Question
H nlormabon Curdon rDon dioxi de certain Compounc J 530 1 Hot I 1 H 11 10772. sd 6
H nlormabon Curdon rDon dioxi de certain Compounc J 530 1 Hot I 1 H 1 1 1 0772. sd 6


Answers
$\frac{\text { 1. } \mathrm{H}_{2} \mathrm{SO}_{4} / \text { heat }}{2 . \mathrm{Br}_{2} / \mathrm{CHCl}_{3}}$ Product
The correct order, the correct order of buy bonds in increasing order. In increasing order. In increasing order is given as follow. Just look at it carefully. But ET off S two S 03, so I'm just writing it in increasing order, so more is off as to as 205 and highest each of as to as to or six two according to the option option B is correct. Option B is correct here.
In this problem, this compound, which I am writing here, just look at it carefully here. It will be A and here it'd pr and this compound here it is. Beyond here it will be a These two compounds in Potenza access any manage to then as to oh, work up https your four As two years of four and me oh, edge to produce the final, productive this compound reality. They will won't know so according to the option in this problem absence. See absentee are correct answer.
In this problem, this component which I am writing he had just located carefully this compound in presence of We are two HB K edge eight people at he will produce the final product, ID. This compound Heritage, double bone according to the option. In this problem, Option B. Each correct answer. Ob Cindy is the correct answer for this problem.
Dark Hussein is white phosphorus and reaction with see A. We're told to ems we have wide fast for us. Yes. Yeah. Which will too So this upon reaction will give This will give p three less. Yeah, that's too you're too All too. So this is the product of this reaction. So let us set the options so we see option B and option here, correct and speaking rate of sin the and option the uh that answer.