5

Consider a titration of 30.7 mL of 0.284 M propanoic acid (CH3CHzCOOH; Ka = 1.3 x 10-5) with 0.147 M NaOH: What is the pH after 72.6 mL of the 0.147 M NaOH has been...

Question

Consider a titration of 30.7 mL of 0.284 M propanoic acid (CH3CHzCOOH; Ka = 1.3 x 10-5) with 0.147 M NaOH: What is the pH after 72.6 mL of the 0.147 M NaOH has been added? Report your answer to two decimal places_

Consider a titration of 30.7 mL of 0.284 M propanoic acid (CH3CHzCOOH; Ka = 1.3 x 10-5) with 0.147 M NaOH: What is the pH after 72.6 mL of the 0.147 M NaOH has been added? Report your answer to two decimal places_



Answers

When $50.0 \mathrm{~mL}$ of $0.050 \mathrm{M}$ formic acid, $\mathrm{HCHO}_{2}$, is titrated with $0.050 M$ sodium hydroxide, what is the $\mathrm{pH}$ at the equivalence point? (Be sure to take into account the change in volume during the titration.) Select a good indicator for this titration from Table 16.7 .

Yeah. To solve for the volume of sodium hydroxide needed. We'll start with the volume of the acid, convert the volume two mil leaders. I'm sorry the volume in mill leaders to leaders by dividing by 1000. Then multiply by the polarity to get molds of the acid. We then recognize the reaction is 1-1. So we get mold sodium hydroxide and then we'll divide by the polarity of sodium hydroxide to get peter sodium hydroxide And then multiply by 1000 to get ml sodium hydroxide. So 59 ml of sodium hydroxide is required to carry out this type tradition. This is sodium hydroxide. Then to solve for the ph at the equivalence point the hydroxide concentration because a base has been created will be equal to the square root of the KB value which is going to be the K. A. Value for acetic acid divided into K. W. Multiplied by the concentration of the acetate that is present at the equivalence point which will be the moles of acetate which is the molds of acetic acid. We start with which is its volume multiplied by its polarity Divided by the new volume which is the 42 million L plus what we just added 59 mil leaders converted to leaders And we get 347 times 10 to the -6. This being the hydroxide concentration. We can then solve for P. H. By taking the negative log of the hydro knee um concentration which is the hydroxide concentration divided into K. W. And we get 8.54. Next for part B. We'll do the same thing. We'll start with the volume of the asset that we have convert from mill leaders to leaders than leaders. To mull with more clarity here, we recognize that we need two moles of sodium hydroxide for every mole of sulfurous acid. Well then convert the Mosul of sodium hydroxide to leaders by dividing by its polarity and then from leaders to mill leaders. So this is what's required to reach the second equivalence point half of that is what's required to reach the first equivalence point. The ph of the first equivalence point where we have the unflattering species. H S 03 minus can be calculated as ph equals one half PK one plus PK two. This is typically the best way to solve for ph when we have an ample Terek species And we get 452. Now to solve for the ph at the second equivalence point will have the soul fight and ion. And we can solve for the hydroxide concentration by taking the square root of The KB one value which will be the K two divided into KW. Multiplied by the concentration of sulfite at the equivalence point. The moles of H203 that we start with will now be equal to the moles of sulfite that we have which will be the initial volume multiplied by the initial polarity. We then divided by the new volume which will be the volume. We started with Plus 132 million liters, And we get a hydroxide concentration of 45 times 10 to the negative five ph will then be the negative log of the hydro knee um concentration, which will be the hydroxide concentration that we just calculated, divided into K. W. Giving us a ph of 969.

In the mix solution. Before any reaction occurs, some major species are present, which are it's positive, I negative and the positive which negative on water. I know that the larger quantities off both positive and which negative are present. 5.0 Millie mole off added. Which negative will react with 5.0 minimal off exported them, which can be represented in the given table after the reaction solution. Contains edge positive I negative and the positive on dhe. It's too. Oh, the pH can be determined by the concentration off each positive remaining in the solution. The concentration or fetch positive can be determined mind as follows. Using their given formula to calculate the pH, we know that P H is equal to negative. Log off each positive and B it's stones out, Toby. One point two three for Part B. We know that P H is equal to seven, which is the equal balance point off any solution. That means at this point the asset will equal. Do the cool off base solution contains 15 more off asset Now to calculate the volume off base, which contains 15 more off base, we can use the given formula substituting the values in the given formula we can deter mined that 60 and mel off based solution would be required in order to reach the guerrillas. Point, that is B. It's seven. We need to act 60 ml off base solution off any which into the given solution.

