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Ravlow 0t Probablilty ConcoptBased from the same survey above; what is the probability that the respondent does not have child In college?0 440.560.350.25What is th...

Question

Ravlow 0t Probablilty ConcoptBased from the same survey above; what is the probability that the respondent does not have child In college?0 440.560.350.25What is the probability that the respondent has a child In college or thinks that the loan burden Is too high?0,351,040,690 91Whai i the probabillty that the respondent nelther has 0 chilld In eollege nOr thinka thal the Ipan burden to0 high?004Yoo 5

Ravlow 0t Probablilty Concopt Based from the same survey above; what is the probability that the respondent does not have child In college? 0 44 0.56 0.35 0.25 What is the probability that the respondent has a child In college or thinks that the loan burden Is too high? 0,35 1,04 0,69 0 91 Whai i the probabillty that the respondent nelther has 0 chilld In eollege nOr thinka thal the Ipan burden to0 high? 004 Yoo 5



Answers

The table gives the results of a survey of $219,864$ first-year shudents from the class of 2013 at 297 of the nation's four-year colleges and universities.$$\begin{array}{|l|c|c|c|c}\hline \text { Number of Colleges Applied to } & 1 & 2 \text { or } 3 & 4-6 & 7 \text { or more } \\\hline \text { Percent (as a decimal) } & 0.14 & 0.24 & 0.39 & 0.23 \\\hline\end{array}$$ Using the percents as probabilities, find the probability of each event for a randomly selected student. The student applied to fewer than

We have to find in this problem. Probability Off student A flight. So no colleges so which is probably tee off zero, which can be written as one minus off probability off one. Bless probability off who are today plus probability off. 4-6 Less probability off greater than equal to seven. So therefore which is one minus off 0.20 plus 0.29 plus zero point to the seven blood zero point 14 So which is equals to one minus one, which is zero.

So for these crushes when you use a table in the exercise. 15. So let's go back to the exercise. 15 to see the table pull this table. We have, ah, six rows and six columns pull. It shows it will present a different country there. China, France, India. You can you, us And who will call? Um, it's represent the front education, apple, postgraduate colleagues, High school point or glass and no answer. And they also has, uh I'm Total Colin one total rose. And we know that the total number of the table is 76 night there will and the then let's go back to the questions. The question is a probable thing that a person from the United States has done Pro posed too great. I started. Ah, hey, I asked him probably that person from United States and did graduate postgraduate study. I read G. Yet what? What we we need to do is go back to the table and find you asked Rose and the postgraduate columns and find in section. The number is 84 so the probability here is it goes to a holding by by its total on birth 76 nights they will get approximately because through their point, they want it. And the problem be iss probable that he that Ah, a person from United States who have don't gradual proposed a graduate story. So here, as different from problem a sense, it's a conditional probability. And it's a probability that the person from the United States, uh, given that he has already don't postgraduate study. But here was you use ah, conditional for look, cackle I this it goes to p your ass and a postgraduate study divide by the postgraduates. So the probability and go back to the table. We can fight the probability you ass and the postgraduate saw the ISS a full divide by 76 night. They will, in the probability that the postgraduate study is, uh, uh as total numbering The 1st 2 column Yes. 37 night over 76 90 equals two 84 over 37 approximately equals to their 370.22 Question See, is probable that he data Ah, the person from the 19 state it has done pro postgraduate study. So here you need to find a condition. What's his condition? The condition Keir should be Ah should be the person from the United States. So here what we want ihsaa probability, Uh, as a person has dunk where postgraduate studies given that is from new estates you saw seemed technique is g and you to buy a by you So the numerator is similarly as problem be in the d not, mate Pete, you iss probable old hell you ask Ah, we can see from table is war 557 divided by 76 night Isse 94/1 57 approximately equals two Ah say roll point They will fight in the problem the ISS The probability that's a person from China has only a primary level. Ah, education. So the probable t the person from China and only has primary alas, education. So what we need is find the intersection off the China Rose and primer. Primary Education column is five There were six over 76 night. There were approximately close to zero point. There was heaven in the final problem Is the probability that ah person Onley Ah, primary level education isse from China. So here you should understand me or days questions and right that this is a conditional probability The probability that, um ah, that's how person from China, given that he is solely a primary level as education here, use the conditional formulary. Similar piecing and primary alas, divide by probable he primary old less. Let's go back to you the table. We can see a za numerator Probable t China and the primary in the last education. Yes, fine. 06 Over the total number of 76 night they will and the denominator probability that education primary less is Ah 1234 Force columns A total number here 11 61 over the total number 7690 And ah, the final result we have. Here's Fire co 6/1 161 approximately close to 0.4

For this problem, we need to look at the chart that shows the number of colleges applied to and the percent of students that fall into each of those categories. And I want to know what the probability is that a student applied to more than three colleges, while more than three could be 4 to 6 colleges. Or it could be seven or more, according to our chart thes air. The probabilities for either of those two cases. And since I want to know what the probability of one or the other is, I need to add these up and I end up with 0.62 Now it is important to make sure that there's no overlap between the categories, and in this case there's not. You're either going to be in one or the other, but never both. So the probability that a student applied to more than three colleges, 0.62

In this some we have to find probability off less than four. So which is equals to probability off one plus probability off two or three according to the problem, which is 0.20 plus 0.29 which is equals to 0.49


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