Question
5. Solve the following: Show your solutions_[7 MarlWhether x + 7 is a factor of P(x) = 4x2 1lx + 16 Or not?b. Find the remainder when P(x) = 14x2 + 28x 30 divided by x + 36. Solve the following Show your solutions.[7 Mar_A circle has a diameter of [6 cm_ Calculate the area of a sector when the angle made by the radii is b_ Find the length of an are of a circle with diameter of 18 m that subtends a central angle of 1350
5. Solve the following: Show your solutions_ [7 Marl Whether x + 7 is a factor of P(x) = 4x2 1lx + 16 Or not? b. Find the remainder when P(x) = 14x2 + 28x 30 divided by x + 3 6. Solve the following Show your solutions. [7 Mar_ A circle has a diameter of [6 cm_ Calculate the area of a sector when the angle made by the radii is b_ Find the length of an are of a circle with diameter of 18 m that subtends a central angle of 1350
Answers
Calculate answers to the following problems, and check your solutions by making ballpark estimates.
(a) The melting point of gold is $1064^{\circ} \mathrm{C}$ . What is this temperature in degrees Fahrenheit?
(b) How large, in cubic centimeters, is the volume of a red blood cell if the cell has a cylindrical shape with a diameter of $6 \times 10^{-6} \mathrm{m}$ and a height of $2 \times 10^{-6} \mathrm{m} ?$
Were given that the circumference various directly as radius were given the radius and the circumference so we can find our equation and then using that equation, we need to find the circumference when the radius is 11. So various directly we have circumference is equal to K times our radius. We're given 43.96 is equal to K. Times seven. We divide both sides by seven, so 43 .96 divided by seven. It is 157 over 25 is equal to K. So our circumference is equal to 1/25 times our radius. So we now have 157 over 25 times 11. So 157 divided by 25. Just take that answer at Times 11. This comes out to be and we'll put it in a decimal Is 69.08".
Okay, so this time we want to find our equation of our circle. And it's not that these are two un points of our diameter. So here we can find our center points by summing are X values on dividing Right to So that's three and something, or why values and dividing by two as well. So that's a good one. So our mid points or center is going to be very calm when they could have won. Let's use our equation of our circle on Take one of our points and our center points to solve for R squared. So that's going to give us three minus. Uh, you're actually that's or ex Well, which is a good one minus three squared. Plus why? Which is negative for 123 minus K, which isn't a good one. So that's plus one. Depart to what it's four squared plus four squared, which is equal to 32. So it's not all right out our equation of our circle. That's X minus. Our center rowing, which is three squared class Y plus one squared, is equal to R squared, which is they get you
The following equation is set up so that the values off a B C can be deter mined immediately. Which is it? Solving the E questions which are given our three x squared minus 70 NX minus six is equal. Two X plus five born square is equal to seven. Expert plus X is equal and three explosive. One Pinto X minus seven is equal to zero. The quality ignition is in the standard form. A X squared plus B explosive one, which is in the standard form, is this option. So here is equal to three and B is equal to minus 17 and C is equal to minus six. So excessive will do minus B plus or minus under B squared minus four a. C by to a with equal to minus off minus 17 plus or minus. On the route, minus 17 holes were minus pouring to three to minus six by two into three. So this will give us 17 plus on minors under 3 61 by six that is equal to a 17 plus or minus 90 by six and X is equal to minus. To buy stakes. Common 36 by six x really will be minus one by three. Come on six. These are the two values off the X
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