5

Part AWhal the tension T in the string when the ball tully submorged bui nat louching tho boltom; as shown the figure? Express your answer In termg of any or all ot...

Question

Part AWhal the tension T in the string when the ball tully submorged bui nat louching tho boltom; as shown the figure? Express your answer In termg of any or all ot tha given quantities and the magnitude of tha free-fall acceleratlon: View Avallable Hint(s)AEdSubmitProvique Anawene

Part A Whal the tension T in the string when the ball tully submorged bui nat louching tho boltom; as shown the figure? Express your answer In termg of any or all ot tha given quantities and the magnitude of tha free-fall acceleratlon: View Avallable Hint(s) AEd Submit Provique Anawene



Answers

A $500 \mathrm{g}$ ball moves in a vertical circle on a $102-\mathrm{cm}$ -long string. If the speed at the top is $4.0 \mathrm{m} / \mathrm{s}$, then the speed at the bottom will be $7.5 \mathrm{m} / \mathrm{s} .$ (You'll learn how to show this in Chapter $10 .$ ) a. What is the gravitational force acting on the ball? b. What is the tension in the string when the ball is at the top? c. What is the tension in the string when the ball is at the bottom?

Over here is here is a born and the body is doing emotion like this. So the tension is putting it up. There is sweat mg down Lord and there is the centrifugal force or central centrifugal force and three squared over R outside. And here is attention So the angle is given Tetteh. So we have the scientist is the Vatican Some point of tension on the horizontal component of attention is the scientists. So we would have Do you sign Theta equals m v squared over r and d close. I integer it was MGI. We need to find the tension and the speed of the ball. So if we divide one by the other we find that January of theta equals whisper over RG So the speed of the ball comes out to be r d Daniel Dictator swelled of bad It was zero going eight meter string times 9.8 meters four seconds Where time standard off For immediately weird off that it was 14 in 398 or 1.4 meters per second. Also, we can find the tension in the string from here p equals m g over cause I in terra massive. The ball is 1.4 kilogram, 1.45 kilogram times 9.8 divided by co sign off 14 degree equals 13 Foreign 78 mutant Is the tension in the stream now?

Yeah, the party, the free border diagram of the fall. The force is sitting on the volumes, the weight which is acting downwards that is F. G. Has a magnitude of energy. The tension force which is acting along the string that is still at an angle theater with for party. The centripetal force which is in the our central playing. The centripetal fools. The centripetal fools have C is provided by the horizontal component of the attention. That is the sign theater. So the centripetal force fc is for a little bite. The horizontal component, the attention. How about C. For vertical equilibrium since the world is retreating in the house, entertain. So it is in vertical equilibrium. So we can say the submission of all forces along the right direction will be sealed. And from this de course theater is equivalent to the weight of the world. That is N. G and G is equivalent to MG upon cost theater american substitute the values the tension of the strings, the mass of the waters. Uh, mm 7.2 kilograms into 9.81 m or second square and upon because of the angle data is 45°.. So we find attention is 2.77 Newton and the horizontal component that is The T Science Theatre is secure and Douglas interpreted four status. Um, we square born the radius and radius is 10 scientific to and from this, the university, uh, sorry, when they need speed, other success stories, mm square root dolls be upon them? Sine squared peter. Okay, now we can substitute the values. So that Speed is attention is 2.77 nutrients Upon the masses. 0.2 kilograms in the same square of 45 degrees. And the speed is 3.72 m for a second for party, the attention is 2.77

