5

I) - Ie 8 3 (6-30) +3/46 | 0 { 9 9 + 0 01) + (n 4Find 3 the determinant 9 h LS 4 of 0 2 2 88 J 8 using =_4 8 3 TOw-cofactor +688 expansion...

Question

I) - Ie 8 3 (6-30) +3/46 | 0 { 9 9 + 0 01) + (n 4Find 3 the determinant 9 h LS 4 of 0 2 2 88 J 8 using =_4 8 3 TOw-cofactor +688 expansion

I) - Ie 8 3 (6-30) +3/46 | 0 { 9 9 + 0 01) + (n 4 Find 3 the determinant 9 h LS 4 of 0 2 2 88 J 8 using =_4 8 3 TOw-cofactor +688 expansion



Answers

Compute the determinants in Exercises $1-8$ using a cofactor expansion across the first row. In Exercises $1-4,$ also compute the determinant by a cofactor expansion down the second column.
$$
\left|\begin{array}{lll}{4} & {3} & {0} \\ {6} & {5} & {2} \\ {9} & {7} & {3}\end{array}\right|
$$

Okay, so we want Thio find a determinant off this matrix using expansion across the first road and then we'll find it by the second caller. So the first thing that we have to do is to record to remember what the signs up. So if you want to expand over the first road, it can't be positive, negative and positive. So we have zero times by the determinants off when we removed the road and color off 3031 and then it's negative. Wonderful. Minus full tons of determinants off 502 and one. And finally, it's a plus sign under one time, by the determinant off five minus 32 and three. So this is zero multiplied by voxant determinants that this is zero. So you can stop that in this advice for time by the determinant, which is by time by one minus two times zero plus one times five times three minus two times like native three. This is four miles four time bye bye plus five pounds Freeze 15 15 plus six which is equal to 20 What? Minus 20 plus 21 which is simply one Now if you want todo an expansion on the second column. We have to remember that this is negative. This is positive. And this is negative. So the easiest way to remember is this is 11 The position of this block 11 and one plus one is two even. So, some positive. This is one to which is through one plus two years. Three, This is going to be negative. And this is 22 which is four. So it will be a positive. This is 32 which is five. And so we need to. So you will have minus four. Tether the determinants off 50 to 1 plus by minus three kinds. Like the determinant off your one Jew one in minus three times is your one five and zero. This is minus four times by five times one plus two times zero minus three times zero times one minus. Two times one minus three time. Zero times there, minus five times one. And this is minus four times by five. Minus three times minus two and minus three times minus five, which is minus 20 plus six plus 15 which is equal to one

Okay, so we want Thio find a determinant off this matrix using expansion across the first road and then we'll find it by the second caller. So the first thing that we have to do is to record to remember what the signs up. So if you want to expand over the first road, it can't be positive, negative and positive. So we have zero times by the determinants off when we removed the road and color off 3031 and then it's negative. Wonderful. Minus full tons of determinants off 502 and one. And finally, it's a plus sign under one time, by the determinant off five minus 32 and three. So this is zero multiplied by voxant determinants that this is zero. So you can stop that in this advice for time by the determinant, which is by time by one minus two times zero plus one times five times three minus two times like native three. This is four miles four time bye bye plus five pounds Freeze 15 15 plus six which is equal to 20 What? Minus 20 plus 21 which is simply one Now if you want todo an expansion on the second column. We have to remember that this is negative. This is positive. And this is negative. So the easiest way to remember is this is 11 The position of this block 11 and one plus one is two even. So, some positive. This is one to which is through one plus two years. Three, This is going to be negative. And this is 22 which is four. So it will be a positive. This is 32 which is five. And so we need to. So you will have minus four. Tether the determinants off 50 to 1 plus by minus three kinds. Like the determinant off your one Jew one in minus three times is your one five and zero. This is minus four times by five times one plus two times zero minus three times zero times one minus. Two times one minus three time. Zero times there, minus five times one. And this is minus four times by five. Minus three times minus two and minus three times minus five, which is minus 20 plus six plus 15 which is equal to one

Today we are going to solve a problem. Number one here. We need to find the determinant off. The Given three by three Matrix matrix is 304 toe, three do and 05 minus one there to expand the law. Second column. That's what has the in question. So it will be like minus zero and do some value will be against zero does three Indu minus three plus zero, then minus five. Window six minus eight So it's result will be minus nine plus 10 which is equal to one.

Everyone today we're going to start problem about five heavy needs to find the determent off the three by three matrix which has given us to three minus tree four zero three, 615 So if you expand, why do they get They will be like minus three in the 20 minus 18 second element is zero into some value minus morning. Six press developed. So it comes to be like minus three in your tooth my last one in the 18. So it will be like my last 24.


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