The solution for this is dead. This is it. Penetration off a weak acid, that is monopoly. Take answered with a stronger base that is, sodium hydroxide for this type of titillation, the pH at the half way point toe. The equivalent point is equal toe peak off the asset. That means the value off PK off the A normal Mona Protic acid is 5.52 Therefore, the explanation for the north this okay, is, uh, try tradition offer week answered. That is Mona Protein A sued with a strong based, which is sodium hydroxide. Okay, for these type off dietitians, the pH at the half a point. Yeah, door Mhm. The equivalence point is equal toe BK off the Massoud. That means the value PK yeah, off the unknown Monta project acid. Yeah, yes. 5.2 rich correspond toe. Well, you or okay is given as that PK equal to minus law. Okay, 5.2 equal to minus law. Okay, so the K they will be equal to 10 to the power minus 5.2 by solving this and it will be equal to 6.0 three multiplied by 10 to re power minus six. Therefore, the value off a four unknown Monath protic acid is x 40.0 three. Multiply by 10 to repair minus six. So this is the solution off. The answer that this is a titillation off a week, as in that is Mona Pro two captured with a strong they sodium hydroxide for these type of titles. And the pH at the half way point to the equivalence point is equal toe PK off the asset. That means the value peak off the unknown. Mono protic acid is 5.22 which corresponds to the value. Okay, is giving us a PK is going tomorrow. Okay. And by solving this here, we get the value. Okay, It is time to depart minus 5.21 which is equal to zero point. So D, which is equal to 6.23 10 20. Power minus 66.3 to 24 menacing. Therefore, the value off K for unknown mono protic as it is 6.3 multiplied by 10 to the power six. Thank you

Questions 15 points 16 is a rather lengthy problem. Has three parts three different type Trish in calculations. In addition to also calculating the equivalence point value which is necessary in order to make sense out of the three additional penetration volumes to give you to solve for the equivalence point volume, you will take the initial volume of the analyze that you have multiplied by its concentration to figure out the moles of the h o. C. L that you have then recognized that the reaction of HCL with an a O. H is a 1 to 1 molar reaction. You will then have at this point the molds of strong base that you need to add using the polarity of the strong base. You can calculate the moles of strong base needed, man using the polarity, you could calculate the leaders of strong base needed. Then you can multiply by 1000 in order to get the volume milliliters of strong base needed for the equivalence point. Volume is 40.0 no leaders. So after the addition of 10 millilitres, we know that we are pre equivalents because 40 is the equivalence when we are pre equivalents with a weak acid being traded with a strong base. We have a solution. So we need to know the moles of weak acid left in solution and the moles of base that we perform. Moles of weak acid left in solution is going to be equal to the molds of weak acid. We started with polarity times volume multiplied by the moles of weak acid that reacted most of weak acid that reacted will be equal to the molds of strong base form. So polarity times following you. Then the molds of week based form will be equal to the moles of strong days. Added for the molds of strong base. Added again is 10 litres multiplied by the concentration that strong based 100.4. Now, knowing the moles of weak acid and it's confident base left in solution, we can use the Henderson Hassle Baulch equation. P H is equal to peek a negative lock into K, a value that was given to us, plus the log of the molds of the base over the most of the acid, which just calculated appear well. Then set Calculate that ph of 6.98 There we go to Part B, which asked us to calculate the pH of the equivalence point pH in the equivalence point for a weak acid strong based filtration which this is always equal to p k p K. Then simply the negative log of Kay You, which was given to us which in this case, a 7.46 Then at the equivalence point, we need to recognize that all of the weak acid has reacted with strong base and has now become weak base. So all we have in solution is the base. If all we have in solution at the equivalence point is the face, then all we have to do is carry out a base pH calculation. A week based pH calculation requires us to no concentration of the weak base. The concentration of the base is going to be equal to the molds of strong base added, or it's also equal to the molds of weak acid. We started with most weak acid we started with is going to be the volume 100 mil leaders multiplied by the concentration 1000.16 You then have to divide that by the new total volume. We started out with 100 mil. Leaders calculated earlier that the equivalence point volume was 40 No leaders. That then gives us a concentration of weak base at 1.14 times 10 to the negative too. The pH From that the hydroxide concentration for a solution containing a weak base is always equal to okay, be value for the weak base which we can get from the K. A value for the weak acid. K B is the kw value which is 1.0 times 10 the negative 14 divided by K. So this right here is our K B value multiplied by the concentration of the weak base and then we square. So that gives us five 5.71 times 10 to make it to five Moeller concentration for hydroxide get pH from hydroxide when you take the negative log of the hydro Liam concentration which we get from the hydroxide concentration by dividing it into kw. So this right here represents the hydro nian concentration that we will take the negative log in order to get our ph of 9.76


