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Cylinder containing 11.4 moles of monatomic Ideal gas expands from @ to @ along the path shown in the figure below.P(P)J0.010.0V(m ) 1.00 2.00 %.00 4.00 00 G.0u(a)...

Question

Cylinder containing 11.4 moles of monatomic Ideal gas expands from @ to @ along the path shown in the figure below.P(P)J0.010.0V(m ) 1.00 2.00 %.00 4.00 00 G.0u(a) Find the temperature of the gas at point @ and the temperature at point @ point @ point @(b) How much work done by the gas during this expansion?(c) What Is the change intera energy of the gas?(d) Find the energy transferred to the gas by heat this process_Need Help?e

cylinder containing 11.4 moles of monatomic Ideal gas expands from @ to @ along the path shown in the figure below. P(P) J0.0 10.0 V(m ) 1.00 2.00 %.00 4.00 00 G.0u (a) Find the temperature of the gas at point @ and the temperature at point @ point @ point @ (b) How much work done by the gas during this expansion? (c) What Is the change intera energy of the gas? (d) Find the energy transferred to the gas by heat this process_ Need Help? e



Answers

Suppose 145 moles of a monatomic ideal gas undergo an isothermal expansion from $1.00 \mathrm{m}^{3}$ to $4.00 \mathrm{m}^{3}$, as shown in Figure $18-23$. (a) What is the temperature at the beginning and at the end of this process? (b) How much work is done by the gas during this expansion?

So in this problem, we are given the number of months is equal to 145 months and the initial volume is equal to one point. Jerusalem we took you and after expansion, the final volume is equal to 4.0 Mister Cube. In the first part of this question, I have to find initial and current temperature which has got to Cuban which has got to be too. He's got to t. We have to find the temperature because the initial temperature final temperature equal because the processes I saw thermal So we will find even t two, which is good to t for that we will use PV is equal to and Artie or T is equal to we We divide by N r. So we will substitute the values as P is equal 200 multiple our take for three Paschal's and we too is good too. We too. We too went by in her tattoo. Uh, so it will be 4 to 4.0 m Q directed by and is equal to wanted 14th, five months Multiply by R is equal to 8.31 Joel Permal for Calvin So when we saw this We get t two is equal to 332 Calvi, which is the conservative first part of this question. The street who is going to be one is equal to t because the processes are suitable. No, we will come toward the second part of this question in which we have to find the work done in the process. So we will use the question number 18.5. And according to this, Reagan is equal to N r. T Ellen. We towed right by Riven. So we will substitute in r D. Is it good to even? We went So we're done will be equal to we when we were in l n retooled right by we win. So P one is equal to 400 kg pastors and we even is equal to 1.0 m tube multiply by Mr Love off video is going to 4.0 m cube. Do I buy you an easy 4 to 1.0 Speaker 21 point 00 m cube. So when we saw this, we get work there is equal to 555 kg jal, which is the answer of the second part of this question

Hi, guys. I'm doing problem 21 from chapter 18 and it tells us that a mon atomic ideal gas is undergoing nicer thermal expansion. And it it gives us a little diagram and says what is the temperature of the beginning and at the end of this process, and then asks how much work is done by the gas during this expansion? Okay, so if we're dealing with and a nice of thermal expansion, um, of an ideal gas, So an ideal gas always should satisfy the ideal gas equation. P vehicles on our tea, right? PV equals on Artie. Okay, so now, looking at the diagram, we're just just showing, um, just showing an ice, a thermal expansion. You can read all from the diagram, either at the end point or uh either at one end point or the other or somewhere in between. If you can actually see what exact value it's hitting, you can read off the pressure in volume. Okay. And since this is the nicest, their p times, he should always be the same. So shouldn't matter where you take it. But, um, no matter where you you do, it should get the same answer for tea because it's nicer. So that means that the temperature should be the same the whole way through, uh, holy through the curve. And so you can rearrange the vehicles, Artie, to get t equals P V over nr and then calculating that calculating this you get about 408 Kelvin. So you have to be a little bit careful here because the pressure on the ah in the diagram is given Killa Pascal's right. So, um, what you may accidentally think is 400 Pascal's actually 400,000 Pascal's maybe a little bit careful about that, and you get so 408 Kelvin, if you do things correctly and then, uh, let's part a soap for part B and es with work done and the work done for a nicer thermal expansion and Artie Timesthe log VF over v I. So this is kind of nice to memorize, but if you don't have this memorized, you can actually get it from ah. Using work is the interval of P. D. V and then replacing P with and our tea over v using the ideal gas equation. Cuticles are dirty and then you can you can get to this fairly easily. Um, but anyway, this is This is what you need for the second part and do this calculation, you'll find it's about 555 killer Jules here. So end and were given in the problem are is a constant T is what we got from part part A 408 Kelvin's lefties. That and then VF and the initial are also given the problem. And so we find our final answer. 555 killed, Jules.

