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CompiMoving to another question mll save [hls response:Question 19For which of tne following functions specifying positionstuncuon oftimethe velocity te Positive at...

Question

CompiMoving to another question mll save [hls response:Question 19For which of tne following functions specifying positionstuncuon oftimethe velocity te Positive atretion?I7- 6+2 + 5DI=-?-Stts "3+50x= 5+561= =187DLL

compi Moving to another question mll save [hls response: Question 19 For which of tne following functions specifying positions tuncuon oftime the velocity te Positive atretion? I7- 6+2 + 5 DI=-?-Stts "3+5 0x= 5+5 61= =187 DLL



Answers

Questions $20-22$ refer to the following scenario:
What is the impulse during the collision? (A) 10 $\mathrm{N} \cdot \mathrm{s}$ (B) 2 $\mathrm{O} \mathrm{N} \cdot \mathrm{s}$ (C) 3 $\mathrm{O} \mathrm{N} \cdot \mathrm{s}$ (D) 6 $\mathrm{O} \mathrm{N} \cdot \mathrm{s}$

You were given this S. Of T. Function. We want to calculate the instantaneous velocity at time 10. And we'll use our definition of instantaneous velocity. So using our function we will have the limit as H approaches zero of s. Of 10 plus age minus s. Of 10. All over H. So we're gonna do a little bit of side work here. Let's find s of 10. I plug in 10 into the function. So that's 30 minus five. So that's 25. 25 is going to go right there and then you want to find S. Of 10 plus H. By plugging templates agent to the function. And that simplify that by distributing the three. That'll be 30 plus three H minus five. So that'll be 25 plus three H. And that's gonna go over here. All right. So, let's see what we'll have. Then the limit as H approaches zero of 25 plus three age minus 25. Yeah. Oliver H. Our 25 will cancel and then we'll have three H over H the H is will cancel and now we're doing the limit as H approaches zero, there are no H is to plug the zero in.

Use the results of part being problems 65 for the motion along a single axis. In the following situation, frame A in figure 31 is attached to a particle that moves with velocity 310.5 C pass frame be Which moves past frames, see with the velocity of .5 c. What are M a C B and a C? And the velocity of the particle relatives of frame? See Okay, so first let's note that since n is one minus beta over one plus beta, that means that beta is a one minus M over one plus M. So from the problem we know that beta A B is 1/2. And since beta A B is one over to, that means M A B is one third, so M A C is M A B NBC, which is a third time's a third, Which is at 9th for part B. So beta A C is one minus M a c over one plus M a C. And that gives us 4/5 part C, the velocity of the particle relative to frame. See so by definition of beta, which is the speed parameter we have, that V a c is equal to For over 5 0.8 0.80 c.

Did you give him home? We want a function representing the position of a particle which has positive velocity for um T between zero and 0.5 and negative velocity between 0.5 & one. So what this is gonna look like is for example, we could have fFT equal 12 plus 40 And it's 4th t squared. We do this. We see that there is positive velocity from zero so one half From 0-1 half. We see that the slope is positive And then from one a half 21. So from here to here we see that the slope is negative. So that's an option. We can also just bring this down right here. I just need to go all the way up to 12. It could just look something like this and we see the velocity would also fit the same model.

This problem were given, That s what you is 20 times the coast and were asked to find, um, average velocities near the point. All right, He was fired over two and ask us to do it in a someone mad that we didn't exercise in 1920. So if you wanna look at those problems the way we did it, I met her whole from you, Not do you want. And then we find the average velocity that time, period. And the way we do that is by using the equation s, uh do you want minus s team all over Delta T, which is just t one last, you know. So all right, time minerals here. So I wanted to find around pi over two summers going do in a manner like this to I over two plus one, right over to over to plus 0.1. Why over two I, over two plus 0.1 and finally pile over to buy over to plus 0.1 Okay. And like I said, there's gonna be using this equation over here in the blue. So you put this in our calculators quick. So our equation is 20 Coast 90. Make sure your radiance. So we're gonna be going from essentially seclusion. So listen to our average loss equation. All these values is the table will get these the values like I better gives us. So conjecture as their time it'll get smaller and smaller, which means that we're approaching the instantaneous velocity. That time he was by over two. Our average velocity is around negative. 20 So high. Our hypothesis is that the instantaneous velocity at time T equals Sorry Time he goes by over two. Is that the instantaneous losses native 20?


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