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A gas occupying a volume of $725 mathrm{~mL}$ at a pressure of $0.970 mathrm{~atm}$ is allowed to expand at constant temperature until its pressure reaches $0.541 m...

Question

A gas occupying a volume of $725 mathrm{~mL}$ at a pressure of $0.970 mathrm{~atm}$ is allowed to expand at constant temperature until its pressure reaches $0.541 mathrm{~atm} .$ What is its final volume?

A gas occupying a volume of $725 mathrm{~mL}$ at a pressure of $0.970 mathrm{~atm}$ is allowed to expand at constant temperature until its pressure reaches $0.541 mathrm{~atm} .$ What is its final volume?



Answers

A gas has a Henry"s law constant of 0.112 M>atm. What total
volume of solution is needed to completely dissolve 1.65 L of the
gas at a pressure of 725 torr and a temperature of 25 C?

So for this question, we have a sample off 1.65 leader of gases dissolved in water and the Henry's Law constant. It's equal to two point 112 Moeller per atmosphere. So this is the volume of the gas and we have the pressure equal to 725 tour. So we want to convert pressure into atmosphere. We have 725 tour divided by 760 tour for atmosphere, and this is equal to 0.95 four atmosphere and the temperature 25 Celsius degree. We want to convert that into Calvin 25 plus 2 73 Cullen. You could try to 98 colors, so the formula for Harris law is sg you could you K H P G's? And in this formula, the Astra is the sole ability of the guests. K age is Henry's law constant and PG is a partial pressure of the guests. All right, so to solve for the sill ability of the gas will have SG equal to K H P G, and that is equal to zero point Won't want to Moller per atmosphere. Times zero point 95 or atmosphere and we get it is equal to 0.107 Moeller. So that Issa so ability of the gas and the solution, Then we can go with the most of the gas presenting 1.65 liter of gas. So the moles off the cast is there going to pressure up the volume but the pressure time So volume divided by our times. T This is from the question PB equal to in our tea. So this is equal to pressure. Little 0.954 Atmosphere volume is 1.65. Leader divided by our is equal to 0.8 to 1 leader for atmosphere derided by mold prick Elvis times temperatures to unite eight cult So this is equal to 0.64 moles. So this is the molds off the guests. All right, now we have the mole's up, the guests and the soul ability of the guests. We can calculate the volume of the water from the molds and mill arah T larrin t equal to more devoted by volume. So you 0.1 of seven Mueller equal to 0.64 more divided by volume. So V is equal to 0.64 devoted by your 0.107 malaria Tous small per leader. So we get a volume of five 0.598 Leader. So the volume required Is there a point by like a leader?

For a constant temperature. Constant breacher. Um, initial pressure times initial William is equal to the file. Will you times the final pressure. He'll find the pressure saurian times final. William, Our initial pressure we have is there a point? So the initial William we have got rather 0.5 and 0.5 a meter cube times the pressure you in four. Hmm. And then finally, pressure. We have also won and we were asked to find the William we f So we'll straighten our soul for the f ree Jesu to meet your cube here.

Highways did some problem. 5.24. The problem stays. A weather balloon is, well wait 1,000,000 to evolving off 1.61 later and 74 door. What is the volume of the balloon after it has been released and expression has dropped to 0.8 poor for Adam and the temperature is constant. In this case, let's try down whatever it is given. Given in the shade Did Depression Initiative the balding Waas We want 1.61 liter and initial impression wants 7 34 don't. And after the Belen has released the volume, the two we need to find it and the pressure we do we came 0.84 ful Jim, for ideal guess. We know that for one level of gas and fixed intelligence, then love becomes easy. You're going to almost and or we can right beyond villain going to be to veto four. We do it too. You owned by B two. Wanted Tredway, everyone. No, we know P one. It'll do. 7 34 Don't you can do. Is there one day 44 a team and we want to spend 1.61 leader needs gun. Weren't the unit or a team? 7 30 people directed by 7 60 a team for for a team multiplied by 1.61 leader. The reason behind these thieves. 7 60 Don't. You're going to want need him. Therefore 7 34 door should be ready to this one. And dr Compilation, Real gay. We do go to one point eight four leader. Therefore, the final volume becomes 1.84 liters.

We're told in the beginning of this problem that we are at a constant temperature. So then the question becomes, Which law do I use? Well, I know temperature is not changing, so that means pressure and volume must be changing. And that corresponds to Boyle's law. Boyle's law looks like this. It's p one times V one equals P two Titans V two, where p is pressure and V is volume. But the goal for this problem is we want to know what our second volume is. So we have to rearrange the equation to get you to buy itself. We'll get that V two is equal to P one tons of e one divided by P two. Now we simply plug in the values in our problem. We know that P one is what a. T m. You know that our first volume is 1.55 leaders and we know that our second pressure is 58 PM All we do is a simple division problem and you're fine that our volume our second volume 0.31 leaders


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