Similar Solved Questions

5 answers
9. Find the general solution to the system2 (t)~i r(t) ,and sketch a phase portrait_ Find the solution satisfying 1(0) = 2 What are the nearest and farthest points to the origin that this solution passes through?
9. Find the general solution to the system 2 (t) ~i r(t) , and sketch a phase portrait_ Find the solution satisfying 1(0) = 2 What are the nearest and farthest points to the origin that this solution passes through?...
5 answers
Fin J corres Pondin] d;PexenHia) elualionJ- C,x + C
Fin J corres Pondin] d;PexenHia) elualion J- C,x + C...
5 answers
And center and radius of the circle with the given equation, Find the graph the equation: (x - 3)2 + W -2)" =function. Express the answer in interval notation = and inequality notation. Find the domain of the indicated9 (t) = Vat + 1
and center and radius of the circle with the given equation, Find the graph the equation: (x - 3)2 + W -2)" = function. Express the answer in interval notation = and inequality notation. Find the domain of the indicated 9 (t) = Vat + 1...
5 answers
Water is discharged from a pipeline at a velocity ? (in ft/sec) given by1936p5whereP is the pressure (in psi). If the water pressure is changing at a rate of 0.373 sec find the acceleration (dv/dt) of the water when p = 60.0 psi .
Water is discharged from a pipeline at a velocity ? (in ft/sec) given by 1936p5 whereP is the pressure (in psi). If the water pressure is changing at a rate of 0.373 sec find the acceleration (dv/dt) of the water when p = 60.0 psi ....
5 answers
42v 3 w _ 3v +;w+{ How many solutions does the following system have?: Ev+ w + 1 = Zv + 3 infinitely many one unique tWO none
42v 3 w _ 3v +;w+{ How many solutions does the following system have?: Ev+ w + 1 = Zv + 3 infinitely many one unique tWO none...
5 answers
4) (12 pts) Let A =and assume that det(A) = 3. Find det(B) whereh'2d 2e 2f B = 4a 4b 4c h
4) (12 pts) Let A = and assume that det(A) = 3. Find det(B) where h '2d 2e 2f B = 4a 4b 4c h...
5 answers
Assume that functions and are differentiable with f(3) = 2,f'(3) = 4,9(3) = 5 and 9'(3) = 3. Find an equation of the line tangent to the graph of F(x) = f(xJg(x) at x= 3The equation of the tangent line is (Type an equation using and y as the variables_
Assume that functions and are differentiable with f(3) = 2,f'(3) = 4,9(3) = 5 and 9'(3) = 3. Find an equation of the line tangent to the graph of F(x) = f(xJg(x) at x= 3 The equation of the tangent line is (Type an equation using and y as the variables_...
5 answers
Give an acceptable name for each of the following.
Give an acceptable name for each of the following....
5 answers
Whenever Suzan sees bag of marbles _ she grabs handful at random_ She has seen bag containing three red marbles_ two green ones, three white ones; and two purple ones She grabs eight of them Find the probability of the following event, expressing it as fraction in lowest terms_She does not have all the green ones.Need Help?Read LtWhlchlt
Whenever Suzan sees bag of marbles _ she grabs handful at random_ She has seen bag containing three red marbles_ two green ones, three white ones; and two purple ones She grabs eight of them Find the probability of the following event, expressing it as fraction in lowest terms_ She does not have all...
5 answers
The amino acid serine is biosynthesized by a route that involves reaction of 3-phosphohydroxypyruvate with glutamate to give 3-phosphoserine. Propose a mechanism. (EQUATION CAN'T COPY)
