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OH Specify a synthetic rbene that would produce thc compound shown abovc 64e4 steps possible Usc onc of thc starting materials sho#u logcthcr with any of the availa...

Question

OH Specify a synthetic rbene that would produce thc compound shown abovc 64e4 steps possible Usc onc of thc starting materials sho#u logcthcr with any of the available reagents Givc thc nurnber of thc statting matcrial followcd by thc Icttcrs of thc rcagcnts te order oftheu usc cxatuple_ 3beStarting MaterialschoCCHCoc,H:CHOCCk CCH;Cch;Available Reagents CHyICHBrCHCH NaOc HH,o , neat N3ux Ho menho

OH Specify a synthetic rbene that would produce thc compound shown abovc 64e4 steps possible Usc onc of thc starting materials sho#u logcthcr with any of the available reagents Givc thc nurnber of thc statting matcrial followcd by thc Icttcrs of thc rcagcnts te order oftheu usc cxatuple_ 3be Starting Materials choCCHCoc,H: CHOCCk CCH; Cch; Available Reagents CHyI CHBr CHCH NaOc H H,o , neat N3ux Ho menho



Answers

What starting materials are needed to prepare each drug using reductive amination? Give all possible pairs of compounds when more than one route is possible.

The question is locked. How we're using today's format of Stephen on from broadband in not more than irish steps. So we have to prepare format. Toxie no. From the flow of energy. Mhm. So first these components reacting any words. Then we will get no, no. Mhm. This final is your thing. Then the CNN do efficiently. Then we will get seeing further requests. Any which will give wonderful. They are toxic. Now, see S. three for minus any business. Thank you. Who's the stu? It was still on the product. What? My dog, stefano. Right, so I hope you're getting correct answer. Okay. Thank you. Okay.

Until for the coaching here. Until for part A, we have a me too. See all acetone. This is a certain and mhm m e m g c l Answer for a party. Answer for Barbie is edge to Siegel. Formally high maternal weekends here. Simplest Ellie Height and C s three CS two Oh, small five M g c l Answer for part C Beauty, anal and m e M G C l are eternal as Italy height and yeah, yeah, C H toy C H two all to m d C. L.

Mm. Hi, welcome to question number 42. In this question, you want to know if we have 25 micrograms of c. 21 age, 30 oh two, We want to know how many moles that is and then how many molecules that represents. So to do this, we are going to need the molar mass of this substance. So we're going to add 21 carbons to the molar mass of 30 hydrogen to the molar mass of two oxygen and I get 314 0.45 So the Mueller mass 3 14 0.45 Of course that would be grams per mole. Right, So I'm going to use this information set up a little bit of dimensional analysis here. First thing I need to do is to get my micrograms two g. So I know that there are one times 10 to the sixth micrograms of anything in one g. Now I can use my molar mass. So there are 314.45 g of C. 21. Age 30 oh two in every mole of the substance. Mhm. Notice I put the grams in the denominator so that they will cancel. So the only unit I have remaining now is moles. So I can go ahead and calculate my answer here. And I'm going to round it to two significant figures since 25 only had two and I get eight point oh times 10 to the negative eighth of the C. 21. Age 30 oh two. Okay, the next thing I want to do then, so let me circle that. That is our first answer. That is the number of moles. Eight times 10 to the negative eight moles. Next thing we want to do is figure out how many molecules this is. So starting with my number of moles eight times 10 to the negative eight moles of C. 21 H 30 02 We need to use of God Rose number because we know there are avocados number of particles in one mole of anything. So six point oh 22 times 10 to the 23rd. That is avocados number. Okay, molecules of the C 21 H 30 02 in every mole of the C 21 H 30 02 What? All right, so mobile cancel and I get a number in number of molecules again rounding the two significant figures. I get 4.8 times 10 to the 16th molecules of C 21 age 30 oh two. So that is the answer to the second part of this question. Thank you so much for joining me.

This question asked how we can synthesise this molecule using starting materials with no more than six carpets. Eso here we have a dy ke tone, and a lot of times Dikky tones are cleaved bios analysis. So, um, for going in reverse order here. The last step would be Oz's analysis, which is a negative Sony degree Celsius. And it's followed by Di methyl sulfide. Um and so what does? It also says that cleaves a double bond into two Carbonell groups like this. So the structure before the O's analysis would look like this. Um, and we know this because the, um, these two had to be bonded together, this carbon in this carbon. And so that's 123456 carbons, says six member ring. They had to have a double bomb that was cleaved into the two Carbonell groups, and then each of the two and the double bond had a methyl group coming off. So that's where these came from. I'm slim to make this. This still has a carbon Zenit winning starting materials with no more than six. So to make this, we're going to do a deal. Zolder reaction. So just to quickly recap deals. Older reaction looks like this. So we start with a dying and a dining a file, and then we always end up with this six member ring with a double bond looked over on the side that have dying file. And that happens like this. All these electrons move with those arrows. And that's why we ended up with that double bond right there. So this is that double bond here, which means that this half of this molecule had to be the dying, so that would look like this. And then the Diana file here would just be that two carbons, cause that's all. It's on that side. Um and so that would be The first step in this reaction is to do the deals older. You get this AL Keen, and then we could split it with those analysis to get our final product


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