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Question 193 ps19. In a radical reaction, the following step Cl = CHSCH CHs CHSCHCHs HCIis an example of a(n)initiationB propagationterminationD addition...

Question

Question 193 ps19. In a radical reaction, the following step Cl = CHSCH CHs CHSCHCHs HCIis an example of a(n)initiationB propagationterminationD addition

Question 19 3 ps 19. In a radical reaction, the following step Cl = CHSCH CHs CHSCHCHs HCI is an example of a(n) initiation B propagation termination D addition



Answers

$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CH}_{2}+\mathrm{ICl} \rightarrow\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CClCH}_{2} \mathrm{I}$ is an example of (a) anti Markovnikov addition to the double bond (b) a regioselective reaction (c) an electrophilic substitution reaction (d) a stereospecific reaction

Right. So here we have shown the reaction of Sallis in with dilute its jail. So, in other words, a shell in water. Ah, and the rest predict the product. Eso first, we're going to have a sugar kind of remain, um, with some slight differences. So first destroying our chair confirmation Ah, we're going to have a non specified in just a wage. Um, that's why do that squiggly line. But then the rest of the chair configuration should stay mostly the same, if not identical. And we're also going to house Ah, this molecule right here, which I believe the book says it's so cilic acid. All right, So in order to propose a mechanism for this reaction, what I'm going to do is ah, going to basically start with ah h 30 plus. Now, that kind of thing would obviously kind of be around since you've got dilute acid in water. So the first step of this mechanism would be this oxygen taking away that very acidic proton. And I'm gonna kind of start by joining this equilibrium a little downwards. Um, but essentially, what that would do is that what yield? Um, that all right, So on important thing is that this oxygen has a bunch of lone pairs because the next step is going to be for that to push on to there. Ah, and then for this bomb to leave completely. And that's where ourselves like acid comes from. Because the next step in this reaction would be to form. I would be this product. All right, So the next thing we could have is since we used our third hydra and we will have just oxygen insulation. Ah, so you could have oxygen attacking this bond and pushing back up onto that the in America oxygen Ah, which will lead to oxygen being on that carbon. It's an important thing to point out is that can attack from below or above the plane on. That's part of the reason we draw this squiggly line when we draw, uh, this structure. All right, so now we need some base Teoh kind of come and take away this third hydrogen because that is a very positive, uh, Austria there. So the two things you can use considering that this is HCL, you could just use C l minus as your base or you could just use another H 20 Both of those won't really make a huge difference. Considering part of using acid catalyst means the acid will survive about the reaction. So I'm just gonna choose to use O h two. But know that if you do this with C l, that would also be correct. But essentially, what's gonna happen is that this is just going Teoh de prone eight, that oxygen. I'm enjoy slightly diagonal arrow here and that we yield our final product, which will be this. All right. And like I said, the second product, this one right here came out of this step away here with this entire group just left.

In this problem, we have given a re accent which I am writing here. Just look at it carefully. Three Cielo minus Act was Is changing to Cielo three ecowas plus to C l minus acquis. So it is an example of it is in example of this proportion. Nation reaction Yes through all see nation every accent. So according to the options here, we can say that option. See each obstinacy. It correct answer for this problem. Obstinacy is correct answer for this problem. I hope you understand it.

In this problem, I can write the reaction at CH three CH 20 h in potential PM and no food Will change into CH three COOH. And this component presence of associate to Well chain into CH three COCL. And this component presence of NS three will change into C h t C or NH two. And after it react with BR two plus, any oh edge Will give the Hopman Bromide reaction and the product from its CH three NH two plus And to see you three plus and maybe R plus S two. Therefore, option B. It's corrected, Option B. It correct here.

First, um, the addition of Roman on pal Mito. Like as it is. Ah ch three ch 25 c h double one ch C h 2702 Etch prisons off there forms ch three ch 25 c h v r C H v R C h 273 or two h Second, um, the addition off hydrogen on belt More Well, metallic, I said is See it three ch 25 c h double born ch ch two 70 or to edge in addition, off hydrogen. Uh huh. Firms ch three ch 2 14 Kowtow Age third Ah, the high drugs relation off, pal Metallic acid with quotation permanent that is ch Terry ch 25 c h Double one ch ch two 70 or to edge friends. Okay, am and four rich minus foreign Tch three ch 25 c h off it The edge or edge ch 2 70 or two minus last late. The addition off I took Laura guested on bell Metabolic acid is ch three ch 25 c h double one ch C h 27 c or to edge. Sure enough, it's hell. It's ch three ch 25 Ch two c F C L c h 273 or two edge that c h three ch. 25 c h C L C h two C h 273 or to pitch.


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