The amino acid serine is biosynthesized by a route that involves reaction of 3-phosphohydroxypyruvate with glutamate to give 3-phosphoserine. Propose a mechanism. (EQUATION CAN'T COPY)...
5 answers
Determine whether each statement makes sense or does not make sense, and explain your reasoning.I used the Fundamental Counting Principle to determine the number of five-digit ZIP codes that are available to the U.S. Postal Service.
Determine whether each statement makes sense or does not make sense, and explain your reasoning. I used the Fundamental Counting Principle to determine the number of five-digit ZIP codes that are available to the U.S. Postal Service....
5 answers
QuestionRelativefixed ongin 0the pcint Desition Veclor 2 - Mj point _ hus positic vcctor Ji Pi whctc the point hae pocition rector Q1 - 7j wherecueatcon DGiven that Iu] 5 6 find the possible values of pGiven thntangle hetween AC andl tba unit vector f E Ndun(b) lind th< exic vulue of q
Question Relative fixed ongin 0 the pcint Desition Veclor 2 - Mj point _ hus positic vcctor Ji Pi whctc the point hae pocition rector Q1 - 7j where cueat con D Given that Iu] 5 6 find the possible values of p Given thnt angle hetween AC andl tba unit vector f E Ndun (b) lind th< exic vulue of q...
1 answers
Each of Exercises $1-4$ gives a value of sinh $x$ or cosh $x .$ Use the definitions and the identity $\cosh ^{2} x-\sinh ^{2} x=1$ to find the values of the remaining five hyperbolic functions. $$\sinh x=\frac{4}{3}$$
Each of Exercises $1-4$ gives a value of sinh $x$ or cosh $x .$ Use the definitions and the identity $\cosh ^{2} x-\sinh ^{2} x=1$ to find the values of the remaining five hyperbolic functions. $$\sinh x=\frac{4}{3}$$...
5 answers
If a player kicks a ball in the middle of a field, and ball's weight is 0.5kg, reaches a speed of 40m / s, and the ball is in the air at 0.05s, state the weight of the kicker
If a player kicks a ball in the middle of a field, and ball's weight is 0.5kg, reaches a speed of 40m / s, and the ball is in the air at 0.05s, state the weight of the kicker...
5 answers
A normal distribution of Boer goat weights at age 6 months defined with p = 30 kg and 0 = 3 kg: Determine theoretical proportions of goats:more than 35 kg; less than 35 kg; less than 33 and more than 25 kg;d) What is the theoretical lowest value for an animal to be included among the heaviest 20%; e) What is the theoretical mean of animals with weights greater than 35 kg
A normal distribution of Boer goat weights at age 6 months defined with p = 30 kg and 0 = 3 kg: Determine theoretical proportions of goats: more than 35 kg; less than 35 kg; less than 33 and more than 25 kg; d) What is the theoretical lowest value for an animal to be included among the heaviest 20%;...
5 answers
The data given in TableBrand of light bulbs manulactured in Johannesburg-Table 6: Light bulbs Brand _26 3u 8 2420 12The manager at the company that manufactures these bulhs is claiming that the sequence of these numbers represents randOm sample.Test the hypothesis using Runs test a[ &=0.0
The data given in Table Brand of light bulbs manulactured in Johannesburg- Table 6: Light bulbs Brand _ 26 3u 8 24 20 12 The manager at the company that manufactures these bulhs is claiming that the sequence of these numbers represents randOm sample. Test the hypothesis using Runs test a[ &=0.0...

-- 0.020477--