We have problem # 52. Indeed, it is being given. There There is a mass of a ball or anything. Yes, mass of a ball is 0.200 kg. This is being attacked with their strength which is massless. Let us say the length of the string it is given. So capital L. Is given as one m. So this is one m is being given and is undergoing a circular motion. So this isn't circular motion. Okay, So we have to find and it is in a horizontal plane. It is uh gentle plan means that this motion is circular and in horizontal plane like this. Okay, ah like this. And we have been given it horizontal view. Also in the question this is M this is a string and this is L. This is equal to one m. Okay, so we have to find certain things. Free body diagram of the ball. So we have to find, we have to just draw the free body diagram of the ball. So let us first ascertain the forces detecting on the ball at a particular instant. So at this instant if you draw the ball separately, so free body diagram will be trying just separating out the ball. So wait that is MG will always be acting vertically downward and this attention in the string. So attention will be like this tension in the string and this angle is theater. Okay so this angle is peter. Okay so these are the two for selecting. Now if we just for the sake of simplicity and for the applying Newton's law, if we could just ah resolve this false tension in vertical and horizontal directions that if we assume this to be Y. Direction. So we could just result pension like dy the detention in X. Y. Axis, attention in the direction of Y. Axis and tension in the direction of X. Success. This is X. Okay. Now if this english theater so this single has to be theater. So by using trigonometry we can say dy equal to t cause theater and dx equal to design data just by using trigonometry. Now we have the forces in two directions that is in X. Direction and in what direction? So this is the free body diagram. An answer of of part A. Okay now we have to find we have B which force plays the role of centripetal force. Okay so now if this is B. So we know that yeah it is in circular motion in horizontal uh circle. So there is only one force which is towards the center that is the X. Component of this tension. So centripetal force, centripetal force will be equal to will be equal to. And let us CFC the X. That is forcing next direction. So we will be having d scientific to we will be just playing in value afterwards. Okay part C. What should be a piece of the mass? Okay now to get the speed of the mass we have to just equipped for everything. So let us I use Newton's law for X. And Y directions separately. So in Y direction, if we find expression in Y direction it will be some of the forces in Y direction divided by M. Now some of the forces in Y direction. So there are two only two forces T. Y and M. G. And T. Y. S. Tva is tension scientist to sorry cause theater which we have already found the cost rita divided by and minus MG. Because this is T. Y. Is in vertically upward direction in MG. And vertically downwards for vertical downward will be taken as negative. But um now we can see that the movement is only horizontally, no ball is not going in the vertical direction, so they will be zero. So zero will be the cost A to minus MG by M. So by multiplying both sides by M. Will be getting he caused it equal to MG. So we will be having equal to MG by cause it. So before using before uh solving, see we have to solve party first to get the value of tension. Okay, so you can plug in the values to get attention. So we have Value of ma 0.200 Kg, 0.200 Kg. And this is 9.8 m per second squared G. Which is explicitly to gravity. And because uh three days, 50 days, 45 degree. So let us right 45 degrees. Mhm .2 in 2 9.8, Divide by cost 45°.. That is 2.77. So we have plenty approximately two point 77 newtons. Okay, this is the answer for party. And when we have found an answer for part day, so let us plug in the value of tension here to get answer for part A. B. Saying 45 degrees. So in two signs 45°, That is 1.96. One of my clients. 96 Newton. This is the subject matter course. Okay, now, but see, but I think we have to find the speed. So we know that you know that speed are we can say that exhalation in after. That will be writing for the speed exploration in horizontal direction. It is A. X. Equal to some of masses in horizontal direction divided by some of the forces in horizontal direction divided by um So there is only one force in horizontal direction which is our centripetal force And which is 1.96 Newton. So let us right 1.96 divided by 0.200 Newton or Kg. And in horizontal direction we have formula for centripetal force. That is centripetal force. I am the Squire by our. Okay so fc by M. Which will be equal to the exhalation in a centripetal force, centripetal acceleration or exhibition in X direction. We're squired by our so let us plug in here. We are required by our The Squire by are equal to 1.96 x 0.200 Newton per kg. So b squared will be equal to 1.96 x 0.200 Newton by Casey. Into our where r is the radius of this circle? Okay So r. Is the radius of this circle? Oh this was our. Sorry. Yeah. Okay, now Radius of the circle. Since this is 90 degree. This release of the circle so we can use ah you're gonna matter here. Scientist to scientist in particular that are or oppose it are buy happiness. Scientists equal to our by one. Scientist to equal to are by L. LH one. So I will be equal to L. Scientist to L. H. One and sign 45 degrees. Have been big pimples simply fine 45 degrees. And whatever it comes it will become in meters. So we it's quite equal to 1.96 By 0.200 Newton but Katie into signed peter. So I was saying for the five between and this will be in Me too. This will be put to one point incentivized by .2 In two signs 45°, 36.92 explain. 9296 for six. Me Too Square for a second square. So 26.929646 meter square Pushkin square 22.60 velocity will be 2.62 m/s. Oh, we have all the solutions. Thank you.