In this question were given two moles of a perfect mono atomic gas. It is initially kept in a surrender at a pressure of one into 24 6 newtons per meter square. And at a temperature of 2017 to 6 years. This gas is expand until its volume is doubled. In the first part of the question to calculate What is the one done? If the expansion is adequate expansion, I saw batting expansion and I scramble expansion. In second part, we have to draw the diagram for these cases. In third part we have to uh choose in rich process that he transferred his maximum and minimum. Uh In the fourth part we have to find uh in which process that changing internal energy is maximum and minimum. So let's first note down the given data, the number of moles is given to us two more. The initial pressure of the gas is given to us one into 10 power six Newton Par meter Square. The initial temperature of the gas is given to us 27°C means 300 Kelvin. Uh It's also mentioned that the final volume is double the initial volume. So if I assume that the initiative volume is V. Then find the volume will become two times V. Now, let's try to calculate they want them in the first process uh in the first part. Okay, so for part one, in a diabetic process. So in a celebrity process, we feel undermined the Washington, we know the formula for water. That is N R. D. I minus D. F by gamma minus one. So as the gases mono atomic gas. So comma for mono atomic gases five by three that we already know. So then you can drive the work done in this process as N is equal to 10 are is 8.314 Into initial temperature is 300. And the final temperature is not given. So let's write it as TF only developed by gamma is equal to mhm five x 3 -1. Now let's try to find first uh d. A final 10 villages for that. We can ride for added body crosses for and diabetic process. The I. V. I. To depart government as one is equal to T. F. We have to depart government as one. So this will give us T. F. It was T. I times V. I by VF four people gamma minus one. So this will give us the F equals T I. S 300 calories into V IBV would be we buy to read that to people governments five by three minus one. So simplifying this, we will get the final temperature as 1 89 kelvin. So if this is the final temperature then we can write the well done in the deputy process as we have written already two in 28 point 314 in 2 300 minus 1 89 divided by five by three minutes. One minute. That is two by three to buy three. So this will give the value of Ws 2763.9 Joel. So this is the answer for a single part of part A Now in the eyes robotic process. Mm hmm. I saw body process. We know that pressure remains constant in ice robotic process. So then in that case they work done, W will be called A P times V f minus V. I do could change in volume only. Now we f we I we don't know the values so we can be placed that in terms of the temperature. So this we can write it as pee wee f minus P V I. Which will give us a as equal to N R. D F minus N R D. I. Then that we can try to the W go to N R T f minus T I. Or we can just directly find the world. From from here itself. W equal to p times V F minus V. I. Now initial volume we can find using the gas ejaculation, ideal situation PV equal to N R. T. And that employee V. I is equal to n R. The I. P. Because pressure is constant for I should buy the process. So, the initial temperature, the number of more of the gas was two more artists. 8.314. Into initial temperature The initial temperature is 300 Kelvin divided the initial pressure was one into 10 power six newtons per meter square. So this will give us the initial volume of the gas as equal to 4.98 into 10 4 -3 m q. If this is the initial volumes in the final volume is double the initial volume so that it's two times V I. So it would be two times 4.98 into 10 for -3 m tube. So then then they want them in this ice Subotic possible become P is one into 10 power one into 10 power six times final volume is uh two times initial volume. So that is two minus one times 4.98 into 10 power minus three. Right, so this will give us the well done as 4980 jewels. So this is a bargain Andy I saw barrack process now in the third case for isil thermal process we can break for I saw thermal process, the warned um is equal to N r t L N V F by V I. So in this case number of knowledge to our is 8.314 jule part mole kelvin temperature is 302 Ln because in the summer process 10% never changes. So temperatures will be initial temperature that is 300 kelvin Into Ellen VFW's two times initial volume vsV. So this would give us the well done as 3451.92 this is a bargain Andy Isil thermal process. So for part B we can draw the PV diagram for a diabetic process I submit process and is suitable process so for I had a body process you can just draw it if this is representing P and this is representing P then the for I had every process. The variation is very stiff variation like this. Uh So this state can be presented by P I V I D. I. And the state can be presented by P F VF and TF. So this is a violation of our diabetic process. Period diagram. Yeah for I saw robotic process we can again drop people diagram so this axis represents B. And this represent V. And as for adequate process the recently as for isolated process presidents constants of the variation of like this straight variation even if the changing we will not change the pressure show this is initially pressure, it's a volume and this is final volume and the pressure is always speak so this is for the this is for I used robotic process similarly people diagram for isil hammered process can also be drawn so this is representing volume, this representing pleasure and now in this case the variation will be not that steep so it will be like this. Yeah so in in I'm in Hammond process temperature remains constant so the P I V I D I two the F we have temperatures dia is still so this is for I saw thermal process. Yeah to answer the party we can just conclude that as in the case of in between a deputy process, the Walden is 2763 point angel. In nice way process. The bargain is 49 age of Joel and national process 3451 point angel. So then uh the heat transferred in the robotic process is maximum and it is minimum for a deputy process. So the answer for answer for party see we can ride the heat transferred in I saw robotic process please. Maximum and in activity process in a diabetic process it is minimum. Yeah this is the answer for part C. Now for party to compare the change in internal energy we can just say that in Iceland Hamel process in iso thermal process. The change in internal energy is zero because there is uh no change in temperature so changing internal energy Internal Energy is zero and that is the minimum. Changing internal energy in the process. And for ice robotic process for I saw barrick process as V is constant. The heat transfer is maximum so change in internal energy. Mhm attend in intimate energy is also maximum for these process. So this is the answer for the whole question

