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Question 65 ptsConsider the following reaction:CINaOMeOMeWhat is the full name of the organohalide reagent used? What reaction is occurring here? Describe how you w...

Question

Question 65 ptsConsider the following reaction:CINaOMeOMeWhat is the full name of the organohalide reagent used? What reaction is occurring here? Describe how you would draw curly arrows to explain this reaction (specifying which atom or bond the arrow will start and end): How does your mechanism explain the stereochemical outcome of this reaction?

Question 6 5 pts Consider the following reaction: CI NaOMe OMe What is the full name of the organohalide reagent used? What reaction is occurring here? Describe how you would draw curly arrows to explain this reaction (specifying which atom or bond the arrow will start and end): How does your mechanism explain the stereochemical outcome of this reaction?



Answers

Identify the electrophile and the nucleophile in each of the following reaction steps and then draw curved arrows to illustrate the bond-making and bond-breaking processes.

We start a reaction, Wes, these two reactant, we lose our double bond. Wind up with a carbo cat Ion waas, a water molecule. These electrons will moved to bond with our original molecule. And our product is three metal. Butin to all this is our minor product, our major product. This formed in a similar process with our water molecule attaching Efty Carbo Cat ion That positive hydrogen will find our water molecule. And we will wind up with to mess Aled two beautiful, which is our major product.

In this question. We were asked to identify the Electra file and nuclear file in each step and then draw curved arrows to show how the reaction is happening. So in the 1st 1 are Electra file is the thing that's being attacked. So that is going to be the carbon here. Um, and then the nuclear file is the thing that's attacking, which will be the bro mean? So if we draw a curved arrows to show what's happening here, roaming will come in and attack from the opposite side system on carbon. On the opposite side of that, our, um, transitions are intermediate is on because the pyramid Intermediate that we have with the bro mean is too big to allows coming from the same side. So it will come in from the opposite side, and it will tack you more substitute carbon, and then this will push off. Um, and we'll end up with that other bro Ming on the top. Um, so then, for the 2nd 1 our nuclear file is the thing that's attacking. So that's going to be the NH two. And our laughter file is what's being attacked. That will be the hydrogen on this all kind. So we draw those curved arrows again. The any issue will come in and grab the hydrogen. And, um, the electrons in this bond will go on to be carbon to make that lone pair. That makes it a carbon Ryan. And in the 3rd 1 um, again, our nuclear file is with doing the attacking. So that will be this carbon nine over here and our electric files. What's being attacked? That will be the carbon on the ethyl bromide. And if we draw those arrows are nuclear ill will come in and attack our Electra file. And then we will push this broening off as a leaving group and give it that well, in parable electrons to make it negative.

Mhm. See this? Mhm See? Yeah, you're Yeah. Mhm, Yeah. Mhm. Yeah, yeah, yeah. Mhm. You do? Yes. Mhm.

Whereas to show the reaction mechanism between three methyl butin and sulfuric acid and water 2123 and with water. So this is known as the hydration reaction. The first step is for the are keen to grab a hydrogen from sulfuric acid. Electrons flow back to the oxygen. Yes, to have a secondary carbon cat, I'm But we notice this carbon is tertiary and tertiary carbon cata tertiary carbons are more stable at secondary because the methyl group acts as an electron donating group to help stabilize the positive charge. So therefore we're gonna have a hydride shift. It's hydrogen goes over here and the carbon cat angers the tertiary carbon. The next step is for water to attack it to this. The oxygen now is a positive charge because it donated a pair of electrons, they were negative and the final step is for the acid that lost the purse on. They lost the parts on the first step to take it back. In this case from the water. Yeah, sweet. How the structure two hydroxy Or to Bethel too beautiful to the o l d n a pause, even alcohol


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