Mm. Hi. So for this question we have that Ebola is attached to a string And wound around in a circle of an angle of 30° and I want to find the speed of the ball in a circle apart. So what's the we have three forces that we have detention for us. You have this force which is horizontal central chance better of course. And then we have to wait she's going down sure detention is balancing these two forces right here and right so the vertical component of detention it's going to be the weight and there is undocumented attention of it is so result in detention and she is horizontal. This would be F. G. Sign 30 and that would be cool to send entrepreneur force which is envy squid. Uh huh. Then for the vertical Yeah there's going to be F. G. Because 30 and there's a record MG which is the weight so we can make a teacher director from line both of these ft Nicole two MV 2. What about our sign 30 and the F. T. Is called MG. Or of course 30. Now are we just just circle apart. But what we're given is the land Which is 24 cm So resolving this with 24 sign 30 and this is in centimeters so from here now we can equate this to tension forces. M. V. Squared over R. Sign dirty culture M. G. Of course 30. Our councils out here. The tv is a cultured script of her key SAn Turkey or cost 30. So now we have our ethical to 24-730 substitution disappear And converting this to me that would weigh about 100 years with your .24 SAm Touchy Thomas Sniper. It's one times, sorry dad. She divided by course. Dirty square the whole that there's a culture Approximately equal to zero point it to me. Test my second, but there is a velocity.