Hi, friends for one more up Mon Autumn it gets we we grow up given eight to reprocess is I saw thermal expansion We approved calculate in the party net Bergen and be part amount of the heat. Absurd amount of the heat Rejected representing Compared efficiently, bit bit efficiency off or not working for same temperature difference And I see it first part In the first part we have to calculate involved in so work done for the process to be minus be a three a learn off volume at me upon volume Attic Fight in tow 1.13 10 to the power five Bottom in meter cube 10 in tow 10 to the Power Ministry Learn off 50 upon 10 So it is to be minus 8150 June B to C is isil Barrick process So work done in way to see pressure at me in tow Change in volume pressure at B is given burn atmosphere Volume at a is 10 deter bottom at BB conscripted later. So it is Toby full 0502 Process it to a is isil coric So Bogdan is zero. So work done and see to a zero because see, to a change in volume is zero hence, network that we will get worked in the process. It Toby worked on in the process we to see and we're going in the process. You to eight minus 8150 plus 4 +050 plus zero. That is 41002 Not be part amount off. Energy added to the guests That will be in the process. Hey, Toby B A B A Learn off volume at me upon volume. Attic five in tow. 1.13 10 to the power five, 10 and 10 to the power minus three. Learn off 50 upon 10. So it is to be 8150 Do you now in super we have to fight? Yeah. Heat added to the guest in the process It to eight. It is Toby CV in two Delta T. That is three way to our temperature at a minus temperature at sea. That is three way to our be a V a upon our minus p CBC upon art. So it can be a little less 352 in tow. 8.314 Pressure at age five. Atmosphere and tow Bottom is 10. Later. Pressure at sea becomes one atmosphere. Volume is 1 10 liter. Sorry. Yeah. Eight point to even put kind 8.314 So it is to be six year old. Eight year old do energy added Do the guests by heat. You add it. You every bless you see a 81 50 6080 So it is 14 to 0. Do energy exhausted from the system are rejected it five by two TV B C minus baby substitute develop 1.13 10 to the power five, 10 and 10 to the Power Ministry minus 15 to 10 to the Power Ministry. So it is Toby minus 101 dear Oh dear. Oh, dude Or 10.1 Pillow. Dude. Efficiency off the cycle. Yeah. Okay. Network done upon heat added 4100 upon 14200 So that is 0.2 nights. That's all. Thanks for watching it


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