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A0.4S mol gas sample s volume was changed from 62 Lto 9.1 L what will be the gas sample? resultant number of moles of tng0 0.066 mol0.068 mol0.069 mol0,067 moe...

Question

A0.4S mol gas sample s volume was changed from 62 Lto 9.1 L what will be the gas sample? resultant number of moles of tng0 0.066 mol0.068 mol0.069 mol0,067 moe

A0.4S mol gas sample s volume was changed from 62 Lto 9.1 L what will be the gas sample? resultant number of moles of tng 0 0.066 mol 0.068 mol 0.069 mol 0,067 moe



Answers

An $11.1$ - $\mathrm{L}$ sample? sample of gas is determined to contain $0.50 $ $\mathrm{mole}$ sample?of $\mathrm{N}_{2} .$ At the same temperature and pressure, how many moles of gas would there be in a $20 .$ - $\mathrm{L}$ sample?

There's this question 36 from Chapter 16 and it's another ideal gas equation problem. And we have so full surfer pics of fluoride. And we were trying to soften the volume. So the equation the gas androgynous pressure. That's volume this equal to mold times a gas constant times temperature, the rear someone petroleum's they're gonna You're gonna rearrange this equation. Teoh Volume is equal to most Pastor cost gas constant divided by pressure. Okay, so now we can actually write this out. So we have nine 0.8 morals times a gas constant of 0.0 a tooth. Eight 206 Leaders times, atmospheres Her main times Calvin times the temperature on the give us 105. But we have to convert this to Calvin. And so you got the at 273. And that gives you 378 Kelvin and we have a pressure of 9.4 atmospheres. Cut this in nine times. Eight. My point, You 86. I was 378. Good. Not to be about 300. And divide that by my 1.4 and should be about 32 0.35 liters as your volume

In this question. We have a balloon with 0.1 to 8 molds of the gas and a volume of 2.76 leaders and were asked if an additional 0.73 moles of gas were added. What would be the volume of the balloon? So our end to here is really 0.1 to 8 plus 80.73 So that gives us an and two of zero point 201 moles, um, and really use of a God firms law assault. So that is the one over N one equals B two over end to Before. I was looking for this end to number. Um, and we're gonna solve for B to here because I will be the volume with this many moles. So the one is 2.76 leaders over end one, which is 0.1 to 8 moles. And that's equal to B two, which we're solving for over end to which is 0.201 moles. So now we do some math. 2.76 divided by 0.1 to 8, gives me a 21.56 leaders over moles equal to be to over point to a one moles on and then we'll go ahead and multiply it this side by the point to a one. Moles, um, and that will cancel out the mold unit and then also give me the two in leaders. So if I do, that's I will get a view. Two of 4.33 leaders.

For this question you have to use The idea gets loss, but I don't guess. Know is PV equals and R T and P is the pressure. V is volume, and this number of both are It's just a constant number. T is the temperature, so you're plucking every single element into the equation. So you are giving the number of moles with polio and temperature. So go neo is 30.4. He closed to number of more 6.9. Multiply by the constant. The constant is zero, pulling 08 to 1 and multiply by the temperature 62. But remember when we calculating the pressure, we always use Kalfin instead off degrees Celsius, so it's given 62. You have to change it to Calvin at 2 73 All right, once the all the calculation used to get 6.28 year

Hi there. This problem is located in the ideal gas equation section. So to solve this problem, we will be using the ideal gas law which is PV equals nrt. In this problem, we are given several values as we read through the problem. But we see that what we're trying to find, it's the number of moles. So we're trying to figure out how many moles of seen on gas we have reading on through the problem we see that were given a pressure of 1.18 atmospheres were given a temperature of 18 degrees Celsius. However, we know whenever we're using the ideal gas law equation, temperature must be absolute temperature. It must be in Calvin. So we're gonna add to 73 to this, which gives us 2 91 Kelvin and we're also given a volume of 26.7 leaders. So right now we have four out of the five variables in this equation we're missing. Our are is the universal gas constant. We have a couple of values for our that were given to us in this unit. We want to select the one that matches up in terms of units So since our pressure is an atmospheres, I'm going to select the R value that has atmospheres in its unit. So that is 0.8 to 1. Leaders times, atmosphere, leaders Sorry, times atmospheres over. Mole Kelvin has some rather odd units there, but we will see what happens with those units here. In a few moments, we are trying to solve for molds, which is end. So I'm gonna take the PV equals NRT equation before I put any numbers in it and I'm going to rearrange it. I'm going to isolate and by itself, by dividing both sides of the equation by rt If I divide both sides of the equation by rt I get end by itself and on the other side of the equation, I will get P V over R t. At this point, since I've identified all of our variables and our equation, we just need to plug these in and calculate the answer. So we have 1.18 atmospheres. We have a volume of 26.7. Leaders are we decided we were going to use the 0.0 8 to 1 leaders times atmospheres over mold Calvin and finally our temperature was 2 91. Calvin, have this all set up. It's just a matter of calculating it now. But before I do that, let's look at what happens to our units. Atmospheres will cancel. Leaders Will. Can't will cancel. Kelvin will cancel. The only unit we have left is moles, and it's in the denominator of the denominator. We have a complex fraction going on here, since it's in the denominator of the denominator. We know that that means it's actually in the numerator. So we go ahead and we calculate everything and we get 1.32 Moles of Xena. And that is our answer. Number of moles is 1.32 moles. All right, Thanks for watching.


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