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Docs thc amount of ndiation (pm) incTcasc or dccTcasc as thc distancc bctwccn thc sourcc and thc scnsor inccases} Explain.Docathc amount of rdiation ((m) incTcasc O...

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Docs thc amount of ndiation (pm) incTcasc or dccTcasc as thc distancc bctwccn thc sourcc and thc scnsor inccases} Explain.Docathc amount of rdiation ((m) incTcasc Or dccrcasc = thc thickncss of thc shielding incrcascs (whilkc tkc distancc bctwccn thc toun c and thc scnsor Ga thc samc)? Explin.Dece tbe amount of rdiation (cm) ~ change ' whcn sshickling made from differcnt material js uscd? Exphin

Docs thc amount of ndiation (pm) incTcasc or dccTcasc as thc distancc bctwccn thc sourcc and thc scnsor inccases} Explain. Docathc amount of rdiation ((m) incTcasc Or dccrcasc = thc thickncss of thc shielding incrcascs (whilkc tkc distancc bctwccn thc toun c and thc scnsor Ga thc samc)? Explin. Dece tbe amount of rdiation (cm) ~ change ' whcn sshickling made from differcnt material js uscd? Exphin



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At least $25 \mu \mathrm{g}$ of tetrahydrocannabinol $(\mathrm{THC}),$ the active ingredient in marijuana, is required to produce intoxication. The molecular formula of $\mathrm{THC}$ is $\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}$. How many moles of THC does this 25 \mug represent? How many molecules? (b) Caffeine, a stimulant found in coffee, contains $49.5 \% \mathrm{C}$, $5.15 \% \mathrm{H}, 28.9 \% \mathrm{~N},$ and $16.5 \% \mathrm{O}$ by mass and has a molar mass of $195 \mathrm{~g} / \mathrm{mol}$. (c) Monosodium glutamate (MSG), a flavor enhancer in certain foods, contains $35.51 \% \mathrm{C}, 4.77 \% \mathrm{H}, 37.85 \% \mathrm{O},$ $8.29 \% \mathrm{~N},$ and $13.60 \% \mathrm{Na},$ and has a molar mass of $169 \mathrm{~g} / \mathrm{mol}$

So in this problem, we're given that we have a twenty five microgram off Tetra Hydro Can a banal are being C, which is an active ingredient in marijuana, and this is recorded produce intoxication. So this is the mass ofthe DSC, which is required to produce intoxication, and the molecule or formal off its has given us citrine too on his thirty or two. In first part of the question, you have to find out how many malls off T. H. C does this trait of five microgram represent and then we have to find out how many molecules subject etc. Does. This, Trent, if I'm acronym represents so what we have to do first is simply since we have to find out the number of malls off this mass off, etc. First you have to find out the Moler, massive t etc. That means the molar misses the mass contained in one mall. That means from there we can find out how many months is contained in strange if I microgram mess. So from this formula, we can find out on the Moler mass off the sea. My children, since we have carbon carbon, has a more mass of twelve point Oh Won, and we have twenty one carbon here when multiplied by twenty one. Then we have Metro's on which has more elements of one point or eat, and we have her t I'd risen sun multiplied by eight thirty, and then we have to walk season. That means sixteen is the monuments of oxygen and we have to oxygen multiplied by two. And this will give us a value off three one four point four five I, um So this is the two and four point four five gram per mall, and this is the molar mass off. Let's see, That means one more lofty is he will contain through one four point four five gram and then so we can write three one four point four five gram is contained in one multi it. See, that means twenty five microgram, or twenty five times ten to the minus six gram is contained in, um, twenty five times ten to the four minus six over two on four point four five Graham this a gram per mole and it will give us value off seven point nine five times intended to par minus eight more so This is the number of malls that going to find microgram off dates represent. And then we have to find out how many molecules is contained in twenty five macron. And since we have calculated the number of morals, so twenty five microgram TOC, then we know that one mole off any substance contains six point or co times ten to the twenty three molecules. That means from there we can find out how many molecules is contending this much more are twenty five micrograms of hearsay, so one more it's sea contains six point or two times ten to the port twenty three molecules, therefore seven point nine five times during the one minus eight. Here's the contents. Six point oto time stint Report twenty three Time's thiss and this will give us value off for planned seven nine I'm standing. There were sixteen molecules, so this is the number of molecules containing twenty five microgram off, etc.