Similar Solved Questions

5 answers
5 0 041 1 aubaoth invorko 2 dopiot ] twcy 3 IF functionx 233 dofinins 4 3 eaoh codomaina 81FimureCHa
5 0 041 1 aubaoth invorko 2 dopiot ] twcy 3 IF functionx 233 dofinins 4 3 eaoh codomaina 8 1 Fimure CHa...
5 answers
10. Calculate Ta, for vaporization of water, HzO(l) H-Olg) AH = 40.0 kJ; temperature range is the vaporization spontaneous?118.9 J/Kwhat
10. Calculate Ta, for vaporization of water, HzO(l) H-Olg) AH = 40.0 kJ; temperature range is the vaporization spontaneous? 118.9 J/K what...
5 answers
Integrate_cos (8x) 17sin (8x) dxcos (Bx) e 17sin (Ex) dx = D+c
Integrate_ cos (8x) 17sin (8x) dx cos (Bx) e 17sin (Ex) dx = D+c...
3 answers
Probkn 3: ApprOximate the following integrals using Trapezoid rule: Find DOu_ tor the eTTOT ULSiLg the erTOr Honuua compare this the actual cmuT chc CaSeFn /K" 2e"'drFrabkmRepeat Froblem IsiI Simpson
Probkn 3: ApprOximate the following integrals using Trapezoid rule: Find DOu_ tor the eTTOT ULSiLg the erTOr Honuua compare this the actual cmuT chc CaSe Fn / K" 2e"'dr Frabkm Repeat Froblem IsiI Simpson...
5 answers
Sketch the graph of the curve and show your complete analysis (identify all necessary parameters}V =-2-3 Cos 2t2
Sketch the graph of the curve and show your complete analysis (identify all necessary parameters} V =-2-3 Cos 2t2...
5 answers
Question 7 (1 point) A thylakoid membrane is damaged and now leaky to hydrogen ions. Th have the most direct effect on which of the following processes?1) the synthesis of ATP2) the splitting of waterthe absorption of light energy by chlorophyllthe flow of electrons from photosystem Il to photosystem /5) the reduction of NADP_
Question 7 (1 point) A thylakoid membrane is damaged and now leaky to hydrogen ions. Th have the most direct effect on which of the following processes? 1) the synthesis of ATP 2) the splitting of water the absorption of light energy by chlorophyll the flow of electrons from photosystem Il to photos...
5 answers
Select the incorrect match.(a) Morels and truffles- Phycomycetes(b) Puff balls and toad stools - Basidiomycetes(c) Early blight of potato Alfernaria solanj(d) Late blight of potato- Phytophthora inlestan
Select the incorrect match. (a) Morels and truffles- Phycomycetes (b) Puff balls and toad stools - Basidiomycetes (c) Early blight of potato Alfernaria solanj (d) Late blight of potato - Phytophthora inlestan...
5 answers
How do the different ages of disk stars and halo stars support the idea that our galaxy formed from the gravitational collapse of a protogalactic cloud?
How do the different ages of disk stars and halo stars support the idea that our galaxy formed from the gravitational collapse of a protogalactic cloud?...
1 answers
Two particles of mass $m_{1}=15 \mathrm{kg}$ and $m_{2}=25 \mathrm{kg}$ are connected by a massless rod of length $1.2 \mathrm{m}$ Find the moment of inertia of this system for rotations about the following pivot points: a. the center of the rod, b. the end at $m_{1}$, c. the end at $m_{2},$ and d. the center of mass. Assume the rotation axis is perpendicular to the rod.
Two particles of mass $m_{1}=15 \mathrm{kg}$ and $m_{2}=25 \mathrm{kg}$ are connected by a massless rod of length $1.2 \mathrm{m}$ Find the moment of inertia of this system for rotations about the following pivot points: a. the center of the rod, b. the end at $m_{1}$, c. the end at $m_{2},$ and d. ...
5 answers
For f(x) =x4 12x3 + 3 find the following: (A) f' (x) (B) The slope of the graph of f atx =3 (C) The equation of the tangent line at x = 3 (D) The value(s) of x where the tangent line is horizontal(A) f' (x) = 4x3 36x2(B) At x = 3, the slope of the graph of f is 2161(C) Atx = 3, the equation of the tangent line is y(D) The tangent line is horizontal at x (Use a comma to separate answers as needed )
For f(x) =x4 12x3 + 3 find the following: (A) f' (x) (B) The slope of the graph of f atx =3 (C) The equation of the tangent line at x = 3 (D) The value(s) of x where the tangent line is horizontal (A) f' (x) = 4x3 36x2 (B) At x = 3, the slope of the graph of f is 2161 (C) Atx = 3, the equa...
5 answers
Tell me if you would decide to “reject” or “not to reject” thenull hypothesis for each of the following two scenarios:Scenario # 1 : H0 : u = 0 and Ha : u > 3 given: alpha ( α ) =0.05 and p = 0.03 Scenario # 2 H0 : p ≥ 0.25 and Ha : p < 0.25given: alpha ( α ) = 0.025 and p = 0.17
Tell me if you would decide to “reject” or “not to reject” the null hypothesis for each of the following two scenarios: Scenario # 1 : H0 : u = 0 and Ha : u > 3 given: alpha ( α ) = 0.05 and p = 0.03 Scenario # 2 H0 : p ≥ 0.25 and Ha : p < 0.25 given: alpha ( ...
5 answers
QUESTION2 Let G =< 215, +> and H =< [3] > is a subgroup of G. Find the number of distinct coset using Lagrange Theorem. List out all distinct left coset of Hin G.[SMARKS]
QUESTION2 Let G =< 215, +> and H =< [3] > is a subgroup of G. Find the number of distinct coset using Lagrange Theorem. List out all distinct left coset of Hin G. [SMARKS]...
5 answers
CALCULATE THE CONSTANT N FOR NACL, GIVEN THAT THE MEASUREDBINDING ENERGY FOR THIS CRYSTAL IS 7.95 EV/MOLECULE ANDcoffecint = 1.75.
CALCULATE THE CONSTANT N FOR NACL, GIVEN THAT THE MEASURED BINDING ENERGY FOR THIS CRYSTAL IS 7.95 EV/MOLECULE AND coffecint = 1.75....
5 answers
Three reslstors are connected as shown In the figure. The 2.0 potential difference between points A and B Is 26 V3.0Relerence Rel 20-3What is the equivalent resistance between Ihe points A and B?Select one: a.5.10 b. 9.0 0 c.4.30 d.3.806.8 0
Three reslstors are connected as shown In the figure. The 2.0 potential difference between points A and B Is 26 V 3.0 Relerence Rel 20-3 What is the equivalent resistance between Ihe points A and B? Select one: a.5.10 b. 9.0 0 c.4.30 d.3.80 6.8 0...
5 answers
Find three solutions toy 5X Use x=0,x = 5, and x = 20,Complete the table0520
Find three solutions toy 5X Use x=0,x = 5, and x = 20, Complete the table 0 5 20...
5 answers
1 arkedout =point be the intersection 1 passes between through ahe point (4,dned @ perpendicular t0 the plane
1 arkedout = point be the intersection 1 passes between through ahe point (4, dned @ perpendicular t0 the plane...
5 answers
[-/6 Points]DETAILSLARSON8 13.1.006.Find and simpllfy the function values(x Y) =(a) f(0, 0)(b) f0, 1)(c) ((2, 3)(d) f(1, Y)(e) f(x, 0)() ", 1)
[-/6 Points] DETAILS LARSON8 13.1.006. Find and simpllfy the function values (x Y) = (a) f(0, 0) (b) f0, 1) (c) ((2, 3) (d) f(1, Y) (e) f(x, 0) () ", 1)...

-- 0.019247--