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Part Awire of length 2.0 m and diameter 2 Inm has resistance of 0.50 n What Is the resistivity of the material used t0 make the wire?2x10-6 fmn1,5*10 Om8.8x10 - Qm5...

Question

Part Awire of length 2.0 m and diameter 2 Inm has resistance of 0.50 n What Is the resistivity of the material used t0 make the wire?2x10-6 fmn1,5*10 Om8.8x10 - Qm5.9x10-5 fltnt2.8*10- IlmSubmitBequeaLAnaWoL

Part A wire of length 2.0 m and diameter 2 Inm has resistance of 0.50 n What Is the resistivity of the material used t0 make the wire? 2x10-6 fmn 1,5*10 Om 8.8x10 - Qm 5.9x10-5 fltnt 2.8*10- Ilm Submit BequeaLAnaWoL



Answers

What is the resistivity of a wire of 1.0 $\mathrm{mm}$ diameter, 2.0 $\mathrm{m}$ length, and 50 $\mathrm{m} \Omega$ resistance?

Hi given problem diameter of the conducting wire is given as 1.0 millimeter. So its radius of cross section will be half of the diameter means 1.0 by two millimeter. Which can also be it in as 0.50 millimeter. Or we can say this is 0.50 into 10 minus the need to. It's Lynn he's given us L is equal to ooh, wine Sposito meter. And resistance is 50.0 millie on which can also be written as 50 into 10 dish par minus we mm. Or using expression for resistance in terms of its resistive. Itty R. Is equal to rho into L by a. There is the area of pro section of the wire which is written as by R squared. So putting the values here for resistance, this is 50 into 10 par minus three. Home is equal to resist a bit in which we have to find multiplied by the land, which is 2.0 m length of the wire, invited by 3.14 value of pi, and he will 0.5 zero into parenthesis and reach the power minus three meter to the whole square. So rearranging the values we get, there's this treaty rule is equal to 50 into 10 days ar minus three on multiplied by 3.1 fold into 0.5 into tennis part minus three square centimetres squared, divided by no 0.0 m, canceling one m. And this resistive itty here comes out to be 19.6 to 5 into endless par minus nine home centimetre. Or we can say this is row is equal to one point 96 into 10 dish par minus eight home meter, which is the answer for the given problem here. Thank you.

So in this of them were given The length of fire is a well deserved .60 mutation. And the directory of files you got to the .10 centimetre. We have to find resistance of why which is middle of cooper for that purpose. First to find the radius which is going to half of time out there. We should be called Entrepreneur five situated or We can write this 0.05 multi batteries for -2 material. We can find idea of course. Section of where by using for the tir square, The pie has got 3.14 particular by our square mean 0.05 multiplied by Transport -2 m square. When we saw this, you get area is equal to 7.8. multiplied by 10 for -7. We test square and we know from the table that the city of cooper is going to 1.70 multi to transform -8 oh amateur. So we can find, for instance, by using for Gladys Mexico too, the state into land divided by area. So we will subside your visit to the city resident. He's got 1.70 with people. Our transport -8. Well, how many fish When malevolent is their .60 m divided by idea is equal to 7.8 multiple. Our terrorist for -7. We did square when we saw this week, for instance, of the copper wire is equal to 1.3 multiplied by tourist for minus to a home. Which is the answer to this question. Thank you for watching.

All right, so in this problem Ah, So for the copper wire, we already know that the lengths of the copper wire is, uh ah equal 20 meters into the diameter de equal 2.5 free may bitters And you can look up the value of the resistive ity for copper on the internet All in the sing the textbook and the very iPhone Ihsaa row equal. Ah, 1.75 times 10 to the negative Eighth er, holmes Time meter. Okay. And the you can utilize the relation between the resistance and the resist of resistive ity. So are equal road times a ll over s. So how is the lens of off the copper wire and essays the cross section so you can re express the s s role? Um, hi times, half d swit. Okay. And you need to plug in the values t this expression. And he would say the value is 1.16 homes right?

Hi. In a given problem, the first part of the problem length of the copper wire is given as L is equal to 1.0 m. Its diameter of cross section is 0.50 millimeter, so radius of its cross section will be R is equal to half of the diameter means 0.50 by two millimeters or and say this is 0.25 millimeters, or 0.25 into 10 days. Par minus street meter. Yeah, resistive itty of copper is raw is equal to 1.72 into 10. Dish par minus eight in 2 m. Hence, resistance of the core provider will be given as roll into l by a a is the area of cross sections. It becomes thrown into l by pi r squared So plugging in or non values for road, this is 1.72 into 10. Disbarment escaped into for land. This is 1.0 m divided by 3.144 by into our, which is 0.25 into 10. Dish par minus three Swear so this answer finally comes out to be 8.76 into 10 for minus to whom? This is the answer for the first part of the problem. The resistance of the given copper wire. No, in the second part of the problem, length off the iron wire is given as L is equal to 10 centimeter. Or we can say this is 0.1 m. Yeah, its area of cross section will become as its area of cross section is square shape so that we be given SK is equal to 1.0 millimeter multiplied by 1.0 millimeters, which comes out to be tender HR minus 3 m into 10 for minus 3 m, which becomes standards for minus 6 m square. Resistive itty of iron is wrote a sequel to 9.71 into 10 par, minus eight home centimeter. So the resistance of this wire made up of fire and will be given by roll into L by a again so plugging in on values or road. This is 9.71 into 10 days, par minus eight. Home into meter for length. This is 0.1 m divided by area, which is enriched par minus 6 m. Require hands and Finally, this answer here comes out to be Are is equal to 9.71 into 10 Dish, part minus tree. Oh, which is the answer for the second part of the problem. Thank you.


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