Hi everyone. So in this question they asked the electronic compilation of four elements are given as and uh one is managed to reassure people. The second managed to two years to do before 30s managed to do is to to be 3420s. When I should we ask you to pay six years 23 people? Which of the following enrichment gives the character order in terms of increasing electronic equity of lemons. So option she is correct. Oh son. Yeah. See is correct. Mhm correct. Alder off. Okay. Increasing electronic entity of the lemon teas increasing. Okay. Mhm. Electronica activity. Mm. Mhm. Yeah. Of the element ease. Mm As follows. Yeah. One X two creation To be 6 3 ash too three p 1 we can say at live India smaller than Okay. One is to to rest. Oh yeah to be three that is nitrogen which is smaller than nice to us to be for decades oxygen. Mhm Yeah, it is smaller than 1" to 3 years to to be for you that is floating chlorine. Is the lament having a guest electronic. It'd in the periodic table Florrie is the Lemon Read I. Yeste 11 12 negativity in the periodic table and erotic devil. Thanks loved

This is the answer to Chapter three. Problem number 45 from the Smith Organic Chemistry textbook. Ah, And in this problem, we're asked to compare tetrahydrocannabinol, which is the active ingredient in marijuana, um, to ethanol, which is the alcohol. That's, uh, you know, in beer, wine and hard liquor. Um, and so were asked, um, why, um, drug screenings are able to detect the presence of T h c, which is tetrahydrocannabinol. Ah, but not ethanol. Weeks after these substances have been introduced into the body. Um, okay. And so the answer here, um, is, uh, because of polarity. Eso ethanol has two carbons. Um, and one alcohol. One. Ohh. And so ethanol is very water soluble. Um, very water soluble. Ah, and so it is. It is rapidly passed into the urine, rapidly enters urine. Ah, and is rapidly urinated out. So, uh, several hours after a person stops consuming ethanol, they've urinated out all of the ethanol, and it's metabolites that were in their body. Um, and that again is because ethanol is so water soluble. So when we look at th see, what we see is that we have une ether here. Ah, and we have one alcohol here. Let me just make sure that I did redraw that correctly. Okay, Um and so there are only really two polar groups in this, uh, somewhat large T h c molecule. And so, based on the water soluble ity rules that we learned in this chapter, T h C is not water soluble. And so what ends up happening is it is soluble in organic solvents, Um, and so T h c enters the body and it ends up stored in fatty tissue. Um, because fatty tissue lipids, lipids, air able to sort of act as a solvent here and and dissolve the T h C. So T c is stored in fat. Ah, and then very slowly excreted over a period of weeks. And so that's why th see is detectable for up to 30 days after use. Whereas Effie no, um, you know, at 30 hours, you probably can't detect that someone. Someone used it 30 hours ago. This is also the reason that, um, tht extracts our oil based and not water based because th c is not water soluble. Um and so, uh, that's that's the way to approach this problem. We just need to consider soluble ity and then realize that polar ethanol is rapidly excreted in the urine, whereas very non polar water insoluble T C eyes stored in fat and takes much longer to slowly exit the body a little at a time. Ah, and so that's the answer to Chapter three. Problem number 45.

This question now you just It says if one off the test subjects is randomly selected, find the probability that the subject did not use marijuana. Find the probability of the subject that he did not use marijuana. These are the total subjects who did not actually use marijuana. These are truly negative. These are the ones who are negative and who have also tested negative. But these are the ones who are negative but who have falsely been tested positive. So 24 plus 1 54 is 1 78 1 78 by 300. This is the probability that we want. And do we think the result affect the general population rate off subjects who do not use marijuana? I think the result is somewhat low for people who do not use marijuana. By the way, this value turns out to be 0.59 something zero point Faith Night. And this is my answer


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