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Question 345 ptsIf you mix 20.0 mL ofa 3.00 M sugar solution with 30.0 mL of a 5.74 M sugar solution; you will end up with 3 sugar solution of4.37 M0.175 M0 7.74 M4...

Question

Question 345 ptsIf you mix 20.0 mL ofa 3.00 M sugar solution with 30.0 mL of a 5.74 M sugar solution; you will end up with 3 sugar solution of4.37 M0.175 M0 7.74 M4.64 M11.61M

Question 34 5 pts If you mix 20.0 mL ofa 3.00 M sugar solution with 30.0 mL of a 5.74 M sugar solution; you will end up with 3 sugar solution of 4.37 M 0.175 M 0 7.74 M 4.64 M 11.61M



Answers

What is the molarity of an HNO $_{3}$ solution if 68.5 $\mathrm{mL}$ is needed to react with 25.0 $\mathrm{mL}$ of 0.150 $\mathrm{M}$ KOH solution? The equation is
$$\mathrm{HNO}_{3}(a q)+\mathrm{KOH}(a q) \longrightarrow \mathrm{KNO}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$$

Problem for people party. We know that modernity m equals two mall of solute divided by volume of solution. In leader we can also write this formula as given weight of solute divided by molecular weight, absolute multiply way one upon volume. Okay we need to put the values in this formula. So given that wait 15 g of L do Almond himself and so forth. All tries divided a molecular weight of al money in self. It is 3 42. Going two grand L two. Yeah. And so four whole tries multiply by one upon Julio. Given volume is sorry molecular weight 33 42.2 g caramel. Multiply by given volume is zero point 250 l object solving we get Approximately 0.175 and L two. So poor Paul tries this is our final and support party. Okay, in part of the again we used this formula. Okay we need to only put put the values given that high point to five g. Uh magnus nitrate dot to H two divided by molecular weight 215 points. Ground parmesan multiply by given volume is 0.17 pipe looked at after calculating they get approximately value 0.140 and magnus nitrate. This is our final answer for part B. Okay. In part C. We use this formula. I'm already at consent. SNC multiplied by holy met consent agency. Because to I'm already at values and be multiplied by volume up at dilution. The after I listened we use this permanent because the number of moles is constant after be poor and opted valuation of of any solution. Okay so given that mall dirty before dilution is nine mm H two S 04. Multiply by a given volume of solution is 0.0 three 50 Later it calls to mull pretty at Dallas and D multiplied by holy moly. So listen, that is 0.50. Your leader. After solving this, we get modularity of at two air support of as to as a four equals 2 0.630. Um, This is our functional and support part C. This small ready is uh multi tiered volume of solution. 500 ml, 500 ml. Or I want it later. 0.50 leaders.

Okay. What song? Wandering. They dio wind really do. But the local one 50 boy mu and boy by 13 a. M And when you go to 120 What? Doing well, but thank you. And 233 And so these are the two solution Gomes together. And when I miss together, we have the the media You call V one What we want lost b two, All right. And when they they missed the red together with another concentration off the Mitchell. Right? So the concentration of mature should be equal and Mitja and one last and do and one ego sit the pause here. Happy won't? No this so we got em, media and once a 13 in

In order to figure out the polarity from Grams, we're gonna have to figure out the molar masses. So I've taken the liberty, taken the liberty of going ahead and figuring out for every compound. Once you have the molar masses, though, you need to figure out how you need arrange some factors in order to actually calculate you're malaria. So we know that, um, pretty much we have to have moles per liter in order find polarity, which is a good thing, for the most part. So, um, if we're gonna kind of sketch out our approach here in a road map, we have grams. And we know that we're trying to get from grams to moles because we're trying to make molds for leader. And so, in between, we're trying to get toe leaders, and then we're trying to get to here to polarity because we're trying to figure out the number moles in one leader. But sometimes we have milliliters along the way where we have to know that one leader equals 1000 milliliters to kind of convert that way. And then we actually have to use the Mueller Mass to convert two moles from grants So for the first example, we have 31.76 grams. Well, if I go ahead and divide that by my molar mass, I get moles and then I have to take into account the milliliters, which is 475.0 milliliters. So I'm putting my volume on the ball bottom because supposed to per leader anyway. And that is just going to be changed into a leader. And then I get 0.6 to 8. Moeller if I do the same thing ever here I have 6.37 grams over 250 male leaders. And then I use my morass again. Multiply by 1000 to change the boy in tow leaders, and we get 0.193 Moeller. If I do the same thing here, that's gonna be the master they gave me, divided by the volume the molar mass to cancel out our grams to get moles, which is what we want. Multiply buyer No leaders to cancel that out to get moles per liter and we end up getting 0.333 Moeller And then finally, the last 1.773 grams 3 31.2 grams to get bowls put our volume on the bottom 100 knows. Multiplied by 1000 mills. Our units canceled out and we end up getting 0.233 Moeller.

So here in this problem we have, we're trying to get the grams of the US that was required to create the solution and to the 1st 1 It tells that we have a six Mohler anyway, solution or I like to write moles over leaders because that just to expand it out to understand the cancellation of the units and does that we have two liters of this. So you can see already that the leaders canceling your in moles and then how do we get to grams? So to get the grounds refused the molar mass in the Mueller massive Noh is 39 0.99 grams per one more and you can see the moles cancel now and you multiply that the entire top and you get 480 point grams and which in this point, right here, the steps more here is important because we have three sig figs and so the next one, we have a 10.100 Moeller or moles per liter of um yeah, moles per liter of this C A c l to solution are and it tells us that we have five leaders of it so 5.0 Leaders, leaders cancel and then finally, we use the molar mass again and you can you look it up or I use the periodic table and it's 100 and 10 grand, 110.98 grams for one more, and you can see the most cancel. And when you want to buy the entire top across, you get that equal to 55 0.5 grams of C A C L two infant Last one, we have 3.0 Moeller or moles over leaders of this ah, sodium nitrate or and and all three. And right now you have to put the, uh or here we have to put the leader. So 1.175 leaders and be careful don't put 175 milliliters here like it says in the problem. We have to convert that into leaders, which is just moving the decimal place three over or 30.175 liters and then we can use alarm ass to get rid of moles and get into grams. So you get 84.99 uh, grams for one more, and you can see all the units cancel and you're left with grams and you get a final answer off 44.6 grams of the N N 03


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