Make it neutral. These will come back down and we'll kick off our leaving group. So our end product here will be en It's neutral and then we have our carb oxalic acid from the other side of the in hundreds.


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