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Complete the following reaction by adding the missing reagentsOHCHaOHCH3CH3...

Question

Complete the following reaction by adding the missing reagentsOHCHaOHCH3CH3

Complete the following reaction by adding the missing reagents OH CHa OH CH3 CH3



Answers

What are the products of this alkene addition reaction? $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{Cl}_{2} \longrightarrow$ $\mathrm{CH}_{3}$

Okay, so let's take a look at what happens when we take a compound. In this case, we're gonna take a look at to beauty mean And what happens when we try to react? This compound with a variety of couple of a reactant on here. The first reactant we're gonna use is B R. Two when we react, or Al cane with B R. Two. What we end up with is one grooming attached toe, one carbon and the other bro mean attached to the other carpet. We need a gained nor lost any carbons or hydrogen. Now, let's take the same starting material. But in this case, we're going to add each to with palladium or platinum. And this case were using platinum, which is P. T. In this particular case, this is a case where we're adding in high Trojans. So instead of adding in bro means like we did for the previous one, we're now actually going in and forming just these new bones with arc hydrogen. Because of this, what we're gonna see is we're gonna form an Al cane as our final product in the very last example we're going to look at is what happens when we react are all keen. With some 02 this is gonna turn into a combustion reaction. The products that we would form here are going to be CO two plus water. Now. In this particular case, we need to make sure that we have a balanced chemical reaction in our original compound. We know that we have four Karpin's and we have a total of eight hydrogen. And because of law, massive conservation, we cannot lose any carbons for hydrogen in the reaction. Therefore, the coefficients we must see in front of the carbon dioxide is going to be four because we need to make sure that we have four carbon still present. The coefficient in front of the water is going to be four. Because remember, when we take that four multiplied by the subscript of two, we get a total of eight hydrogen. Now. One thing to keep in mind is the number of oxygen's that we have on the right side four times. The subscript of two gives us eight plus four from the water gives us a total of 12 oxygen's. Because of this, we need to add the correct coefficient in front of the oxygen. In this case, it will be six because six months ago the subsequent to will give us 12.

Let's discuss the problem from organic compounds. Here we are given certain reactions of L canes, and some molecules in the reactions are missing. We need to indicate their missing molecules. The first reaction is the reaction between elkin and hydrogen in the presence of platinum acting as a catalyst. So this reaction is hydrogenation reaction where hydrogen molecule is added to double bond and forms. L came so the product formed would be ch three ch two ch three. The next reaction is the reaction between a molecule with bro mean to form one to dive remote propane. This reaction again is an addition. Reaction where bromine is added to elkin. So the missing molecule must be ch two double bond C H C H three that is propping. The third reaction is the reaction between an L keen and a molecule to produce carbon dioxide and water. Since hydrocarbon produces carbon dioxide on combustion. So this reaction must be the combustion reaction, and the missing molecule must be the oxygen that is 02 So these are the missing molecules for the reactions of Elkins, which are indicated here

Question 69 is in reference to an AL Keen reacting with a halogen, resulting in an addition reaction. In addition, reaction, we have a double or a triple bond in this case, a double bond onto which the two chlorine atoms attached. Then the only product would be A and Al Kane, where the double bond has been replaced with a single bond in order to accommodate the two chlorine atoms that were added. So we have CH three ch, with our double bond going to ch ch C H three and then the to chlorine end up attaching one to this carbon and one to this carbon in order to get this as our final product.

Hey, guys. So in this question were given various halogen ation and hydro halogen ation reactions and were asked to find the products for each of them. So for all of these questions, I, uh, grew the line bond drawings instead of writing out what was given in the textbook just to make it easier for us to a visualize the process of these reactions. So in part A, we have to beauty ing, and it's reacting in the halogen ation reaction with chlorine. So when we have a ah halogen ation, this chlorine is going to be added across the double bond and it's going to be added across both sides of the double wall. So we have our beauty mean parent chain right here, and the double one is going to be broken, and we're going to be adding our chlorine ions across it. So this will be our final product for this first question. Moving on to Part B. We have a similar reaction with a hydro halogen nation where four metal to Penn teen is reacting with hydrogen bromide, and we're going to see a similar reaction where the hydrogen and Bro Ming are going to be added, cross the double wand. So there's two ways disc can occur so the hydrogen can add be added to this carbon right here, or this carbon right here, as well as the bromide to either of the carbons opposite of which the hydrogen bonds to. So if we start off with our parent chain first, we have our contained now and then we have our metal attachment. The bro mean could be added here, and that means the hydrogen will be added here. I'm not gonna show it since, uh, this is the line one drawing and we don't normally show hydrogen ins or the hydrogen can be added over to this side. And the hype shin over here, the romaine over here, moving on to part C. We have to Pantene reacting with Romain. So the bro means going to be again at it across the double bond. So we have our parent chain for plantain and as our don't wants going to be broken, and our bro Ming is going to be added to each of these carpets, this is our final product. And for our last part, we have to four dimethyl to Pantene reacting with hydrogen chloride and the hydrogen is going to be added across to, ah, this side of the carbon. And this chlorine is going to be added to this center, most carbon atom, and we'll learn later in orga one. This is due to stability, and this is going to be our final product here.


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