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Enter your answer in the provided box:Calculate the mass of KI in grams required to prepare 5.00 X 10? mL ofa 2.4 M solution:...

Question

Enter your answer in the provided box:Calculate the mass of KI in grams required to prepare 5.00 X 10? mL ofa 2.4 M solution:

Enter your answer in the provided box: Calculate the mass of KI in grams required to prepare 5.00 X 10? mL ofa 2.4 M solution:



Answers

Calculate the mass of $\mathrm{KI}$ in grams required to prepare $5.00 \times 10^{2} \mathrm{mL}$ of a $2.80 \mathrm{M}$ solution.

Here, we're fastly looking to calculate the number of miles of K. I. Which is equal to the concentration, multiplied by the volume. We got not point not not two moles. And then we can calculate the grams. So we take not point not not two moles. And then we multiply it by the molar mass. What we get is not .332g. So the number of g of K. I. is not .332. And so the equation we need here now is the polarity of the concentrated, multiplied by the volume of the concentrated is equal to the polarity of the dilute, multiplied by the volume of the dilute. Where the polarity of the concentrated is not point not to 00 moloch the volume of the concentrated 250 mil. The polarity of the dilute not point not not one Mola. So we're looking to calculate the volume of the concentrated, not point not not 100 mola multiplied by 2 50 mil, Divided by 9.9200 Mola gives us 12.5 mil. The volume of the concentrated

Opponent of the solution is identified as the solvent and the minor component is identified as the sole. You. So many chemical reactions are carried out in solutions and solutions are very closely related to each one of our everyday lives. So from the liquids that we drink to the air we breathe and the fluids within our bodies, they are all considered solutions. So what we have here is the matter of potassium iodide, which is 258 mg, which is 258 times 10 to the minus three g. Where the mass of potassium iodide is equal to the mass of solution, multiplied by 5%. So we can determine the massive solution by the following. There's our 5% and then we take our S. I. Units of the massive potassium when I died 258 times 10 to the minus three grounds is equal to the mass of solution multiplied by 9.5 we've taken that 5% and divided by 2100 so that our massive solution we can rearrange and solve for and what we get is 5.16 g

In the problem. 49. You have to recalculate, um, the new volume mobile solution after it gets diluted on DDE in order to do the easy calculations off a solution before and after dilution, there is, uh, simple relation. We can remember, you know, to make it easier for ourselves. Polarity hold times falling old equals two mil at you times volume go, do you We're gonna use this equation in order to calculate the new volume of the but that see my that solution. So, um, if we solve this for well, you kn you we will see if we have to multiplies already. Oh, by William Old, then divide it all by Larry. Yeah, and that's as easy as it ever gets. Take a look at what we actually are given. Were given, uh, the old milady. It iss actually 5.0 Smaller solution. Um, were givens up old volume. It's, uh, 54 0 milliliters. Uh, we're not given than you. Concentration or polarity, I should say off the doesn't my that. So this is what we gonna calculate from equation that was previously you. So, milady, you He's equal to, uh, moles of substance divided Vita ball here when we don't know them all. So we have to calculate that as well. And this we calculate from the relation off the amount of moles of the substance is equal to mass off the substance divided by the molar s. If you put that relation into this equation will get mass divided by volume. Mm. Divided if I volume smaller mess. So, um, we know that we have in our new solution, we have 30 point all five grounds with that same iodide in 25,000,000 dress, which was 0.25 leaders. And the molar mass of potassium iodide is 100 66 point oh grounds. Colonel. So what's he puts these values in our calculator? We get the new polarity, which is open seven, 35 miles. And now we have everything you know to be able to calculate, Didn't your volume. So let's do that. What you is equal to, um polarity old, which we know is what I want. Oh, Muller, Times volume, Walt, which is all points call five Oh, leaders, um, divided by D. Well, I already knew which would just calculate all point 735 Moeller. And this will give us full 0.340 clears or 300 morning. Milius said, This is our Asher. In order to get the concentration that is required by a problem, we will We're gonna have to dilute the solution that we have with water to a volume off 340 milliliters or 1340 leaders.

To what volume should you dilute? 50 milliliters of five more clarity's of Okay, I So that 25? No, it is. Does I wish deleted solution contain 3.5 grams of K. Okay, so recall the polarity of art. That solution is equal to the math. 3.5 grands over. Um, the volume in meter. I said that 25 times. 10 to the negative three leaders, and then this will supply it out by a more math. Okay, I That's 166.28 grams for one more, and it gives me zero points. 73493 polarity of K. I Okay, Not I would have the polarity. Um, I definitely solution. We know that the polarity of C is equal to five. And the volume with the secrecy 50 million. The vault are similarity of ours. Included is equal to zero point some indri for 93 We need to find the volume of our solution. So volume over there with a solution is equal to empty. BC over m d. That gives me five times 50 milady. Over 0.73493 polarity. And that gives me 240 militar.


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