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QUESTIONSclect the product of the follovng reactionLWNHa ethor2 H,o"OHHOHOOHHO-...

Question

QUESTIONSclect the product of the follovng reactionLWNHa ethor2 H,o"OHHOHOOHHO-

QUESTION Sclect the product of the follovng reaction LWNHa ethor 2 H,o" OH HO HO OH HO-



Answers

What is the product of the reaction below?

In this problem, I am doing the Diagram 1st. Just look at it carefully. Here it is, Oh, edge and this is the edge. So this stage three degree alcohol, which is which age not oxy died, but first degree alcohol washed degree alcohol gives bottom obsolete acid on observation. So according to the given option, according to the given up some option B, it correct? Be it correct answer.

Action is So we have this compound. 1st 1 is final and the second one is by a journey in salt. So Andy. Is that living group? Okay, so much is that Palestinian group. So now is the last time singing group that is a drink activity group. So it will be all 200 para, para will be major. So this molecule attack on that better position of the family. So this time when we get back on this card and coupling will takes place. And so.

In this problem, the reaction will be happened. Something like this. Just look at it carefully. Here it is suitable 10 inherited or edge. This compound in pageants alpha associate to as well add CH three CH two edge add plus will give the final product ID. This compound I am doing the structure of the final product so just look at it carefully here it is. See there will 10 mm CH two see it to the according to the option. In this problem of some CH correct answer for this problem.

Okay. This problem is asking us to predict the product of this reaction. So first step, we have a key tone reacting with an alcohol. So there's a couple of different important things here. First off the key tone, and we know it's a key tone because we have a Carbondale. And on either side of the Carbonell, we have two carbons. So ketones are considered Electra Philip towards nuclear Filic edition reactions. So here's my nuclear fall. We only have one equivalent of the alcohol, right? So we're not We know we're not gonna have to have two equivalents come in. For example, we're only gonna get this one equivalent. So the electrons on the oxygen are going to come in and attack this electro Philip Carbon. Okay, we know that that carbon is considered Electra Philip because it is part of the Carbondale. We can move these electrons from this pie bond up to this oxygen due to oxygen's, um, natural. More electro negativity than carbon. Okay, so after this air pushing mechanism, I'm going to get this ch three. I'm gonna get my carbon. This carbon right here is correspondent to this formerly electric Philip Carbon and connected to that carbon. We have the connection to an oxygen with a negative charge. So this oxygen corresponds to this one? Because I simply moved those electrons onto the oxygen mean that I had to incorporate that negative charge and then over here, also connected to this carbon. I have the connection to an oxygen. So this oxygen right here corresponds to this one. That was the incoming nuclear file and connected to the auction. We have a connection to a hydrogen, which is, of course, this one And then finally, my ethel group. Okay, but because this auction has three bonds instead of just two, that means it's gonna have that positive charge. Okay. And last, but not least, attached to this carbon as well. We have the connection to my C two h five. So we have to write that right here. C two h five. Okay, So as we can see, we only added that alcohol one time, right? If we're toe, add it twice, then we would get perhaps a key tall. But instead, we're going to form this Hemi kettle product because I only have the one equivalent incorporated. Okay, But we can't just end right here. We have to get rid of this negative charge and this positive charge, if possible. And we can accomplish that by simply transferring a proton from this oxygen onto this oxygen. Okay, so I'm just gonna represent that with Proton transfer. Some teachers will teach that this occurs in trauma molecularly, but others will teach that occurs, in turn, molecularly. But nevertheless, we're simply gonna get that proton transfer. That means that the oxygen is gonna have that new proton. I mean, that it will have a negative charge any longer. And then this oxygen will have its Ethel group minus one hydrogen. So no positive charge. And then finally, my C two h five. Okay, so this will be the Hemi Keitel product, and this will be see for the answer.


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